4.3 Repeat Example 4.1, but using the function f(t) = A for 0 < t
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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![4.3 Repeat Example 4.1, but using the function f(t) = A for 0 < t <T and
f(t) = 0 for all other values of t. Explain the reason for any differences between
your results and the results in the example.
EXAMPLE 4.1: Obtaining the Fourier transform of a simple continuous function.
The Fourier transform of the function in Fig. 4.4(a) follows from Eq. (4-20):
8
F(μ) = √ ƒ(t)e-²µ³ d
=
e-j2μt] W/2
-W/2
A
2πμ
A
W
AW sin(μW)
(лμW)
-e
W/2
=
Ae-j2πμt dt
-W/2
-A
2πμ
=](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc80a717d-7684-40f5-9bb7-29c4b981aba0%2F1eaf373d-505c-4bef-84dc-a4111f4487e6%2Fd3v3uq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:4.3 Repeat Example 4.1, but using the function f(t) = A for 0 < t <T and
f(t) = 0 for all other values of t. Explain the reason for any differences between
your results and the results in the example.
EXAMPLE 4.1: Obtaining the Fourier transform of a simple continuous function.
The Fourier transform of the function in Fig. 4.4(a) follows from Eq. (4-20):
8
F(μ) = √ ƒ(t)e-²µ³ d
=
e-j2μt] W/2
-W/2
A
2πμ
A
W
AW sin(μW)
(лμW)
-e
W/2
=
Ae-j2πμt dt
-W/2
-A
2πμ
=
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