Reading Check_Unit10

Highest acidity Lowest acidity Answer Bank CH. H- -0-CH3 H3C CH, H3C CH3 H. H H H. H3C CH, H- -CH, H.

d. 1. LAH, THF; 2. dil. HCl C(CH3)3 -C(CH3)3 f. CH3 g. 1. BB13; 2. water „NH2 H3C PH 5, NaBH,CN, МеОН i. excess HBr j. 1. BuLi, THF, -78 C; 2. PHCH,Br; 3. HgCl2, HCl, water k. CH3 1. LAH, THF; 2. dil. HC1, -D 1. cat. TSOH, HOCH,CH,OH;, 2. Ra Ni, E1OH; 3. HCl/water

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Help 100% 2 Tue 4: Public Health Ch x * HSC 258 - Major Projec X * Mind Tap - Cengage Lea X C The Illustration To The d=55750828934189288909969212&EISBN=9781305657571&id=1061392007&nbld%3D21... * O TO Q Search this co References Use the References to access important values if needed for this question. For the following reaction, 6.43 grams of sulfur dioxide are mixed with excess oxygen gas . The reaction yields 6.30 grams of sulfur trioxide . sulfur dioxide(g) + oxygen(g) sulfur trioxide(g) grams What is the ideal yield of sulfur trioxide? What is the percent yield for this reaction? Submit Answer

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Experiment-A8: Spectrophotometry of Cobalt( Pre-laboratory Exercises 1. (a) Define Beer's law and give the mathematical equation (specify each symbol in the equation). concentration of achemical Solution Beer's Law states that the in the following A = Ebc is directly proportional to its absorption of light & can be calculated formula (b) Briefly explain what Beer's plot is and how do you obtain the Beer's constant (k) from the plot. is a straight line with _ay-intercept Beer's plot of zero & a slope of ab oreb. It represents the absorptunity the length Absorbance 8 can be calculate by multiplying Constant by the path length then dinding that value by the 2. The following solutions are prepared from 0.200 MNICI, and their absorbance measured at 725 nm. Solution # 1 2 3 4 5 Volume (mL) of 0.200 M NiCh 1.00 2.00 3.00 4.00 pride 5.00 Volume (mL) of H₂O 4.00 3.00 2.00 1.00 0.00 INICI] (a) Calculate the molar concentration of NiCl₂ in each solution 1-5. Absorbance at 725 nm 0.105 0.210 0.315…

7. Don believes that fewer than one-third of the students at his college hold part-time jobs while in school. To investigate this, he randomly surveyed 116 students and found that 32 students held part-time jobs. a. ( - Provide a 90% confidence interval for the population proportion of students that hold a part-time job. b. 1 (a). ;Give the correct interpretation of the interval in part c. Extra Credit: Does this interval support Don's claim? Why?

8) B) B) 3. Observation of burning match or splint_ What caused the change in the burning match or splint? 4- 5. Type of reaction: Na₂CO3(s) +. F. Hydrogen Peroxide Reactants 1. Appearance of Reactants b. bleaching a stain ΚΙ c. burning a match a. H,O2(aq) 3. ___ H,O,(aq) 4. Type of chemical reaction: Questions and Problems Q1 What evidence of a chemical reaction might you see in the following cases? Refer to Table 7.1. 70.000 a. dropping an Alka-Seltzer tablet into a glass of water b. HCl(aq). d. rusting of an iron nail Q2 Balance the following equations: . Mg(s) + Al(s) + H₂O(1) + O₂(g) HCl(aq) Chemical Reactions and Equations 83 CO₂(g) + H₂O(7) +_ NaCl(aq) 0₂ (8) 2. Evidence of a Chemical Reaction H₂(g) + MgCl₂(aq) Al₂O3(s)

← Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic steps. Be sure to account for all bond-breaking and bond-making steps. HH H H HO: :O: Select to Add Arrows H neutralizing workun Li → Li O Select to Add Arrows 1 Н HAIGH Al. н 'Н Li HO: :0: Select to Add Arrows Li Ⓒ Li O H Li O I Select to Add Arrows I H HI | I I I Problem 39 of 40 Please select a drawing or reagent from the question area Submit

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C030 BY NC SA S. Alvanipour, Y, Gedeon, G. Zoorob, CC BY-NC-SA 4.0 B. Determination of unknown acid concentration Unknown Acid number Volume of acid used (ml) Initial buret reading (mL) Final buret reading (ml) Volume of NaOH used (ml) Molarity of NaOH Trial 1 Unknown Quid 25.0ml Ome 12.4ml 12.4ml -10m Calculated molarity of HCI (M) Show a sample calculation of HCI molarity AVERAGE MOLARITY OF Unknown HCI Show a sample calculation of NaOH molarity: Trial 2 Unknown 25-am omo 12.5ml 12.5ml -lom Trial 3 Unknown af 20% ome come 12.630 12.6ml -tom

Using the data provided in Table 1 to fill in the blanks on table 2

Week 8-1 X + " https://app.101edu.co 79°F Mostly cloudy Substance NH:(9) HCI (g) NH.CI (S) Chapter 5 x 00 5.3 The Fu X 00 Quiz 5.1 to x 0o DESU Calc X 2 W " # 3 * E $ 4 27 O R 12 Calculate AS for NH3(g) + HCI(g) → NH4Cl(s). % 5 " Search 40 6 الت " S* (J/mol-K) 192.5 186.7 94.6 4- & 7 YIL M Log In | Fe X Aktiv Chen X U Question 8 of 23 4+ 8 DA hp 9 ► 11 M ) IL O O Flashcards X O A4 P C { Photograp X A + L A = O Welcome X Ⓒ P } 1 4 7 +/- G prt sc 。 2 5 8 delete backspace B Log In | Fe X + J/mol K 3 6 9 0 home . num lock x 1 end G 7 home

Below you will find five reaction products (labeled product 1, product 2, etc.), but you will only find four reaction schemes. Your job is to match the reaction scheme with the correct product. Simply fill in the blank with the product number (i.e. 1,2,3,4, or 5). Then, state the regio-control that governs the reaction (i.e. Markovnikov or anti-Markovnikov). If the reaction does not have any regio-control then enter none. OH X Product 1 iocontrol: Product 2 1. Hg(OAc)2, H₂O 2. NaBH4 $ -OH do % Product 3 OH to 4- Product 4 OH OH Product 5 700 hp

Complete the following reactions: a. Mg H,C-d CH, Et,0 b. H,C KCN nota CH,0 Na HC CH– Br d. H,C KMNO H,C OH он CH, KMno, f. HI H,C_0_CH, CH, g. NH, H,C

H30* d. [1] CH3OH, H* CH30 HO. MgBr е. [2] (2 equiv) [3] H20 HO [1] SOCI, f. [2] CH3CH,CH,CH,NH2 [3] LIAIH4 [4] H2O

What is the missing reactant? Select one: A. I B. III C. iv OD ii CH-8-001 MgCl LDA 78 C THE ILL IV ? ())-01-2-0031,

Complete the table.

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السلم Br HO 1. NaBH4 (0.25 eq.), H₂O 2. 1. 1. MgBr (1 eq.), CH3CH₂OCH₂CH3 MgBr (xs), Et₂O 2. DCI, D₂O Br . Mgº (1 eq.) 2. CH₂CH₂OCH₂CH3 MgBr (excess) CH3CH₂OCH₂CH3

40 mg of sodium hydroxide is required to saponify 1gm sample, this means that (MW of NaOH= 40 g/mole, MW of KOH is 56g/mol) O a. saponification value equals 56 O b. acid value equals 40 O C. Acid value equals 56 O d. saponification value equals 40