If 25.0 ml of HF (aq) ( a weak acid) is titrated to an equivalence point with a solution of NaOH (aq) of unknown concentration, which of the following is correct. HF (aq) + NaOH (aq) --> NaF (aq) + H2O (l) Select one: a. At the equivalence point the HF and the NaOH will be used up and the resulting solution will have a pH = 7 because NaF and H2O are neutral. b. At the equivalence point the HF and the NaOH will be used up and the resulting solution will have a pH > 7 because NaF is a weak base. c. At the equivalence point the resulting solution will have a pH of < 7 because NaOH is a strong acid. d. At the equivalence point the pH will equal pKa of HF. e. At the equivalence point the pH will be = 7 because NaOH is a strong base.
If 25.0 ml of HF (aq) ( a weak acid) is titrated to an equivalence point with a solution of NaOH (aq) of unknown concentration, which of the following is correct. HF (aq) + NaOH (aq) --> NaF (aq) + H2O (l) Select one: a. At the equivalence point the HF and the NaOH will be used up and the resulting solution will have a pH = 7 because NaF and H2O are neutral. b. At the equivalence point the HF and the NaOH will be used up and the resulting solution will have a pH > 7 because NaF is a weak base. c. At the equivalence point the resulting solution will have a pH of < 7 because NaOH is a strong acid. d. At the equivalence point the pH will equal pKa of HF. e. At the equivalence point the pH will be = 7 because NaOH is a strong base.
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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If 25.0 ml of HF (aq) ( a weak acid) is titrated to an equivalence point with a solution of NaOH (aq) of unknown concentration, which of the following is correct.
HF (aq) + NaOH (aq) --> NaF (aq) + H2O (l)
HF (aq) + NaOH (aq) --> NaF (aq) + H2O (l)
Select one:
a. At the equivalence point the HF and the NaOH will be used up and the resulting solution will have a pH = 7 because NaF and H2O are neutral.
b. At the equivalence point the HF and the NaOH will be used up and the resulting solution will have a pH > 7 because NaF is a weak base.
c. At the equivalence point the resulting solution will have a pH of < 7 because NaOH is a strong acid.
d. At the equivalence point the pH will equal pKa of HF.
e. At the equivalence point the pH will be = 7 because NaOH is a strong base.
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