SCH4U Lee 2.3
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OCV
Chemistry, Grade 12 University Preparation (SCH4U-04/05)
Ottawa-Carleton Virtual Secondary School 2020-2021
Mr. Daniel Cho-En Lee (
daniel.cho-en.lee@ocdsb.ca
)
While all chemical bonds are stable “energy valleys” (low chemical potential energy), some valleys
are shallower than the others. Take a look at the table below and identify which bonds are more
stable than the others. (In general, large ΔEN = stable.) Bond energy = “
how much energy input is
required to break a bond.
”
Through a chemical reaction, electrons currently trapped in a shallow valley, such as a C-C bond, a C-H bond, and O=O
bond may “fall” to an even lower energy level, such as a C=O bond and O-H bond, and release the chemical energy
(typically as heat - increased movement and vibration of molecules). We will come back to this critically important
concept in Unit 3. For now, we should know that
C-C and C-H are relatively high-energy bonds
compared to those
found in the products of their combustion reaction. Hydrocarbons are rich in chemical energy.
Refining crude oil through Fractional distillation
Every day, millions of barrels (1 barrel is about 100L) of crude oil is produced. Crude oil contains a mixture of
hydrocarbons with various sizes and chain lengths. Through a long pipeline (which frequently generates front-page
news in Canada), crude oil is transported to a refinery. An oil refinery separates hydrocarbon components based on
their different boiling points through the distillation process.
Exercise 1:
Why do some people support the construction of an oil pipeline? Why do some reject it?
Economy vs. ecology
1
OCV
Chemistry, Grade 12 University Preparation (SCH4U-04/05)
Ottawa-Carleton Virtual Secondary School 2020-2021
Mr. Daniel Cho-En Lee (
daniel.cho-en.lee@ocdsb.ca
)
How distillation works
A liquid has two components, A and B.
A’s b.p. = 100ºC
B’s b.p. = 200ºC
When we heat up the liquid to 100ºC, only A starts evaporating. The gaseous
substance A is collected separately and cooled back down (often by running
tap water) to liquid.
The boiling point of ethanol (78ºC) is lower than that of water. This property
enables the brewery industry to separate ethanol and water in a distillery.
However, home-made moonshine often contains toxic methanol, a byproduct of
fermentation. Drinking moonshine often causes methanol poisoning, leading to
blindness and even death. Since methanol has an even lower boiling point (65ºC) than ethanol, it is possible to
distill the mixture at a lower temperature to remove it first.
Extended topic:
NileRed: Making toilet paper moonshine
https://www.youtube.com/watch?v=17WjcVWw2H8
Exercise 2.
In a home-made moonshine mixture, there is methanol, ethanol and water are mixed together. The
container is heated to 80°C, while the gaseous distillate is collected and cooled back to liquid. Is this moonshine safe
to drink? Explain.
No because both methanol and ethanol boil at 80ºC. Consuming methanol causes poisoning.
An oil refinery has a tall, multi-layered fractional distillation column, through which there is a temperature gradient.
Pre-heated ~400°C crude oil (a grand mixture of hydrocarbons) enters at the bottom, where the temperature is the
highest. All but the largest hydrocarbons, which attract each other with the most intermolecular force, evaporate and
rise up to the second-last level. The temperature in the second last level is slightly lower, while all but the largest
remaining hydrocarbons evaporate and rise up to the next, higher level. As the temperature continues to drop when
hydrocarbons travel up, smaller and smaller hydrocarbons are separated from the rest. Eventually, only the smallest
hydrocarbons - the natural gases - reach the top column at around room temperature (25°C).
Fuse school: fractional distillation
https://youtu.be/PYMWUz7TC3A
2
OCV
Chemistry, Grade 12 University Preparation (SCH4U-04/05)
Ottawa-Carleton Virtual Secondary School 2020-2021
Mr. Daniel Cho-En Lee (
daniel.cho-en.lee@ocdsb.ca
)
After hydrocarbons are separated by their boiling points (which correspond to different chain-lengths), they become
useful fuels for different purposes. Larger molecules require a higher temperature to start burning (as O=O is much
more accessible while the fuels are in the gas phase) but there is also more stored chemical bond energy to harvest.
❏
Natural gases
(1-4 C) are burned in a household furnace for heating.
❏
Naphthas
(5-10 C), are burned in the internal combustion engines of cars.
