Week 1_ Homework-Review

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North Carolina State University *

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Computer Science

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Dec 6, 2023

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1/21/23, 8:56 PM Homework Week 1: Attempt review https://moodle-courses2223.wolfware.ncsu.edu/mod/quiz/review.php?attempt=1177545&cmid=768226 1/8 Started on Saturday, January 14, 2023, 4:32 PM State Finished Completed on Sunday, January 15, 2023, 11:04 AM Time taken 18 hours 32 mins Grade 83.33 out of 100.00 Information Question 1 Partially correct 3.33 points out of 5.00 An online agency rents out vacation properties via its website. The websites is dynamic in the sense that it looks and operates differently depending on the combination of device (e.g. desktop) and application (e.g. Safari or Firefox) that is being used. Therefore, the company is interested in examining the relationship between booking requests and the device/application being used. Ultimately, the agency prefers that a higher percentage of users send a booking request. Please use the Data Dictionary and the Raw Data to help this agency answer a series of specific questions. Create a histogram of Session Length. Which of the following apply (check all that apply)? Select one or more: a. The data is skewed right. b. The mean and median will be exactly equal. c. The mean will be lower than the median. d. The data is skewed left. e. The data is normally distributed. f. The mean will be higher than the median. g. The data is not normally distributed. Your answer is partially correct. You have correctly selected 2. The distribution is not close to normal. The distribution is also skewed right which implies that the mean will be greater than the median. The correct answers are: The data is not normally distributed., The data is skewed right., The mean will be higher than the median.
1/21/23, 8:56 PM Homework Week 1: Attempt review https://moodle-courses2223.wolfware.ncsu.edu/mod/quiz/review.php?attempt=1177545&cmid=768226 2/8 Question 2 Correct 5.00 points out of 5.00 Question 3 Correct 5.00 points out of 5.00 Question 4 Correct 5.00 points out of 5.00 What is the standard deviation of Session Length (round to two significant digits (e.g. 3.14957 would be 3.15)? Answer: 20.48 The correct answer is: 20.48 What is the mean Session Length (round to 2 significant digits)? Answer: 14.43 The correct answer is: 14.43 What is the median Session Length (round to two significant digits (e.g. 3.14957 would be 3.15)? Answer: 7.26 The correct answer is: 7.26
1/21/23, 8:56 PM Homework Week 1: Attempt review https://moodle-courses2223.wolfware.ncsu.edu/mod/quiz/review.php?attempt=1177545&cmid=768226 3/8 Question 5 Incorrect 0.00 points out of 5.00 Question 6 Correct 5.00 points out of 5.00 Given the distribution, what is the most appropriate measure of center in this distribution? Select one: a. Mean b. Skewness c. Median d. Standard Deviation Your answer is incorrect. The mean is impacted more by skewness and outliers. Therefore, in this situation, the median is the most appropriate measure of center. The other measures do not measure center. The correct answer is: Median Create a Bar Chart for the variable DEVICE APP COMBO ("device app combo on the x axis, and number of occurrences on the y axis). Create a pie chart for DEVICE. What observations can you make based on these graphs (ignore "Unknown" and "Other" categories) ? Which device/app combo is most often used to access the site? Which device/app combo is least often used to access the site? What device is most often used to access the site? What device is least often used to access the site? iPhone - iOS Android Tablet - Moweb Desktop Android Tablet Your answer is correct. The bar chart shows that Android Tablet - Moweb is the least used combo while iPhone - Ios is the most used combo. The pie chart shows that desktop is the device that is used most often while Android Tablet is the least used (after ignoring Unknown and Other). The correct answer is: Which device/app combo is most often used to access the site? iPhone - iOS Which device/app combo is least often used to access the site? Android Tablet - Moweb What device is most often used to access the site? Desktop What device is least often used to access the site? Android Tablet
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1/21/23, 8:56 PM Homework Week 1: Attempt review https://moodle-courses2223.wolfware.ncsu.edu/mod/quiz/review.php?attempt=1177545&cmid=768226 4/8 Question 7 Correct 5.00 points out of 5.00 Question 8 Correct 5.00 points out of 5.00 Question 9 Incorrect 0.00 points out of 5.00 For the following questions, create a contingency table with the variables DEVICE and APPLICATION and use the table to answer questions about probabilities.. What is the marginal probability that the site was accessed via iPhone Device (write in whole percentages with two significant digits (e.g. .2544 would be 25.44)) Answer: 37.26 The probability that users used an IPhone is 37.27% =1616/4336 The correct answer is: 37.27 What is the marginal probability of the site being accessed via Moweb (round to two significant digits using percentage notation (e.g. .2544 would be 25.44))? Answer: 4.15 The marginal probability the site was accessed via Moweb is 4.15 =180/4336 The correct answer is: 4.15 Given an iPhone was used, what is the probability that the Web was used to access the site (round to two significant digits using percentage notation (e.g. .2544 would be 25.44))? Answer: 4.59 12.31% of iPhone users used the Web to access the site =199/1616 The correct answer is: 12.31
