EET-115 Lab 11 - GFCI & Arc Fault Protection
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Centennial College *
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115
Subject
Electrical Engineering
Date
Apr 3, 2024
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Page 1
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Centennial College
Electrical Engineering Technician / Technology
EET-115 Installation Methods 1
Name:
ROBIN SHARMA
Student #:
301451669
Section:
Date:
LAB #11
GFCI & Arc Fault Protection
Objectives
:
To understand all theory reviewed and correctly install and wire a GFCI/AFCI breaker, and a
ground fault receptacle.
Materials
&
Tools
Required
:
●
Deck Screws
●
Linesmen Pliers
●
NMD90 Cable
●
Diagonal Pliers
●
15A GFCI Receptacle
●
Needle-nose Pliers
●
15A AFCI Breaker
●
Screwdrivers (Various)
●
Wire Nuts (Marrettes)
●
Wire Strippers
NOTE: Do not install any improper or damaged components. Wiring must be performed to meet current electrical code requirements.
Installation
Instructions
:
Review all components at your work station and ensure they are installed correctly.
Install and wire an arc fault breaker to a duplex receptacle
Install a breaker and wire a GFCI receptacle.
Have instructor review finished work.
Answer all questions for this lab listed below.
Page 2
of 2
Questions
: State the CEC Rule number if the code book is used.
1.
How do you add additional standard duplex receptacles to a GFCI receptacle so that they too are
protected by the GFCI receptacle?
We add additional standard duplex receptacles to a GFCI receptacle by connecting it to the load side of the GFCI receptacle.
2.
A combination type AFCI protects you from what type of arc faults?
Combination type AFCI protects from parallel and series arcing.
3.
Name 1 room of a house that requires AFCI protection according to the CEC?
According to CEC Bedroom of the house is required to be AFCI-protected. 4.
All receptacles installed outdoors and within 2.5 m of finished grade shall be protected with (
GFCI
)
(
Rule 26-722
)
protection. (circle one)
AFCI
GFCI
5.
GFCI protection is required for all receptacles installed within what distance of a swimming pool?
According to CEC Rule 68-064 (2), GFCI protection is required for all the receptacles installed within a 1.5m distance of the swimming pool.
Page 3
of 2
GFCI
AFCI
QUESTIONS
TOTAL MARK
5
5
5
15
Instructor Signature
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Related Questions
1. The subscript d in the generator subtransient reactance refers to:
1. Generator
impedance
2. If the available fault current slightly exceeds the breaker published
2. Generator
3. Direct axis
4. 1 and 2
reactance
interrupting rating, then it is safe to use the breaker.
1. True
| 2. False
3. Maybe
3. The rms symmetrical fault current times an asymmetry factor K, is equal to
the ac fault current.
| 2. False
4. The most common fault on a 3-phase power system is:
1. True
3. Maybe
| 2. DLG
3. L-L
1. SLG
5. All rotating and non-rotating load impedances are usually included in a power
system fault study
1. True
2. False
3. Мaybe
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Q2
Figure Q2 shows a single line diagram of a power system and the associated data of this system
are given in Table Q2. The pre-fault load current and A-Y transformer phase shift are
neglected.
(a)
(b)
If a Single Line-to-Ground (S-L-G) fault occurs at Bus 5 and the pre-fault voltage is
1.0 pu, calculate the subtransient fault current in Ampere.
(c)
(d)
(e)
Using base of 100 MVA and 11 kV at generator G₁, construct the positive sequence,
negative sequence and zero sequence networks with their corresponding component
values indicated.
G₁
Recalculate (b) if the neutral on HV side of T3 is solidly grounded.
Repeat part (b) with Line-to-line (L-L) fault.
What will happen to L-L fault current in (d) if the neutral on the HV side of T3 is
solidly grounded?