Larger hydrocarbons are used for heavier vehicles such as trucks (
diesel
), airplanes (
kerosene
), and ships. Motor oil
consists of hydrocarbons that are large and stable enough to
lubricate
machine parts to prevent frictional worn-out.
Candle wax
consists of even longer-chain hydrocarbons so that it remains solid at room temperature. Finally, the
largest hydrocarbons are used to pave roads (
asphalts
).
Exercise 3.
Which of the following organic compounds may be found in car gasoline?
(a)
propane
(b)
benzene
(c)
toluene
(d) 5-pentylnonane
(e)
2,2,4-trimethylpentane
Watch: Octane number
https://youtu.be/vL8Uj2CNWtI
3
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Chemistry, Grade 12 University Preparation (SCH4U-04/05)
Ottawa-Carleton Virtual Secondary School 2020-2021
Mr. Daniel Cho-En Lee (
daniel.cho-en.lee@ocdsb.ca
)
Internal combustion engine (animated .gif)
https://upload.wikimedia.org/wikipedia/commons/d/d7/4-Stroke-Engine-with-airflows.gif
Octane number (89, 91…)
As gasoline is sprayed into an internal combustion engine, a spark ignites the fuel and the combustion reaction
proceeds to produce CO
2
, H
2
O, and energy. Ideally, all fuels react with oxygen at the same time when the combustion
chamber compresses the fuel-oxygen mixture. The hot gas reaction product then pushes the piston up to drive the
vehicle. However, since gasoline is a mixture of hydrocarbons, some fuels ignite before the engine’s compression
phase is complete. A premature ignition creates an engine knock (vibration), reduces fuel efficiency and may cause
engine damage.
The petroleum industry uses “octane number” to indicate how well a hydrocarbon fuel ignites together.
Here is a list:
https://chem.libretexts.org/@api/deki/files/30450/e10687fa219cb79e41c16f513ea25c39.jpg?revision=1
2,2,4-trimethylpentane (an isomer of octane, called “isooctane” in the industry) defines
octane number 100 (less engine knock), while n-heptane defines octane number 0 (more
engine knock). Ethanol, which may be produced as a biofuel, has an octane number of 108
(even less engine knock). The petroleum industry frequently mixes ethanol in gasoline to
raise the octane number and to “go green.” Note that this does not mean ethanol actually
contains more chemical energy per unit volume.
Until the 1970s, “tetraethyl
lead” (4 ethane chains bonded to lead) was added to gasoline to
raise octane number. This created widespread lead pollution in the society, causing cognitive
developmental problems in children. It is still common to see gas stations slapping an
“
unleaded
” sticker on their gasoline pump. Being unleaded does not mean a high octane number (in fact the industry
has to think of other ways to raise the octane number).
Exercise 3.
Next time you visit a gas station, pay attention to (1) the octane numbers, (2) ethanol content, (3)
“unleaded” sticker.
Extended topic (highly recommended!)
Clair Patterson’s clean room and the battle on banning tetraethyllead
http://www.documentarymania.com/player.php?title=The%20Clean%20Room
Halogenated Hydrocarbons
(old: Alkyl halides)
Just like H, halogens (F, Cl, Br, I) require one electron to fill their respective electron
shell. Many hydrocarbons have one or more H replaced by halogens. Unlike H,
4
OCV
Chemistry, Grade 12 University Preparation (SCH4U-04/05)
Ottawa-Carleton Virtual Secondary School 2020-2021
Mr. Daniel Cho-En Lee (
daniel.cho-en.lee@ocdsb.ca
)
halogens are larger and more electronegative, giving halogenated hydrocarbons different intermolecular interactions.
When attached to hydrocarbons, halogens are named like side chains (e.g. methyl-)
❏
F = fluoro-
❏
Cl = chloro-
❏
Br = bromo-
❏
I = iodo-
Exercise 1
. Name the molecule on the right.
2-chloro-2-fluoro-5-methylhexane
Exercise 2.
Draw an ortho-dichlorobenzene, a meta-dichlorobenzene, and a para-dichlorobenzne. And supply the
correct IUPAC names. What is their chemical (molecular) formula?
