You discover a cell that uses Cu² as the final electron acceptor in mitochondrial electron transpo (MET) instead of O. Cu* + 2e e → Cu° E°=+0.337 V A. How much free energy can be gained by oxidation of NADH in this novel MET system? Show calculations.

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### Mitochondrial Electron Transport Adaptation

2. **Unique Electron Acceptor in Mitochondrial Electron Transport**:

   - **Observation**: A cell is discovered to use Cu²⁺ as the final electron acceptor in mitochondrial electron transport (MET) instead of O₂.
   - **Reaction**: 
     \[ \text{Cu}^{2+} + 2e^- \leftrightarrow \text{Cu}^0 \]
     \[ \text{E}^\circ = +0.337 \, \text{V} \]

   - **Problem Statement**:
     **A. Calculation of Free Energy**:
     Determine how much free energy can be gained by the oxidation of NADH in this novel MET system. Show calculations.

### Detailed Explanation

The reduction potential (Eº) for the half-reaction provided is +0.337 V for Cu²⁺/Cu⁰. To determine the free energy change (ΔG) from the oxidation of NADH, we need to use the Nernst equation and the known standard reduction potential for NADH/NAD⁺.

Key Steps for Calculation:

1. **Identify the standard reduction potentials**:
   - For Cu²⁺ + 2e⁻ → Cu⁰:
     Eº = +0.337 V
   - For NAD⁺ + H⁺ + 2e⁻ → NADH:
     Eº = -0.320 V

2. **Calculate the overall cell potential (Eºcell)**:
   \[
   \text{Eº} = \text{Eº (electron acceptor) - Eº (electron donor)}
   \]
   \[
   \text{Eºcell} = 0.337 \, \text{V} - (-0.320 \, \text{V}) = 0.657 \, \text{V}
   \]

3. **Use the Gibbs free energy equation**:
   \[
   \Delta G = -nFEºcell
   \]
   where:
   - \( n \) = number of moles of electrons exchanged (n = 2 for NADH oxidation reaction)
   - \( F \) = Faraday constant (approximately 96485 C/mol)
   - \( Eºcell \) = total cell potential (0.657 V)

4. **
Transcribed Image Text:### Mitochondrial Electron Transport Adaptation 2. **Unique Electron Acceptor in Mitochondrial Electron Transport**: - **Observation**: A cell is discovered to use Cu²⁺ as the final electron acceptor in mitochondrial electron transport (MET) instead of O₂. - **Reaction**: \[ \text{Cu}^{2+} + 2e^- \leftrightarrow \text{Cu}^0 \] \[ \text{E}^\circ = +0.337 \, \text{V} \] - **Problem Statement**: **A. Calculation of Free Energy**: Determine how much free energy can be gained by the oxidation of NADH in this novel MET system. Show calculations. ### Detailed Explanation The reduction potential (Eº) for the half-reaction provided is +0.337 V for Cu²⁺/Cu⁰. To determine the free energy change (ΔG) from the oxidation of NADH, we need to use the Nernst equation and the known standard reduction potential for NADH/NAD⁺. Key Steps for Calculation: 1. **Identify the standard reduction potentials**: - For Cu²⁺ + 2e⁻ → Cu⁰: Eº = +0.337 V - For NAD⁺ + H⁺ + 2e⁻ → NADH: Eº = -0.320 V 2. **Calculate the overall cell potential (Eºcell)**: \[ \text{Eº} = \text{Eº (electron acceptor) - Eº (electron donor)} \] \[ \text{Eºcell} = 0.337 \, \text{V} - (-0.320 \, \text{V}) = 0.657 \, \text{V} \] 3. **Use the Gibbs free energy equation**: \[ \Delta G = -nFEºcell \] where: - \( n \) = number of moles of electrons exchanged (n = 2 for NADH oxidation reaction) - \( F \) = Faraday constant (approximately 96485 C/mol) - \( Eºcell \) = total cell potential (0.657 V) 4. **
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