Lab 6B Results 110123

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Name: Student ID: Date: Lab 6B Results Conservation of Energy Record the uncertainties for which blanks are provided. Thereafter, we will assume that the uncertainties are the same for the rest of the values that are measured with that particular device. This will save a lot of tedium. Measured Values Mass of NaOH, g 2.80 ± 0.01 Mass of water, g 50.40 Mass of NaOH solution, g (add the first two lines) 53.23 Mass of HCl solution, g 53.25 Temperature of HCl solution, °C 20.7 ± 0.1 Temperature of NaOH solution, °C 20.3 Final temperature of mixed solutions, ˚C 40.3 Calculated Values Heat flow of water = (mass) x (specific heat capacity for water) x (T final - T initial ) Heat flow of water, calories 1053.76 Heat flow of NaOH plus HCl, calories -1053.76 Amount of NaOH used in the reaction, moles 0.07 Heat of reaction for NaOH plus HCl, calories/mole -15053.66 Questions 1. Show your work for the calculation of the heat flow of water. 53.22(1)(19.8)= 1053.76 calories 2. Show your work for the calculation of the heat of reaction for NaOH and HCl. -1053.76/0.07= -15053.71 calories/mole 3. The true value for the heat of reaction for NaOH and HCl is -13.4 kcal/mole, which is equal to -13,400 cal/mole). It is exceptionally unlikely that your result agrees exactly with this value, but it should be fairly close. Does your result suggest that more or less heat was given off by NaOH and HCl. For example, compared to the true value, was the reaction more exothermic or less exothermic? More heat was given off. It was more exothermic

4. To do the calculations, we assumed that the heat exchange between the NaOH/HCl mixture and water was perfect. Identify three material entities that are probably absorbing at least small amounts of heat away from the mixture of water, NaOH, and HCl. (“Evaporation” is not a material entity.) Evaporation, the cup, and the time in between the lab -2107.51 calories 5. Suppose that we had used twice as much NaOH, twice as much water, and twice as much HCl. According to your results, what would have been the heat flow of NaOH and HCl? -15053.66 calories/mole 6. Suppose that we had used ten times as much NaOH, ten times as much water, and ten times as much HCl. According to your results, what would have been the heat of reaction for NaOH and HCl? -10537.562

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