Only expert should solve it 2:43 PM P & G.O+ " 40 221 28IMG-20240829-WA0029.jpg(388/2181)Questiona 5kva,200v/400v,50hz single phasetransformer gave the following test1.open circuit test Voc = 200v loc = 0.7A andPoc =60watt2.short circuit test V=22, current=16a,power=220w, calculate the equivalent ofthe transformer when refered to high voltagesideShare| |||EditоSet as||Deleten

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Delmar's Standard Textbook Of Electricity

7th Edition

ISBN:9781337900348

Author:Stephen L. Herman

Publisher:Stephen L. Herman

Chapter30: Dc Motors

Section: Chapter Questions

Problem 6RQ: What is CEMF?

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Repeat example 35 for FWD and firing angle Fa) 60°. 215 l65 D1985 Example 35: A full wave rectifier used 220V, with firing angle 10° ,total resistance load 5 KQ, inductance 2.34 H,and frequency 60HZ, Draw and calculate: (a) VD.c and Ipc (b) VD.C(Max) (c) Vn (d) Vorms-
A three phase full wave rectifier is shown below along with peak phase voltage Vm-169.7V. The load is purely resistive. The rectifier delivers Ipc = 100 A and the source frequency is 60 Hz. The DC output voltage is %3D VDc=280.7V and the output RMS voltage is equal to VRMS=280.93V. The efficiency, FF and RF are respectively equal to: Secondary D D D, R AD. Z D. D, Select one: O a. 99.83%, 100.08%, 4% O b. 99.83%, 55.08%, 4% O C. 99.83%, 100.08%, 16% O d. 87.83%, 100.08%, 4%
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A resistor Ra is in series with a voltage source Va. Draw the circuit. Label the voltage across the combination as v and the current as i. Draw and label the volt–ampere characteristic (i versus v).
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Find VDc if VAN = VBN = VCN= 120 volts... Half-wave Three-phase Rectifier Conduction Waveform Periodic Time (T) A B 180 360 90° 450 540 time 270 VAN VeN VAN VEN Voc Vrc 30 120 150 270 390 510° time Output Voltage Waveform B
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Example 35: A full wave rectifier used 220v , with firing angle 10° ,total resistance load5 K2, inductance 2.34 H,and frequency 60HZ , Draw and calculate: (a) VD.c and ID.c (b) VD.C(Max) (c) Vn (d) Vor.m.s.
In the circuit in the figure, an AC voltmeter will be made with full wave rectifier circuit structure. R = 50ohm and diodesResistance values in the direction of transmission are Rd = 100ohm. Inside of the DC ammeter to be used as indicatorthe resistance is very, very small. The AC mark to be measured is Vs = 100 Sinwt Volts.a- Draw the shape of the current passing through the DC Ammeter and calculate its maximum value.b- Find the average value of the current passing through the DC Ammeter.c- Analyze the voltage seen at the ends of diode D1 for both alternans.d- Find the Rms value of the voltage seen at the ends of the diode D1.
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(a) Figure Q2 (a) shows the image from the digital osciloscope. It shows two sine waveforms, voltage (Ch1) and current (Ch2). The value of vertical (volt/div) for Ch1, (amp/div) for Ch2, and horizontal scales (time/div) are shown in the image. Analyze the figure and determine: iv) Peak to peak value and the frequency for each waveform (voltage, Ch1 and current, Ch2) v) Phase different between two waveforms. vi) If the vertical scale (volt/div) of Chl is change to 100 V. Determine the total of division of Chl that will be displayed by the oscilloscope. Ch1 Ch2 Ch1 50V Ch2 5A M5.00ms Figure Q2 (a)

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