Bus 1
T₁
Bus 4
Line 1
Line 2
Figure Q2
Bus 5
T2
T3
Bus 2
Bus 3
G₂
G3
arrow_forward
Please solve Q1(C) ONLY. Q1(A) is for reference.
arrow_forward
b) A fault occurs at bus 3 of the network shown in Figure Q4. Pre-fault nodal
voltages throughout the network are of 1 p.u. and the impedance of the electric
arc is neglected. Sequence impedance parameters of the generator,
transmission lines, transformer and load are given in Figure Q4.
V₁ = 120° p.u.
V₂ = 120° p.u. V₂ = 1/0° p.u.
V₂= 120° p.u.
jXj0.1 p.u.
JX2) 0.1 p.u.
jX0j0.15 p.u.
jXn-j0.2 p.u.
1 JX(2)-j0.2 p.u. 2
jX)=j0.25 p.u.
JX20-10.15 p.u.
jXa(z)-j0.2 p.u. 4
jX2(0)=j0.2 p.u.
jXT(1) j0.1 p.u.
jXT(2)=j0.15 p.u.
jXT(0)=j0.1 p.u.
Figure Q4. Circuit for problem 4b).
=
jXj0.1 p.u.
j0.1 p.u.
-
JX(2)
JXL(0) 10.1 p.u.
=
(i) Assuming a balanced excitation, draw the positive, negative and zero
sequence Thévenin equivalent circuits as seen from bus 3.
(ii) Determine the positive sequence fault current for the case when a three-
phase-to-ground fault occurs at bus 3 of the network.
(iii) Determine the short-circuit fault current for the case when a one-phase-
to-ground fault occurs at bus…
arrow_forward
5.The most frequently occurring fault in electrical power systems is Immersive reader.
A) Symmetrical three-phase fault
B) Line to ground fault
C) Line to Line Fault
D) Double Line to Ground Fault
E) N. A.
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b) A fault occurs at bus 4 of the network shown in Figure Q3. Pre-fault nodal
voltages throughout the network are of 1 p.u. and the impedance of the electric
arc is neglected. Sequence impedance parameters of the generator,
transmission lines, and transformer are given in Figure Q3, where X and Y are
the last two digits of your student number.
V₁ = 120° p.u. V₂ = 120° p.u.
jX(1) j0.1Y p.u.
jX2)= j0.1Y p.u.
jXko) j0.1X p.u.
-
0
jX(1) = j0.2 p.u.
1JX(2) = 0.2 p.u. 2
jX1(0) = j0.25 p.u.
jX2(1) j0.2 p.u. V₁=1/0° p.u.
jX(2(2) = j0.2Y p.u.
jX2(0) = j0.3X p.u.
=
V₂ = 120° p.u.
jXT(1)
j0.1X p.u.
jXT(2) j0.1X p.u.
JX3(1) j0.1Y p.u.
JX3(2)=j0.1Y p.u.
jXT(0) j0.1X p.u. JX3(0)=j0.15 p.u.
0-
=
3
=
Figure Q3. Circuit for problem 3b).
For example, if your student number is c1700123, then:
jXa(n) = j0.13 p. u., jXa(z) = j0.13 p. u., and jXa(o) = j0.12 p. u.
4
(i) Assuming a balanced excitation, draw the positive, negative and zero
sequence Thévenin equivalent circuits as seen from bus 4.
(ii)…
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Q2: A generator supplies motor through a star-delta transformer. The generator is connected
to the star side of transformer. A fault occurs between the motor terminals and the
transformer. The symmetrical components of the rubtransient current in motor and
transformer toward the fault as table below
laz(per unit)
j2.0
lao(per unit)
j3.0
las (per unit)
Motof toward the fault
Transformer toward the
-0.8-j2.6
0.8-j0.4
j1.0
fault
Assume X-X,- X2 for both the motor and gencrator. Describe the type of fault.
Find (a) the prefault current, in line a, (b) the subtransient fault current in per unit and (c)
the subtransient current in each phase of the gencrator in per unit.
Gén.
Motor
arrow_forward
Describe the process of fault current analysis in power systems and its significance in protecting electrical equipment from damage.
