answer_3

Q.3 In a bushmandrel system, a bush was turned on a mandrel. The mandrel diameter in millimeter is 400.00 -0.05 and bore diameter of bush is 40+0.06 The -0.010 maximum eccentricity of the bush in mm will be A 0.025 0.045 C 0.055 D 0.065

b) the following data is given for the piston of a four-stroke diesel engine: Cylinder bore 300 min Force on piston due to maximum gas pressure = 424 KN Bearing pressure at small end of connecting rod = 15 MPa Length of piston pin in bush of small end = 0.45D Ratio of inner to outer diameter of piston pin = 0.6 Mean diameter of piston boss = 1.4 x outer diameter of piston pin Allowable bending stress for piston pin = 84 N/mm2 %3D Calculate i. Outer diameter and inner diameter of the piston pin ii. Mean diameter of the piston boss; iii. The maximum gas pressures iv. check the design for bending stresses.

Find the force pneed to fill the gap. Young's modulus as 300 GPa C 1,5 cm² 2 cm2 P. A 1 cm 1/2 p 0.5 m 0.5 m 1 m 0.5 mm (a) 13.84KN. (b) 14.21KN.

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Solidworks

L=9m W=5kN/m 360 UB 50.7

Please help. Written on paper not typed on computer or keyboard please. Need help on all questions. Please include all units, steps to the problem and information such as its direction or if it is in compression or tension. Thx.

3) Calculations for the red dog food can rolling down the slope in the Rube Goldberg design are as follows (we will name it Step 1): DO Step 1 (calculations are given): Coefficient of friction → μ = 0.14 Mass of the object → m = 368 gm = 0.368kg Initial height of the object (red can on top of books) → h=8.89, cm = 0.0889 m Slope of the file folder → 0 = 14° Travelling Distance by the object = 11.5 inch = 0.292 m And length that the object will travel = h/sin 0 = 0.0889/ sin14° = 0.367 m So, the radius of the object → R = 0.367 -0.292 = 0.075 m Initial Velocity of red can → u=0 Velocity and Force Calculations for Step 1: -From total mechanical energy conservation: → Initial mechanical energy = final mechanical energy → mg - In case of pure rolling, the velocity of the center of mass: →→V=Ro=0.075 x 14.28 = 1.07 m/s. -Hence the change in force acting on the object for the travel: →F=mgsine = 0.368 x 9.81 × sin14° =0.89 N Step 2: The Selective Step (Step 2) in this design and for the…

Flat belt 100mm wide and 8mm thick transmits power between two pulleys, running at 1600 m/min. The mass of belt is 0.9kg/m length, the angle of lap in the smaller pulley is 1650 and the coefficient of friction between the belt and pulleys is 0.3, If the maximum permissible stress in the belt is 2MN/m2, find the maximum power transmitted. 1 Add file

A long steel rod is placed horizontally between two supports, one at each end. The rod bends a little in the center. Which property of this rod can be used to estimate how  much the rod should bend at the center? 1. Its Shear Modulus   2. Its Young's Modulus   3. All of these Moduli can be used to compute how much it bends.   4. Its Bulk Modulus.

Given the following conditions: Q = 0.05 m3/s P1 = 12.5 kPa P2 = 11.5 kPa P3 = 10.3 kPa Find HL (1-2) P2 = 50 mm = 50 mm 10m P3 d.= 30 mm

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