3M - MS-DRG Assignment
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Statistics
Date
Feb 20, 2024
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Assessment: 3M - MS-DRG Assignment - Results
Attempt 6 of Unlimited
Written Feb 17, 2024 4:41 PM - Feb 17, 2024 4:42 PM
Attempt Score
7 / 7 - 100 %
Overall Grade (Highest Attempt)
7 / 7 - 100 %
Part 1
Question 1
1 / 1 point
What is the correct coding assignment for the Cardiac Case?
Question 2
1 / 1 point
What is the correct coding and sequencing assignment for the Renal Case?
I110, Z6842, I5032, Z8546, D72829, I5084, E6601
J90, Z6842, I5032, C61, D72829, I5084, E6601
I5032, J90, I110, Z6842, Z8546, I5084, E6601
I110, Z6842, E6601, I5084, Z8546, D72829
Question 3
1 / 1 point
What is the correct PCS coding and sequencing assignment for the Neoplasm
Case?
Part 2
Question 4
1 / 1 point
Which of the following is a CC for the DRG in the Neoplasm case?
Question 5
1 / 1 point
What is the correct DRG and weight for the Neoplasm case?
I951, I5040, I129, N1830, E860, N281, 0TD14ZZ
I951, I13.0, I5040, N1830, E860, N281, 0TD14ZZ, 0TJB8ZZ, 5A1D70Z
R55, I951, I5040, N1830, E860, N281, 0TD14ZZ, 0TJB8ZZ
I5040, I129, N1830, E860, N281, 0TD14ZZ, 0TJB8ZZ, 5A1D70Z
150.40, 195.1, I13.0, N19.30, E860, N281, OTJB8ZZ, OTD14ZZ,
5A1D70Z
00BX0ZX, 00UT0JZ, B518ZZA, B030ZZZ, B03BYZZ
00BX0ZX, 00UT0JZ, B518ZZA, B030ZZZ
00BX0ZX, 00UT0JZ, B518ZZA, B03BYZZ
00UT0JZ, 00BX0ZX, B518ZZA, B030ZZZ, B03BYZZ
Y842
Z923
R3981
None of the above
Question 6
1 / 1 point
Which of the following is the appropriate weight if R3981 is moved to the
Principal Diagnosis location for the Neoplasm case?
Question 7
1 / 1 point
What is the correct DRG assignment for the Neoplasm Case?
Done
37.0 and 030
030 and 2.2721
030 and 9784.34
3.2 ALOS and wt 2.2721
36.0
2.4381
2.1333
030
350
001
2.1333
030
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Chapter 6, Section 2-CI, Exercise 109
What Influences the Sample Size Needed?
In this exercise, we examine the effect of the margin of error on determining the sample size needed.
Find the sample size needed to give, with 99% confidence, a margin of error within +6. Within +4. Within ±1. Assume that we use o = 25 as our estimate of the standard deviation In each case.
Round your answers up to the nearest integer.
ME = 6
n =
ME = 4:
n =
ME = 1: n=
Click If you would like to Show Work for this question: Open Show Work
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70
nent 1 Privacy Policy .2000-2020 John Wiley 8 Sons, Inc. All Rights Reserved. A…
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