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York University *

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2020

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Chemistry

Date

Jan 9, 2024

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docx

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User You A 28.6 mL solution of HBr (a strong acid) of unknown concentration was titrated using 0.3194 mol L-1 NaOH using phenolphthalein as a pH indicator. At the moment when the solution turned a consistent light pink colour, the burette volume read 28.12 mL. The initial burette reading before the experiment was 7.58 mL. What was the concentration of HBr in the original HBr solution in mol L-1 ? ChatGPT ChatGPT To find the concentration of HBr in the original solution, you can use the concept of titration. In a titration, the moles of the titrant (NaOH, in this case) reacting with the analyte (HBr) can be determined based on the balanced chemical equation. Then, you can use this information to calculate the concentration of HBr. Here's how you can calculate it step by step: Calculate the moles of NaOH used: Moles of NaOH = (final burette reading - initial burette reading) × NaOH concentration Moles of NaOH = (28.12 mL - 7.58 mL) × 0.3194 mol/L Moles of NaOH = 20.54 mL × 0.3194 mol/L (convert mL to L by dividing by 1000) Moles of NaOH = 0.00656836 mol Since HBr and NaOH react in a 1:1 ratio according to the balanced chemical equation: HBr + NaOH → NaBr + H2O The moles of HBr in the original solution are also 0.00656836 mol. Calculate the concentration of HBr in the original solution: Concentration (mol/L) = Moles of HBr / Volume (L) Volume (L) = 28.6 mL / 1000 (convert to L) = 0.0286 L Concentration (mol/L) = 0.00656836 mol / 0.0286 L ≈ 0.2294 mol/L So, the concentration of HBr in the original solution is approximately 0.2294 mol/L.
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