C
4
H
6
Cl
2
ortho-dichlorobenzene = 1,2-dichlorobenzene
meta-dichlorobenzene = 1,3-dichlorobenzene
para-dichlorobenzene = 1,4-dichlorobenzene
Case study:
Chloro
fluoro
carbons
(small alkane with -H replaced by -F and -Cl)
In the latter half of the 20th century, there was a widespread fear about a continent-sized “hole” of the ozone (O
3
)
layer of the stratosphere, specifically over Antarctica. Ozone is capable of absorbing high-energy ultraviolet radiation
from the sun before it reaches us. UV ray is energetic enough to lift bond electrons completely out of the energy
valley. The broken bond creates almost filled orbitals. Imagine a stable 3s
2
3p
6
becomes 3s
2
3p
5
! (If the bond electron
escape completely, a charged ion is left behind. Such a high-energy radiation is called “ionizing radiation.)
Back then,
c
hloro
f
luoro
c
arbons (CFCs) were widely produced as a coolant, a solvent, and a propellant for hair spray
and asthma inhaler. However, due to its non-polar nature and low molar mass, CFCs will remain a gas and rise up in
the atmosphere. The UV ray reaching the stratosphere is capable of breaking a C-Cl bond, producing a free-flying Cl
atom. This Cl atom is more often called a “
free radical
” and is written as
Cl•.
(By definition, a
free radical
is
atom/ion with an unpaired electron - though this Cl
•
is specifically missing one e
-
to fill the last orbital of the third
shell, [Ne] 3s
2
3p
5
). The very reactive Cl atom (Cl
•
) can eventually break down 2 ozone molecules to three O=O and
regenerate itself perpetually. Cl
•
is a catalyst of the reaction 2O
3
→ 3O
2
.
5
OCV
Chemistry, Grade 12 University Preparation (SCH4U-04/05)
Ottawa-Carleton Virtual Secondary School 2020-2021
Mr. Daniel Cho-En Lee (
daniel.cho-en.lee@ocdsb.ca
)
In the midst of the ozone hole panic, CFCs were banned in the mid 90s. Finally, in recent years there are signs that
the ozone hole has stopped growing and is actually shrinking.
Watch
: Seeker: What Ever Happened To The Hole In The Ozone Layer?
https://youtu.be/0ZfBgjUnXIs
Extended topic:
Chlorofluorocarbons (CFC) depletes the ozone layer
https://www.youtube.com/watch?v=aU6pxSNDPhs
CFC as a greenhouse gas (3rd worst after CO
2
and methane)
https://www.globalchange.gov/browse/indicators/annual-greenhouse-gas-index
Case study: DDT
(
Di
chloro
di
phenyl
tri
chloro
ethane, not an IUPAC name)
DDT was once
the
pesticide. It did not appear to be toxic to humans at first, but it
effectively killed bugs, such as mosquitos and flies. During World War II, DDT started
to be sprayed in regions plagued by malaria, typhoid fever, and cholera. The inventor
of DDT received a Nobel Prize in 1948.
Then scientists discovered that DDT accumulated in the
body of animals. DDT is quite a non-polar compound so that it does not dissolve in
water to be excreted. Being a recent synthetic compound, it cannot be broken down by
existing enzymes. As a result, DDT molecules gather in animal fat tissues. It takes about
8 years for the DDT level to drop by half. DDT also accumulates up the food chain, so
that the top predators have the highest DDT level. DDT is linked to the thinning of the
egg shells of lake gulls and eagles, causing the eggs to break before hatching. There is
also evidence that DDT is linked to male cancer by mimicking the male hormone
6
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Chemistry, Grade 12 University Preparation (SCH4U-04/05)
Ottawa-Carleton Virtual Secondary School 2020-2021
Mr. Daniel Cho-En Lee (
daniel.cho-en.lee@ocdsb.ca
)
(shown on the right).
The US and Canada banned DDT in the 70s. Since then, the DDT level in Great Lake fish and birds have reduced and
the bird's population has recovered. However, DDT is still used in developing countries to combat the aforementioned
diseases.
Footage: Spraying DDT on happy children
https://youtu.be/GIxMvUZVRDE
Case study: PCBs
(Polychlorinated bi
phenyl
)
PCBs are a group of chlorinated "benzene doublets" that were
manufactured as industrial lubricant, coating agent, and
solvent. Like DDT, PCBs are quite non-polar and, being
synthetic, there is no evolved enzyme to break them down
quickly. PCBs also end up in animal fat tissues and accumulate
up the food chain.
Worse than DDT, PCBs are quite toxic to humans, damaging the
nervous system (incl. brain), the reproductive system, and the
immune system. Those who are poisoned by PCBs develop
chloracne on the skin. There have been a couple of large-scale
PCBs poisoning as PCBs made their way into consumer oil. While PCBs were banned in the late 1970s, old equipment
could still contain PCB. Recently, scientists have developed microbes that have enzymes to break down PCBs.