1/21/23, 8:56 PM Homework Week 1: Attempt review https://moodle-courses2223.wolfware.ncsu.edu/mod/quiz/review.php?attempt=1177545&cmid=768226 5/8 Question 10 Correct 5.00 points out of 5.00 Question 11 Correct 5.00 points out of 5.00 Question 12 Correct 5.00 points out of 5.00 What is the combined probability that a users accessed the site via an iPhone or an iPad (round to two significant digits using percentage notation (e.g. .2544 would be 25.44))?? Answer: 44.86 = (329+1616)/4336 The correct answer is: 44.86 What application are Desktop users most likely to use when accessing the site? Select one: a. Firefox b. Chrome c. IE d. Safari Your answer is correct. 47.35% of the Desktop users access the site via Chrome = 778/1643. All others are lower within the Desktop users. The correct answer is: Chrome What is the overall probability that a site visitor makes a booking request? (round to two significant digits using percentage notation (e.g. .2544 would be 25.44)) Hint: you can build a contingency table with "Sent Booking Request" and "Device" as categorical variables to answer the following questions. Answer: 2.70 117 out of 4336 visitors sent a booking request = 2.70% The correct answer is: 2.7
1/21/23, 8:56 PM Homework Week 1: Attempt review https://moodle-courses2223.wolfware.ncsu.edu/mod/quiz/review.php?attempt=1177545&cmid=768226 6/8 Question 13 Incorrect 0.00 points out of 5.00 Question 14 Correct 10.00 points out of 10.00 What percent of iPhone user sessions make a booking request (round to two significant digits using percentage notation (e.g. .2544 would be 25.44))? Answer: 17.95 21 of 1616 iPhone sessions made a booking request (1.30%). The correct answer is: 1.3 Given your results regarding booking requests. Which of the following statements are true (check all that apply). Select one or more: a. As compared to iPhone users, Desktop users are more than 3 times as likely to make a booking request. b. As compared to the overall probability, iPhone users are less than half as likely to make a booking request. c. As compared to IPAD users, Desktop users are more than 2 times as likely to make a booking request. d. As compared to the overall probability of making a booking request, Android Phone users are 3 times as likely to make a booking request. Your answer is correct. The correct answers are: As compared to iPhone users, Desktop users are more than 3 times as likely to make a booking request., As compared to the overall probability, iPhone users are less than half as likely to make a booking request., As compared to IPAD users, Desktop users are more than 2 times as likely to make a booking request.
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1/21/23, 8:56 PM Homework Week 1: Attempt review https://moodle-courses2223.wolfware.ncsu.edu/mod/quiz/review.php?attempt=1177545&cmid=768226 7/8 Question 15 Correct 10.00 points out of 10.00 Question 16 Correct 7.50 points out of 7.50 Given you analysis so far, which of the following statements is the most appropriate conclusion? Select one: a. There is no difference in booking rates across device and application. b. There is definitely a problems with the iPhone user experience. c. There are differences in booking rate, but it really doesn't matter as hardly any of the users interact with the site via phone or tablet. d. It appears as if desktop users are more likely to send a booking request. We should look into whether the experience is bad for other users or people just prefer to book using a computer. Your answer is correct. We can see that there are apparent differences in the booking rates of devices. However, we can not determine why those booking rates are different. So, we can say the experience is bad only we should look into why its happening. The correct answer is: It appears as if desktop users are more likely to send a booking request. We should look into whether the experience is bad for other users or people just prefer to book using a computer. Assume the raw data provided is the entire population. If you take multiple samples each having a sample size of n=40. What would you expect the sample means of SESSION LENGTH to be (round to two significant digits)? Answer: 3.24 The sample means should approach the overall populations mean given sample size is sufficiently large. The mean of Session Length in the raw data is 14.43. The correct answer is: 14.43
1/21/23, 8:56 PM Homework Week 1: Attempt review https://moodle-courses2223.wolfware.ncsu.edu/mod/quiz/review.php?attempt=1177545&cmid=768226 8/8 Question 17 Correct 7.50 points out of 7.50 Assume the raw data provided is the entire population. What would you expect the mean sample standard deviation of SESSION LENGTH to be if sample size n=100 (round to two significant digits)? Answer: 2.05 The sample means should approach the overall populations mean given sample size is sufficiently large. The mean of Session Length in the raw data is 14.43. The standard deviation of the sample means should be the population standard deviation (20.48) divided by the sqrt of sample size (=20.48/sqrt(100) = 2.05) The correct answer is: 2.05