SCH4U Lee 2.4

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OCV Chemistry, Grade 12 University Preparation (SCH4U-04/05) Ottawa-Carleton Virtual Secondary School 2020-2021 Mr. Daniel Cho-En Lee ( daniel.cho-en.lee@ocdsb.ca ) Functional groups IUPAC Functional Groups Naming Priorities You should be familiar with the naming of red starred suffixes and prefixes * . When there are more than two functional groups, the highest- priority group becomes the suffix . For all lower- priority groups, use their prefix , like methyl is the prefix of a one-carbon alkane side chain. If there is a carboxyl group (highest priority), this compound is a carboxylic acid (e.g. ...ethanoic acid) Halogens and ethers have lower priorities than alkanes, so they are always named using prefixes (e.g. fluoro-, ethoxy-). Review: What does hydrogen bond look like? https://sketchfab.com/3d-models/ice-lattice-7bacd374b8d849a2bdc92148b840b6ef Up to how many hydrogen bonds can be made in this molecule? 3 maximum, in reality, up to 2 on average 6, 4 (ethane -1,2-diol) 3, 2 1
OCV Chemistry, Grade 12 University Preparation (SCH4U-04/05) Ottawa-Carleton Virtual Secondary School 2020-2021 Mr. Daniel Cho-En Lee ( daniel.cho-en.lee@ocdsb.ca ) How about this molecule? And this? Which of the above has the highest boiling point? middle Alcohols ( suffix: -ol ) (prefix: hydroxy-) (-OH = a hydroxyl group) Exercise 1. (a) What is the chemical (molecular) formula of propan-1-ol? What is the other possible propanol? Better: C 3 H 7 OH (ok: C 3 H 8 O), propan-2-ol (b) Among alcohols, how many isomers of butanols are there? Draw their line diagrams. See below (c) The molecule on the right is glycerol . What is its IUPAC name? (hint: it is a … tri ol) propane-1,2,3-triol With a polar O-H bond like those in water, alcohol makes hydrogen bonds with each other and polar solvents such as water. The hydrocarbon region on the alcohol provides only weak intermolecular attractions. Therefore, the b.p. of small alcohols are lower than that of water. Small alcohols are miscible with water, as their polar region (-OH) is relatively large. For bigger alcohols (starting with butan-1-ol), they become immiscible with water, like oil and water. Halogenation reactions of primary, secondary, and tertiary alcohol Remember Markovnikov’s rule? The same C-H dipole analysis can be used to predict the reactions of the halogenation reaction of alcohols. As the O-H group is bonded to a C , we can classify alcohols based on how many additional carbon atoms this C is bonded to. If it is bonded to only 1 C atom, we have a primary (1º) alcohol. With an alkane mainchain, each carbon makes 4 bonds. Regarding the C where the -OH group is attached, there is 2
OCV Chemistry, Grade 12 University Preparation (SCH4U-04/05) Ottawa-Carleton Virtual Secondary School 2020-2021 Mr. Daniel Cho-En Lee ( daniel.cho-en.lee@ocdsb.ca ) already an -OH bond. The rest of the 3 bonds are either C -C or C -H. A primary alcohol has its hydroxyl C bonded to 1 C and 2 H, in addition to 1 O. A secondary alcohol has its hydroxyl C bonded to 2 C and 1 H, in addition to 1 O. A tertiary alcohol has its hydroxyl C bonded to 3 C, in addition to 1 O. Also, we know that with each C -H bond, the C gains a weak δ - . With each C -O bond, the C gains a δ + . There is no dipole moment generated across a C-C bond. Exercise 2. Among primary, secondary, and tertiary alcohol, regarding the carbon atom where the -OH group is attached, which C carries, relatively, the strongest partial negative charge? Explain. Back in the halogenation reaction of alkenes, we know that over a double bond, the carbon with the smaller δ - is the preferred site of halogenation. You may therefore infer that a tertiary alcohol is the best candidate to receive a halogen , such as Cl. But the -OH bonded carbon is already making four bonds. The period-2 carbon is too small to have an open surface area to make a 5th bond with the halogen. An existing bond has to be removed first. In the case, the -OH group will leave, and the -X (e.g. -Cl) will take its place. Exercise 2.5. With suitable conditions and catalyst, it is possible to add water onto an alkene. This is a type of addition reaction, or more specifically, hydration . (a) Using your knowledge in dipole analysis (or simply recite Markonikov’s rule), what should be the major product of the following reaction? Propene + HCl 2-chloropropane Propene + H 2 O (H + -OH - ) → propan-2-ol (b) The reverse reaction of hydration is dehydration, which is a type of elimination reaction. For butan-1-ol, name the product of its elimination/dehydration reaction. Elimination: butan-1-ol → H 2 O + but-1-ene Substitution Reaction 3