Case study: Dioxins
Dioxins are a group of byproduct compounds produced from burning organic compounds,
such as plastics, that contain chlorine. The common feature of dioxins are two central
benzene rings connected by two oxygens, while the number of chlorines on the sides vary. The most toxic varient is
2,3,7,8-t
etrac
hlorod
ibenzod
ioxin (TCDD). A few decades ago TCDD was a highly feared pollutant through the damages
it caused in experimental animals. TCDD and is still classified as group-1 carcinogen today. (Next time when you smell
people burning plastic, better stay away!)
Exercise 5.
What are the common structural features of DDT, PCBs, and Dioxins? Do you think dioxins could be found
7
OCV
Chemistry, Grade 12 University Preparation (SCH4U-04/05)
Ottawa-Carleton Virtual Secondary School 2020-2021
Mr. Daniel Cho-En Lee (
daniel.cho-en.lee@ocdsb.ca
)
in fat tissues? Do you expect high levels of dioxins may be found in top predators (e.g. eagles, killer whales)? Explain.
(Almost think about Polyaromatic hydrocarbons, PAH - they have similar properties and behaviours.)
Extended topics
: Agent orange
The New York Times: The Dark Shadow of Agent Orange
https://youtu.be/uzvTB0mOS0w
Addition Reactions of Alkene
(hydrogenation, hydration, halogenation)
Previously we touched on the hydrogenation of alkene by
combining H
2
and an alkene, such as ethene or a cis-
fat. The π bond may also be broken when the
alkene reacts with an
H-X acid
(HF, HCl, HBr, HI), an
X-X
(F
2
, Cl
2
, Br
2
, I
2
), and even H
2
O, with suitable conditions
and catalyst in each case.
The common theme of hydrogenation, hydration, and
halogenation is that a small molecule is added to the main
reactant. Therefore, we call these “
addition reactions
.”
The reverse reaction, where an alcohol loses a water, or a halogenated alkane loses H-X or X-X to form an alkene, are
called “
elimination reactions
.” Here a small molecule is eliminated from the main reactant.
Which isomer product is preferred?
Consider the addition reaction between propene and HCl. There will be
two possible products: 1-chloropropane or 2-chloropropane. One takes
up 70% of the product mixture while the other 30%. We will have to
rewind the reaction a bit to explain why. Right before the Cl
-
(or Cl δ
-
,
if it has not dissociated) is added, it could be attracted to either C
1
(first from right) or C
2
.
8
OCV
Chemistry, Grade 12 University Preparation (SCH4U-04/05)
Ottawa-Carleton Virtual Secondary School 2020-2021
Mr. Daniel Cho-En Lee (
daniel.cho-en.lee@ocdsb.ca
)
For high school, we can simplify the reaction mechanism as such: the local bonds connected to C
1
and C
2
decide their
partial charge. C
1
is bonded two =C, -H, -H while C
2
is bonded to =C, -C, and -H. There will be no dipoles
generated from =C, while each C-H will make C more δ
-
. Since C
1
has one more -H than C
2
, C
1
has a
stronger δ
-
than C
2
. Consequently, the H
+
of HCl will be more likely added to C
1
rather than C
2
. Therefore, 2-
chloropropane is the preferred product over 1-chloropropane.
Markovnikov’s rule
When a HX is added to an alkene, the H gets attached to the carbon with more H substituents, and the X gets
attached to the carbon with more C substituents. (The ric
h
get ric
h
er.)
[Ignore this paragraph if this is your last chemistry course.] The
actual reaction is: (1) A π bond electron over C=C is lost to the
pretty significant δ
+
H of HCl due to electrostatic attraction. (2) The
new paired electrons (a bond) now exists between the other C and the H
of HCl. The new C-H bond is made right here. (3) The bond between H and
Cl is broken and -Cl leaves with both bond electrons, becoming Cl
-
. (4) C
2
on the alkene is more likely than C
1
to
donate that electron from its share of the π bond. This is because the result of that electron loss will
leave a positive charge, a carbo
cation
. The neighbours of C
2
are together less δ
+
than those of C
1
, and can
better stabilize the carbocation. (5) Finally, the C
2
carbocation attracts the Cl
-
and the C
2
-Cl bond forms.
