. Opposites attract. The following graph shows how the AGAG for the hydrolysis of ATP varies as a function of the Mg2+Mg*+ concentration (pMg=-log[ Mg2+ ]).(pMg = –log [Mg²+]). 36 8.6 8.4 35 8.2 34 8.0 을 33 7.8 7.6 7.4 31 7.2 30 1 2 3 4 5 6 7 pMg Berg et al., Biochemistry, 9e, © 2019 W. H. Freeman and Company a. How does decreasing [ Mg2+ ]lMg*"] affect the AGAG of hydrolysis for ATP? b. Explain this effect. -AG (kJ mol-1) -AG (kcal mol-)

. Opposites attract. The following graph shows how the AGAG for the hydrolysis of ATP varies as a function of the Mg2+Mg+ concentration (pMg=-log[ Mg2+ ]).(pMg = –log [Mg²+]). 36 8.6 8.4 35 8.2 34 8.0 을 33 7.8 7.6 7.4 31 7.2 30 1 2 3 4 5 6 7 pMg Berg et al., Biochemistry, 9e, © 2019 W. H. Freeman and Company a. How does decreasing [ Mg2+ ]lMg"] affect the AGAG of hydrolysis for ATP? b. Explain this effect. -AG (kJ mol-1) -AG (kcal mol-)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Many metabolites are maintained at steady-state concentrations that are far from equilibrium. A comparison of Keg and Q, the mass-action ratio, can determine whether a metabolic reaction is far from equilibrium. The equation for this equilibrium is, fructose 6-phosphate + ATP = fructose 1,6-bisphosphate + ADP Calculate Keg for this reaction at T = 25.0 °C. AG' = -14.2 kJ/mol Keg = Calculate the mass-action ratio, Q, from the approximate physiological concentrations for rat heart tissue shown in the table. Metabolite Concentration (µM) fructose 6-phosphate 82.0 Q = fructose 1,6-bisphosphate 31.0 АТР 12,900 ADP 1,390
2) a)Determine AGrxn° values for the following COmbustion reactions at 25°C b) Decide whether this reaction is spontanious at 25°C or not CH(g) + 0:(g) → CO:(g) + H;0 (1) AH (kJ/mol) -74.87 S (kJ/mol) CH4 0.186 0.205 CO: H,O -393.51 0.214 -285.83 0.070
To answer this question, please reference the Problem Solving Video: Free Energy, ATP, and Creatine in Resting Muscles. The standard free energy (AG) of the creatine kinase reaction is -12.6 kJ-mol-¹. The AG value of an in vitro creatine kinase reaction is -0.1 kJ-mol-¹. At the start of the reaction, the concentration of ATP is 6 mM, the concentration of creatine is 12 mM, and the concentration of creatine phosphate is 25 mM. Using the values given, calculate the starting concentration of ADP in micromolar. [ADP] = μM
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AH = - 1.2 kcal/mol; Kp = 16 nM OH 1 HO AH = - 6.0 kcal/mol; N. Kp = = 76 nM OH 2 HOl. AH = - 5.5 kcal/mol; Kp = 0.5 nM OH (iii) By considering the enthalpies given, what do you think this suggests about the target (e.g. the binding pocket of an enzyme) that the molecule binds to?
Assume that in a certain cell, the ratio of products/reactants or Keq = 614.9 (Keq is dimensionless) for the reaction Glucose + ATP <> Glucose-6-P + ADP, at a particular instant, the concentrations of each compound were Glucose =4.3M, ATP =10.5M, ADP =17.3M and G-6-P =23.5M. Calculate the difference (dimensionless) between Keq and the ratio of products/ractants at this instance, in this cell, to five significant figures.
CH₂OH T C=O CH₂OPO²- DHAP Triose phosphate isomerase H HCOH CH₂OPO3²- G-3-P Under standard conditions, AG° = +7.53 kJ/mol. What is AG when the initial concentration of DHAP is 2 x 10-4 M and the initial concentration of G-3-P is 3 x 10-6 M? R = 8.314 x 10-3 kJ*mol-¹*K-1 T = 310 K
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2. The electron transfer potential of NADH and FADH2, relative to O2, drives oxidative phosphorylation and ATP synthesis. Oxidation of NADH occurs by the following reaction (1) : (1) 0.5 02 + NADH + H* H20 + NAD* The reaction above can be expressed in terms of the following half reactions: (2) 0.5 O2 + 2 H* + 2 e > H20 (3) NAD+ + 2 H* + 2 e → NADH E. E, = -0.32 V = +0.82 V Calculate AE'" and AGO for the oxidation of NADH (Reaction 1). а. b. What is AG'º for the synthesis of ATP from ADP? c. Using your results from Parts (a) and (b), explain how the electron transfer potential of NADH drives ATP synthesis.
17.In the following unbalanced equation, which of the products would be considered the driving force? K33PO44 + MgCl22 --> KCl + Mg33(PO44)22 A.Mg33(PO44)22 B.KCl C.No reaction because there is no driving force