ECE_331-Post_lab_3 (1)

Looking to see if I have the concept right . Thank you

an empty evaporating dish weighs 25.1295 g. When unknown mixture is added, the dish and mixture weigh 29.9745 g. After removing the Fe with a magnet, the dish and remaining mixture weigh 28.2374 g. After extraction of the NaCl and drying the remaining solid, the dish and final mixture weigh 26. 8928 g. Calculate the mass and mass percent of Fe, NaCl, and SiO2 in the sample. Show all your work.

c. The table below shows characteristics of two dopants added in Czochralski growth processes of crystalline silicon. In both, a mass M of the dopant was added to 1 kg of silicon. Growth 01 Silicon mass Dopant mass Dopant atomic weight (molar mass) Distribution coefficient (ka) 1 kg M 74.9 g/mol 0.3 1.0 x 10¹5 cm- Growth 02 1 kg M 31 g/mol 0.36 Doping concentration 22 As shown in the table above, we got doping of 1.0 x 10¹5 cm3 for the first process (Growth 01), what is the doping concentration that we will get in the second process (Growth 02) ? A) 0.5 x 10¹5 cm-3 B) 2.0 x 10¹5 cm-³ Answer C) 2.9 x 10¹5 cm-3D) 3.4 x 10¹4 cm-3

The coefficients needed to balance the second step of the Ostwald process, __ NO. + __ O 2 -----> __ NO 2 , are

If the cells were spread out into a thin layer that was a single cell thick, what would be the total surface area ( in square meters) for the top side of the cell layer ? Be sure your answer has the correct number of significant digits? ……m^2pls help me

Bb.30.   What will prevent iron from interfering with the aluminum measurements?

4. A 0.200-g sample of pyrolusite is analyzed for manganese content as follows: 50.0 ml of 0.100 M solution of ferrous ammonium sulfate was added to reduce the MnO₂ to Mn²+. After reduction is complete, the excess ferrous iron is titrated in the acid solution with 0.0200 M KMnO4, requiring 15.0 ml. Calculate the %Mn3O4 (MW = 228.812) of the sample. The reaction between Fe²+ and MnO₂ is: MnO₂ + 2Fe²+ + 4H+ → Mn²+ + 2Fe³+ + 2H₂O The reaction between Fe²+ and MnO4 is: 5Fe²+ + Mn0 +8H+ → 5Fe³+ + Mn²+ + 4H₂O

Resistance of 0.2 M solution of an electrolyte is 50 0. The specific conductance of the solution is 1.3 S m-1. If resistance .1 of the 0.4 M solution of the same electrolyte is 260 D, its molar conductivity is 6.25 x 10-4 S m2 mol-1 .a O 62.5 S m2 mol-1 .b O 625 x 10-4 S m2 mol-1 .c O 6250 S m2 mol-1 .d O

Hi there! I had recently checked that one of the questions I showed seemed to be incomplete, my apologies for doing so. I have a picture of the question just to make sure that it's not incomplete. Thank you very much for the support as well.

Significance of your results: Titanium is also commonly anodized, but does not need to be dyed to achieve colored surface layers. Instead, the color comes from thin-film refraction within the oxide layer - the color is characteristic of the thickness of the oxide layer. Ti²+ (aq) + 2e-Ti (s) E° = -1.60 V TiO₂ (s) + 4 H+ (aq) + 4 e-Ti (s) + H₂0 (1) E° = -1.076 V a. What is the half-reaction at the anode for the anodization of titanium? b. Under standard conditions, what is the smallest potential you would need to provide in order to anodize titanium?