Exercise 6
. Predict the major product of 3-ethylpent-1-ene + HBr.
2-bromo-3-ethylpentane
Exercise 7
. Complete the following reactions with IUPAC names for each organic compound (it might help to
translate names to structures first). If there are more than one possible products, only show the primary product in
9
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Chemistry, Grade 12 University Preparation (SCH4U-04/05)
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Mr. Daniel Cho-En Lee (
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)
each case.
(a)
(Z)-but-2-ene (Z = cis) + H
2
→
n-butane
(b)
ethene + Cl
2
→
1,2-dichloroethane
(c)
pent-1-ene + HBr →
2-bromopentane
(d)
(E)-but-2-ene (E = trans) + HBr →
2-bromobutane
The reverse reaction of an addition reaction is called an
elimination reaction.
For example, when an HCl leaves 2-
chloropropane, propene is produced. Simply reverse the arrow of the addition reaction.
Kahoot!
10
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Using bond energies, calculate the bond dissociation energy of the O-F bond in OF7.
Average Bond Energies (kJ/mol)
Single Bonds
Multiple Bonds
pt
N-H
391
149
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614
432
565
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839
495
745
1072
607
418
941
pt
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160
208
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272
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175
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295
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200
pt
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243
S-H
347
N-O
201
S-F
327
N=N
N N
253
S-CI
S-Br
467
413
347
305
358
C-H
146
218
C--C
C--N
C-O
C--F
C-CI
C-Br
O-O
891
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C-N
S-S
266
190
203
O-F
615
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340
393
360
452
485
O-I
一
234
Si-Si
339
276
Si-H
Si-C
Si-O
e F-F
154
253
240
259
F-CI
F-Br
Cl-CI
C-S
237
239
218
193
Cl--Br
Br--Br
*C==
O(in CO,) - 799
O-F bond dissociation energy:
kJ mol
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nything
%3D
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Rank the elements or compounds in the table below in decreasing order of their boiling points. That is, choose 1 next to the substance with the highest boiling point, choose 2 next to the substance with the next highest boiling point, and so on.
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Lewis structure of H2S. Any polar bonds in molecule? Polar or non polar?
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Resonance a):
C1
Resonance b):
C1
C2
03
C4
C5
06
C2
03
C4
C5
06
Resonance c):
C1
C2
03
C4
C5
06
Resonance d):
C1
C2
03
C4
C5
06
When examining the Lewis structures of organic molecules, to determine the location a reaction will occur, a chemist must identify the
sites of maximum and minimum electron density, which is often emphasized by showing the formal charge on the atoms. The ability to
quickly recognize the presence or absence of formal charges on atoms is an important skill. You should be able to recognize bonding
around the common elements in organic chemistry, and determine the formal charge on the atom based on the number of bonds. The
key elements to recognize include carbon, nitrogen, phosphorous, oxygen, sulfur and the halides. For every one of these elements
there is a pattern of bonds and lone pairs which will allow rapid determination of formal charge without going through the exercise
shown below in determining the formal charge on the nitrogen atom in diethyl amine:…
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Calculate the enthalpy change for the reaction shown below between ammonia and
phosgene to produce urea and HCI. Use the bond-dissociation energies listed in the
table.
Bond
H-CI
H-N
C-CI
C-N
CI
+ 2 NH3
AHBDE
(kJ/mol)
432
339
397
748
AHrxn = +444 kJ/mol
AHrxn= -888 kJ/mol
AHrxn= -444 kJ/mol
AHrxn= +888 kJ/mol
.C.
HẠN-“NH, * 2 H-CI
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I only need part C
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14.
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ELECTRONIC STRUCTURE AND CHEMICAL BONDING
Predicting deviations from ideal bond angles
Consider the bromate (BrO3)
anion.
What is the central atom? Enter its emical symbol.
How many lone pairs are around the central atom?
What is the ideal angle between the bromine-oxygen
bonds?
Compared to the ideal angle, you would expect the
actual angle between the bromine-oxygen bonds to
be ...
0
口。
(choose one)
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H
4 H.
H:Y:H
H
The Lewis representation above depicts a reaction between hydrogen (blue) and a main-group element from group
(red).
| bond(s)
In this representation, each Y atom needs
with atoms of H.
|electron(s) to complete its octet, and gains these electrons by forming
unshared electron pair(s) and
|bonding electron pair(s) in the product molecule.
There are
The bonds in the product are|
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