Only expert should solve it 2:43 PM P & G.O+ " 40 221 28IMG-20240829-WA0029.jpg(388/2181)Questiona 5kva,200v/400v,50hz single phasetransformer gave the following test1.open circuit test Voc = 200v loc = 0.7A andPoc =60watt2.short circuit test V=22, current=16a,power=220w, calculate the equivalent ofthe transformer when refered to high voltagesideShare| |||EditоSet as||Deleten

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Delmar's Standard Textbook Of Electricity

7th Edition

ISBN:9781337900348

Author:Stephen L. Herman

Publisher:Stephen L. Herman

Chapter30: Dc Motors

Section: Chapter Questions

Problem 6RQ: What is CEMF?

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A three phase full wave rectifier is shown below along with peak phase voltage Vm-169.7V. The load is purely resistive. The rectifier delivers Ipc = 100 A and the source frequency is 60 Hz. The DC output voltage is %3D VDc=280.7V and the output RMS voltage is equal to VRMS=280.93V. The efficiency, FF and RF are respectively equal to: Secondary D D D, R AD. Z D. D, Select one: O a. 99.83%, 100.08%, 4% O b. 99.83%, 55.08%, 4% O C. 99.83%, 100.08%, 16% O d. 87.83%, 100.08%, 4%
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Find VDc if VAN = VBN = VCN= 120 volts... Half-wave Three-phase Rectifier Conduction Waveform Periodic Time (T) A B 180 360 90° 450 540 time 270 VAN VeN VAN VEN Voc Vrc 30 120 150 270 390 510° time Output Voltage Waveform B
(a) Figure Q2 (a) shows the image from the digital osciloscope. It shows two sine waveforms, voltage (Ch1) and current (Ch2). The value of vertical (volt/div) for Ch1, (amp/div) for Ch2, and horizontal scales (time/div) are shown in the image. Analyze the figure and determine: iv) Peak to peak value and the frequency for each waveform (voltage, Ch1 and current, Ch2) v) Phase different between two waveforms. vi) If the vertical scale (volt/div) of Chl is change to 100 V. Determine the total of division of Chl that will be displayed by the oscilloscope. Ch1 Ch2 Ch1 50V Ch2 5A M5.00ms Figure Q2 (a)
A 60 Hz sinusoidal voltage with an RMS value of 120 V is applied to a single-phase half-wave SCR rectifier. The firing of SCR is delayed by 60 degrees. The DC output voltage of the rectifier would be: O A. 60 V O B. 90 O C. 81 V O D. 40 V O E. None of the other choices are correct
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A 60 Hz sinusoidal voltage is applied to an SCR full-wave rectifier. If the DC output voltage is 162 V and the firing angle of the SCR is 60 degrees, the peak voltage of the input sinusoidal would be: O A. 197 V O B. 228 V O C. Can't tell; need more information. O D. 340 V O E. None of the other choices are correct
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