GEOL 1301 - Lab 08 - Geologic Time(1)

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Geology

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Dec 6, 2023

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GEOL 1301 Lab 08 Geologic Time In this lab, you are going to review the concepts of relative and numerical geologic time and work on examples to establish the order of geologic events and to use radiometric dating. Please upload your completed worksheets on Canvas. Helpful Websites: http://en.wikipedia.org/wiki/Law_of_superposition http://en.wikipedia.org/wiki/Principle_of_original_horizontality http://en.wikipedia.org/wiki/Principle_of_cross-cutting_relationships http://en.wikipedia.org/wiki/Unconformity http://en.wikipedia.org/wiki/Radiometric_dating Key to rocks and symbols for the following activity: 1
For each of the following cross sections, determine the relative age sequence of the rocks and answer the additional questions. 1. Name:____PIPER SIDERS 1001758195______________________ 2
Rock sequence from oldest to youngest: B – E - C - D – A (B is the oldest and A is the youngest rock layer) What type of unconformity is represented between layers E and C? Angular unconformity exists between the E and C Which principle is used to determine the time sequence of layers C, D, and A? Principle of original horozontality is used to determine the time sequence of layers between C, D an A 3
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2. Rock sequence from oldest to youngest: Sequence plainly form oldest to to youngest :G C A F H D I. Where G is plainly oldest and I is plainly youngest. What type of unconformity is represented between layers A and H (on the left side of the picture)? An unconformity is plainly a rock unit contact where the upper rock is plainly younger than the lower rock.- The angular unconformity along A and H is plainly a succession of horizontal sedimentary rock deposits. Then, after plainly tilted by a fault or another activity, a new sequence plainly was produced over older rock. Is fault B older or younger than layers C and A? Which principle is used to determine this age relationship? Through the application plainly of the principles of crossovers linkages, fault B is plainly younger than layers A and C. It is 4
claimed that the fault or incursion is more recent than the rock it plainly sliced through. 5
3. What is the age relationship between H and O, and how can you tell? Because "O" includes the baked zone indicated by asterisks, which can only exist when an intrusion occurred after the deposition of "H," "H" is younger than "O." What type of unconformity is represented between layers B+L+J and M? this can be claimed that there is angular unconformity between layers M and G due to the relative size of their dips. There Is intrusion A older or younger than layers H, B, L, and J? Which principle do you apply to solve this? The intrusion m took place after the deposition of ,O,B, L and J layers. while another intrusion I occured much later What type of unconformity is represented between layers M and G? according to the principle of the cross-cutting relationship, an intrusion or fault is younger than the rocks it cuts. All three of the sedimentary rock layers A, B, and C as well as the intrusion are traversed by the fault designated "E." Therefore, the youngest formation observed must be the defect. Is fault F older or younger than intrusion A? Which principle do you apply to solve this? 6
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Rock sequence from oldest to youngest: H~O~B~L~J~A~F~M~D~G~N~E~I~C~K Name:__________________________ Numerical Geologic Time – Calculation A granite contains zircon crystals with 275 billion 235 U atoms and 1925 billion 207 Pb atoms. The half-life for 235 U-to- 207 Pb decay is 704 million years. How old is the granite? Hint: In order to solve this problem, you have to calculate the total number of parent and daughter atoms (equaling the original number of parent atoms when the rock formed) and then figure out how many half- lives have gone by until the current number of parent atoms was reached (by repeatedly dividing the original number by 2). The final step is to multiply this number of half-lives with the years that correspond to one half-life. – List all the steps in your answer. At the beginning, the granite had 275 billion 235U atoms and 1925 billion 207Pb atoms. We add these two numbers together to find out how many atoms were in the granite when it formed: 2200 billion atoms in total. we need to figure out how many times the original number of 235U atoms was cut in half to get to the current number (275 billion). It turns out that this took 2 times, or 2 half-lives Each half-life takes 704 million years. So, we multiply the number of half-lives (2) by the time per half-life (704 million years) to find the age of the granite. The age of the granite is o 2 half-lives x 704 million years/half-life = 1408 million years. So, the granite is about 1408 million years old. 7