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OCV Chemistry, Grade 12 University Preparation (SCH4U-04/05) Ottawa-Carleton Virtual Secondary School 2020-2021 Mr. Daniel Cho-En Lee ( daniel.cho-en.lee@ocdsb.ca ) An addition reaction adds a small molecule (e.g. H 2 , X 2 , H-X) to an existing molecule. A substitution reaction replaces a small group with another small group - a “double displacement” in 3U words. Exercise 3. What are the products of each of the substitution reactions above (+HCl)? A. butan-1-ol + HCl → 1-chlorobutane + H 2 O B. 2-methylpropan-1-ol + HCl → 1-chloro-2-methylpropane + H 2 O C. butan-2-ol + HCl → 2-chlorobutane + H 2 O D. 2-methylpropan-2-ol + HCl → 2-chloro-2-methylpropane + H 2 O Exercise 4. Out of the four reactions above, which one should be the fastest? D) because the carbon in C-OH is the least δ - and it allows for the easiest attachment of Cl - . Exercise 5. Complete the following reactions with IUPAC names for organic compounds. It might help to draw the reactant organic compound first. If there are more than one possible products, only show the main product. (a) prop-1-ene + HCl → 2-chloropropane (b) prop-1-ene + Cl 2 1,2-dichloropropane (c) 1,2-dichloropropane → Cl 2 + propene (d) 1-chlorobutane → HCl + but-1-ene (e) propan-1-ol + HCl → 1-chloropropane + H 2 O (f) propan-2-ol + HCl → 2-chloropropane + H 2 O (g) 2-methylbutan-2-ol + HCl → 2-chloro-2-methylbutane + H 2 O Exercise 6. Each of pentan-1-ol, pentan-3-ol, 2-methylbutan-2-ol, and 2,2-dimethylpropan-1-ol undergoes a substitution reaction with HCl. Which reaction should happen the most quickly? 4
OCV Chemistry, Grade 12 University Preparation (SCH4U-04/05) Ottawa-Carleton Virtual Secondary School 2020-2021 Mr. Daniel Cho-En Lee ( daniel.cho-en.lee@ocdsb.ca ) Skipped lab #1 - Alcohol halogenation In a typical semester, here students have a half-period lab to verify the above hypothesis on reaction rate. Here are the pre-lab questions: (1) Draw a structural or line diagram of the following: A. butan-1-ol B. butan-2-ol C. 2-methylpropan-2-ol D. propan-1-ol E. propan-2-ol (2) Draw the possible halogenation reaction for each of the five alcohols. Name all reactants and products. (3) Are 1°, 2°, and 3° alcohols all expected to undergo substitution (halogenation) quickly? Explain why in 20 words. During the lab Students proceed to mix concentrated HCl with each alcohol. Here are signs that a reaction took place: There were tiny liquid droplets observed on the inner wall of the glass tube within seconds. The solution became cloudy. Some alcohols were immiscible with HCl, and nothing seemed to happen overnight. Discussion questions (besides comparing results with hypothesis) 1. What could be the tiny liquid droplets on the glass tube? Explain. If a molecule makes weak intermolecular forces, it is more likely to escape into the gas phase (evaporate/boil). So the tiny liquid droplets on the glass tube are chemicals that had weaker intermolecular forces and escaped the liquid phase. One way to tell which chemical has the weakest intermolecular force is to look up the boiling points. Even better, we can discuss the number of hydrogen bonds in each: 5
OCV Chemistry, Grade 12 University Preparation (SCH4U-04/05) Ottawa-Carleton Virtual Secondary School 2020-2021 Mr. Daniel Cho-En Lee ( daniel.cho-en.lee@ocdsb.ca ) 2-methylpropan-2-ol (83ºC) + HCl (dissociated into ions) → 2-chloro-2- methylpropane (b.p. = 51ºC) + H 2 O (b.p. = 100ºC) 2-methylpropan-2-ol: one alcohol group, max. 3 hydrogen bonds (on average, up to 2 ) HCl is a strong acid and has dissociated to H + (H 3 O + ) and Cl - . Ions are very unlikely to boil off because of the strong electrostatic attractions in ion-dipoles. 2-chloro-2-methylpropane makes no hydrogen bonds among themselves. (They do have the mediocre δ - Cl-C attract the δ + of H 2 O and -OH, though these are not comparable with the authentic H-bonds among H 2 O and OH.) You already know that H 2 O makes up to 4 H-bonds. 