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Describe the concept of fault current analysis in power systems and its role in protecting electrical equipment.
arrow_forward
Q3. i) Identify the type of the fault can happen for the situation below.
"when a mechanical excavator cuts quickly through a whole 3 phase overhead line".
Justify your answer.
ii) Examine the assumptions and calculation steps for the identified fault analysis in Q3(i).
iii) Illustrate applications of the fault analysis in the Q3(ii).
arrow_forward
b) A fault occurs at bus 2 of the network shown in Figure Q3. Pre-fault nodal
voltages throughout the network are of 1 p.u. and the impedance of the
electric arc is neglected. Sequence impedance parameters of the generator,
transmission lines, and transformer are given in Figure Q3, where X and Y are
the last two digits of your student number.
JX20 /0.1X p.u.
jXa2) 0.1X p.u.
JX20 j0.2Y p.u.
V,= 120° p.u. V, 120° p.u.
V, 120° p.u.
jX4-70.2X p.u.
jX2 j0.2X p.u.
jX o 0.2Y p.u.
jXncay J0.25 p.u.
jXna J0.25 p.u. 3
jXno0.3 p.u.
jXTu) /0.2Y p.u.
jXra j0.2Y p.u.
- j0.2Y p.u.
Xp-10.1X p.u.
jXa j0.1X p.u.
jXp0)- j0.05 p.u.
0
Figure Q3. Circuit for problem 3b).
For example, if your student number is c1700123, then:
jXac1) = j0.22 p.u., jXac2) = j0.22 p.u., and jXaco) = j0.23 p. u.
X-2
Y=8
(iv) Determine the short-circuit fault current for the case when a phase-to-
phase fault occurs at bus 2.
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ignore X and Y values
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Related Questions
- 1. The subscript d in the generator subtransient reactance refers to: 1. Generator impedance 2. If the available fault current slightly exceeds the breaker published 2. Generator 3. Direct axis 4. 1 and 2 reactance interrupting rating, then it is safe to use the breaker. 1. True | 2. False 3. Maybe 3. The rms symmetrical fault current times an asymmetry factor K, is equal to the ac fault current. | 2. False 4. The most common fault on a 3-phase power system is: 1. True 3. Maybe | 2. DLG 3. L-L 1. SLG 5. All rotating and non-rotating load impedances are usually included in a power system fault study 1. True 2. False 3. Мaybearrow_forwardQ2 Figure Q2 shows a single line diagram of a power system and the associated data of this system are given in Table Q2. The pre-fault load current and A-Y transformer phase shift are neglected. (a) (b) If a Single Line-to-Ground (S-L-G) fault occurs at Bus 5 and the pre-fault voltage is 1.0 pu, calculate the subtransient fault current in Ampere. (c) (d) (e) Using base of 100 MVA and 11 kV at generator G₁, construct the positive sequence, negative sequence and zero sequence networks with their corresponding component values indicated. G₁ Recalculate (b) if the neutral on HV side of T3 is solidly grounded. Repeat part (b) with Line-to-line (L-L) fault. What will happen to L-L fault current in (d) if the neutral on the HV side of T3 is solidly grounded? Bus 1 T₁ Bus 4 Line 1 Line 2 Figure Q2 Bus 5 T2 T3 Bus 2 Bus 3 G₂ G3arrow_forwardPlease solve Q1(C) ONLY. Q1(A) is for reference.arrow_forward
