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A titration of 29.2 mL of a solution of the weak base aniline, C_HẠNH, ( K-4.0 x 10-10), requires 21.61 mL of 0.155 M HCI to reach the equivalence point. C_H_NHz(aq)}+HJO* (aq)=C_H_NH, (aq)+H_O() a What was the concentration of aniline in the original solution? Concentration = 0.315 The equivalence point for a reaction is the point at which one reactant has been completely consumed by addition of another reactant. Thus, [C HÌNH, X 0.155 mol HC1 1.00 L 1 29.2 mL <= 0.115 M x 21.61 ml x b what are the concentrations of H₂O*, OH, and CeHs NHS at the equivalence point? [H₂O+]- Correct M 1 mol C₂ H₂NH₂ 1 mol HC1 X Show Hint Previous Next>

A titration of 29.2 mL of a solution of the weak base aniline, C_HẠNH, ( K-4.0 x 10-10), requires 21.61 mL of 0.155 M HCI to reach the equivalence point. C_H_NHz(aq)}+HJO* (aq)=C_H_NH, (aq)+H_O() a What was the concentration of aniline in the original solution? Concentration = 0.315 The equivalence point for a reaction is the point at which one reactant has been completely consumed by addition of another reactant. Thus, [C HÌNH, X 0.155 mol HC1 1.00 L 1 29.2 mL <= 0.115 M x 21.61 ml x b what are the concentrations of H₂O*, OH, and CeHs NHS at the equivalence point? [H₂O+]- Correct M 1 mol C₂ H₂NH₂ 1 mol HC1 X Show Hint Previous Next>

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A titration of 29.2 mL of a solution of the weak base aniline, C@HNH, ( K 4.0 x 10-10), requires 21.61 mL of 0.155 M HCl to reach the equivalence point. CH_NHz(aq) + HyO* (aq) + C,H,NH, (aq)+H,O(l) a What was the concentration of aniline in the original solution? Concentration 0115 ✔ M The equivalence point for a reaction is the point at which one reactant has been completely consumed by addition of another reactant. Thus, [C,HNH] [H₂O+] [OH-]- = 0.155 mol HC1 1.00 L 1 29.2 mL b What are the concentrations of H₂O¹, OH, and C6H5NHs at the equivalence point? M C = 0.115 M x 21.61 ml x M Correct 1 mol C, H, NH, 1 mol HCl Show Hint <Previous Next Sava and E
Transcribed Image Text:A titration of 29.2 mL of a solution of the weak base aniline, C@HNH, ( K 4.0 x 10-10), requires 21.61 mL of 0.155 M HCl to reach the equivalence point. CH_NHz(aq) + HyO* (aq) + C,H,NH, (aq)+H,O(l) a What was the concentration of aniline in the original solution? Concentration 0115 ✔ M The equivalence point for a reaction is the point at which one reactant has been completely consumed by addition of another reactant. Thus, [C,HNH] [H₂O+] [OH-]- = 0.155 mol HC1 1.00 L 1 29.2 mL b What are the concentrations of H₂O¹, OH, and C6H5NHs at the equivalence point? M C = 0.115 M x 21.61 ml x M Correct 1 mol C, H, NH, 1 mol HCl Show Hint <Previous Next Sava and E
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