2. How can the cloudiness in some reactions be explained? 2-chloro-2-methylpropane can make a weak hydrogen bond (probably better to say permanent dp-dp) with water or -OH but the water and alcohol make more and stronger hydrogen bonds among themselves. 3. Suppose a reaction was expected to take place, but the reactants separated into two layers and no reaction seemed to happen. Why is there no reaction? At the liquid interface there are very limited contacts among reactant molecules. End of Quiz #5 coverage SCH4U-06 Quiz #5-#6 https://docs.google.com/presentation/d/1mUy2IUFos3TPGw_Q1Bsvs3kg9RA78O3oVLs5rOweq2I/edit?usp=sharing https://docs.google.com/presentation/d/1S4KWlEi9eFBitfrcWzs7EY9XXTjWD-BK-iCEdeRBZ2w/edit?usp=sharing Alcohol vs. SARS-CoV-2 Hand sanitizers are commonplace during this COVID-19 pandemic. If you have ever taken a deep breath from your just-sanitized hand and, you can smell alcohol. The major and active ingredient of hand sanitizers is alcohol, either 70% ethanol (old: ethyl alcohol) or propan-2-ol (old: isopropyl alcohol). During our next break, if you have a hand sanitizer bottle, take a look at the label to see if it contains one of these two alcohols. 6
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OCV Chemistry, Grade 12 University Preparation (SCH4U-04/05) Ottawa-Carleton Virtual Secondary School 2020-2021 Mr. Daniel Cho-En Lee ( daniel.cho-en.lee@ocdsb.ca ) These two alcohols are able to disrupt the lipid capsule of SARS-CoV-2 (severe acute respiratory symptom - coronavirus - 2), the virus that causes COVID-19. Soap and alcohol both work In high school biology, we typically describe viruses as “genetic material encapsulated by proteins.” In the case of SARS-CoV-2, proteins do not cover the virus entirely, but there is a lipid membrane that protects its RNA. Like fat, lipid has long hydrocarbon tails, though only 2 tails. (Fat has 3.) You might have learned the structure of soap, which is part of a hydrolyzed fat molecule. Soap keeps the long, non- polar hydrocarbon tail of fat and now has an even more polar head due to hydrolysis. The polar head of soap establishes hydrogen bonds with water. When we rub our soapy hands together in the sink, we give the soap’s non-polar tails a chance to establish LDF with the virus’ protective lipid layer. Since the soap’s tails are not really structurally compatible with the viral lipid, they will disintegrate the virus’ protective layer. Then the broken virus may be washed away with water. Watch : Fighting Coronavirus with Soap https://youtu.be/s2EVlqql_f8 Ethanol and propanol disable the virus with a different approach. Pathogens are evolved in nature to survive in an aqueous (solvent = water) environment. The lipid layer keeps water and water soluble chemicals out. By rubbing our hands using a liquid alcohol, we flood the pathogens with a not-so- polar solvent. These small alcohols are not polar to diffuse through the lipid membranes and enter the cell. Both polar and non-polar regions on the macromolecules (e.g. proteins) of the pathogens interact with alcohol, dropping their existing interactions and establishing new ones. Proteins will change their conformations and often denature and 7
OCV Chemistry, Grade 12 University Preparation (SCH4U-04/05) Ottawa-Carleton Virtual Secondary School 2020-2021 Mr. Daniel Cho-En Lee ( daniel.cho-en.lee@ocdsb.ca ) aggregate, losing their functions. Note: 95% ethanol/propan-2-ol does not work as well as 70% here. The 95% alcohol causes a big mess of aggregates near the surface of the pathogens quickly. The big mess becomes a new protective layer! Exercise 5 . Compare the chemistry behind using soap or 70% ethanol/propan-2-ol as a hand sanitizer. In which aspects are they similar? In which aspects are they different? Wash hand with Soap Hand sanitizer 70% ethanol or 70% ethan-2-ol Summary in 20 words Soap molecule is incorporated into the lipid membrane and causes leaks Alcohol molecules penetrate the lipid membrane and disrupts intermolecular forces of the interior Similar Disables the virus Different Soap molecules displaces regular lipid molecules on the membrane Alcohol displaces regular water solvent inside the virus 8