Copy of Mod 3 Statistics Written Problems
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School
Arizona State University *
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Course
142
Subject
Mathematics
Date
Feb 20, 2024
Type
Pages
4
Uploaded by AmbassadorFieldLobster34
Statistics Written Problems
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1.
[3 pts]
The average weight of 6 people in an elevator is 173 pounds. A 7
th
person gets on and now
the average weight is 165 pounds. How much did the 7
th
person weigh?
Set Up & Work
(2 pts)
Answer
(0.5 pt)
117 lbs
Reasoning/Explanation
(0.5 pt)
To calculate the weight of the seventh person, we have to ±ind the difference between the total
weight of the elevators. We do this by taking the average weight multiplied by the number of
people. Thus the elevator with six people weighed one thousand thirty-eight pounds and the
elevator with seven people weighed one thousand one hundred ±ifty-±ive pounds. Then we
subtract to ±ind the difference. One thousand one hundred ±ifty-±ive pounds minus one thousand
thirty eight pounds equals one hundred seventeen pounds.
2.
Use the following data obtained from ages of the last six U. S. Presidents at the time of their
inauguration to answer the following questions:
Ages of Last 6 Presidents
at Inauguration
George Bush
64
Bill Clinton
46
George W. Bush
54
Barack Obama
47
Donald Trump
70
Joe Biden
78
a.
[2 pts]
Find the mean of the data set. (Round to one decimal place.)
Work
(1 pt)
Answer
(0.5 pt)
59.8 years old
Reasoning/Explanation
(0.5 pt)
The mean is calculated by taking the sum of all data values divided by the number of data values.
In this case we add together sixty-four, forty-six, ±ifty-four, forty-seven, seventy, and
seventy-eight to get a sum of three hundred ±ifty-nine. Then we divide by the total number of
data values which is six. Thus three hundred ±ifty-nine divided by six equals ±ifty-nine and eight
tenths.
b.
[4 pts]
Find the standard deviation of the data set. (Do not round until the final answer. Round
final answer to 1 decimal place.)
Work
(2.5 pts)
Answer
(0.5 pt)
13.0
Reasoning/Explanation
(1 pt)
To calculate standard deviation we ±irst have to take each value minus the mean squared. The
table on the right illustrates this process. Each data value is labeled as x. Moving across the table
we take the initial value of x minus the mean which we found to be ±ifty-nine and eight tenths.
Once we have this new value we square it. For example, sixty-four minus ±ifty-nine and eight
tenths equals four and two tenths, then squared it equals seventeen and sixty-four hundredths.
We repeat this process with all the data values. Then we have to add up the farthest right column
with the squared data values. This gave us a total of eight hundred forty and eighty-four
hundredths. Then we can plug this into our standard deviation formula. Plugging it into the
formula we take the square root of eight hundred forty and eighty-four hundredths divided by
the total population minus one, thus six minus one. Through calculations this equals the square
root of one hundred sixty-eight and one hundred sixty-eight thousandths. The square root of this
then equals thirteen. Thus the standard deviation is thirteen.
c.
[1 pt]
What percentage of presidents’ ages fall within one standard deviation of the mean?
(Round to 1 decimal place.)
Work
(0.5 pt)
Answer
(0.25 pt)
66.7%
Reasoning/Explanation
(0.25 pt)
To ±ind the percentage of presidents that fall within one standard deviation of the mean we ±irst
have to establish the mean and standard deviation. We did this in previous steps, the mean
equals ±ifty-nine and eight tenths and the standard deviation is thirteen. Then we have to ±ind
the range in which we are looking at. To do this we take the mean plus and minus the standard
deviation. Fifty-nine and eight tenths minus thirteen equals forty-six and eight tenths and
±ifty-nine and eight tenths plus thirteen equals seventy-two and eight tenths. So the range we are
looking for is forty-six and eight tenths to seventy-two and eight tenths. Four of the six
presidents' ages fall within this range. So we take four divided by six multiplied by one hundred
which equals sixty-six and sixty-six hundredths. Converting this into a percentage, we have
sixty-six and seven tenths percent of the presidents' ages fall within one standard deviation of
the mean.
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