- b) A fault occurs at bus 3 of the network shown in Figure Q4. Pre-fault nodal voltages throughout the network are of 1 p.u. and the impedance of the electric arc is neglected. Sequence impedance parameters of the generator, transmission lines, transformer and load are given in Figure Q4. V₁ = 120° p.u. V₂ = 120° p.u. V₂ = 1/0° p.u. V₂= 120° p.u. jXj0.1 p.u. JX2) 0.1 p.u. jX0j0.15 p.u. jXn-j0.2 p.u. 1 JX(2)-j0.2 p.u. 2 jX)=j0.25 p.u. JX20-10.15 p.u. jXa(z)-j0.2 p.u. 4 jX2(0)=j0.2 p.u. jXT(1) j0.1 p.u. jXT(2)=j0.15 p.u. jXT(0)=j0.1 p.u. Figure Q4. Circuit for problem 4b). = jXj0.1 p.u. j0.1 p.u. - JX(2) JXL(0) 10.1 p.u. = (i) Assuming a balanced excitation, draw the positive, negative and zero sequence Thévenin equivalent circuits as seen from bus 3. (ii) Determine the positive sequence fault current for the case when a three- phase-to-ground fault occurs at bus 3 of the network. (iii) Determine the short-circuit fault current for the case when a one-phase- to-ground fault occurs at bus…arrow_forward5.The most frequently occurring fault in electrical power systems is Immersive reader. A) Symmetrical three-phase fault B) Line to ground fault C) Line to Line Fault D) Double Line to Ground Fault E) N. A.arrow_forwardb) A fault occurs at bus 4 of the network shown in Figure Q3. Pre-fault nodal voltages throughout the network are of 1 p.u. and the impedance of the electric arc is neglected. Sequence impedance parameters of the generator, transmission lines, and transformer are given in Figure Q3, where X and Y are the last two digits of your student number. V₁ = 120° p.u. V₂ = 120° p.u. jX(1) j0.1Y p.u. jX2)= j0.1Y p.u. jXko) j0.1X p.u. - 0 jX(1) = j0.2 p.u. 1JX(2) = 0.2 p.u. 2 jX1(0) = j0.25 p.u. jX2(1) j0.2 p.u. V₁=1/0° p.u. jX(2(2) = j0.2Y p.u. jX2(0) = j0.3X p.u. = V₂ = 120° p.u. jXT(1) j0.1X p.u. jXT(2) j0.1X p.u. JX3(1) j0.1Y p.u. JX3(2)=j0.1Y p.u. jXT(0) j0.1X p.u. JX3(0)=j0.15 p.u. 0- = 3 = Figure Q3. Circuit for problem 3b). For example, if your student number is c1700123, then: jXa(n) = j0.13 p. u., jXa(z) = j0.13 p. u., and jXa(o) = j0.12 p. u. 4 (i) Assuming a balanced excitation, draw the positive, negative and zero sequence Thévenin equivalent circuits as seen from bus 4. (ii)…arrow_forward
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- Q3. i) Identify the type of the fault can happen for the situation below. "when a mechanical excavator cuts quickly through a whole 3 phase overhead line". Justify your answer. ii) Examine the assumptions and calculation steps for the identified fault analysis in Q3(i). iii) Illustrate applications of the fault analysis in the Q3(ii).arrow_forwardb) A fault occurs at bus 2 of the network shown in Figure Q3. Pre-fault nodal voltages throughout the network are of 1 p.u. and the impedance of the electric arc is neglected. Sequence impedance parameters of the generator, transmission lines, and transformer are given in Figure Q3, where X and Y are the last two digits of your student number. JX20 /0.1X p.u. jXa2) 0.1X p.u. JX20 j0.2Y p.u. V,= 120° p.u. V, 120° p.u. V, 120° p.u. jX4-70.2X p.u. jX2 j0.2X p.u. jX o 0.2Y p.u. jXncay J0.25 p.u. jXna J0.25 p.u. 3 jXno0.3 p.u. jXTu) /0.2Y p.u. jXra j0.2Y p.u. - j0.2Y p.u. Xp-10.1X p.u. jXa j0.1X p.u. jXp0)- j0.05 p.u. 0 Figure Q3. Circuit for problem 3b). For example, if your student number is c1700123, then: jXac1) = j0.22 p.u., jXac2) = j0.22 p.u., and jXaco) = j0.23 p. u. X-2 Y=8 (iv) Determine the short-circuit fault current for the case when a phase-to- phase fault occurs at bus 2.arrow_forwardignore X and Y valuesarrow_forward
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