Pre-laboratory Exercises 1. (a) Define Beer's law and give the mathematical equation (specify each symbol in the equation). Beer's Law states that the concentration of a chemical solution is directly proportional to its absorption of light & can be calculated in the following formula A= EbC ay-htercept (b) Briefly explain what Beer's plot is and how do you obtain the Beer's constant (k) from the plot. Beer's plot is a straight line with the absorptunty of zero & a slope of ab oreb. It represents Absorbance 8 can be calculate by multiplying Constant by the path length then dinding that value by the length 2. The following solutions are prepared from 0.200 MNICI, and their absorbance measured at 725 nm. Solution # 1 2 3 4 5 Volume (mL) of 0.200 MNICI 1.00 2.00 3.00 4.00 5.00 Volume (mL) of H-O 4.00 3.00 2.00 1.00 0.00 [NiCh] Absorbance at 725 nm (a) Calculate the molar concentration of NiCl₂ in each solution 1-5. 0.105 0.210 0.315 0.420 0.525

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**Experiment A8: Spectrophotometry of Cobalt(II) Chloride**

### Pre-laboratory Exercises

1. **(a) Define Beer’s law and give the mathematical equation (specify each symbol in the equation).**
   - **Beer’s law states** that the concentration of a chemical solution is directly proportional to its absorption of light and can be calculated by the following formula:  
     \( A = \epsilon bc \)  
     - \( A \) = Absorbance  
     - \( \epsilon \) = Molar absorptivity  
     - \( b \) = Path length  
     - \( c \) = Concentration

**(b) Briefly explain what Beer’s plot is and how you obtain the Beer’s constant (k) from the plot.**
   - **Beer's plot is a straight line** with a y-intercept of zero and a slope of \( \epsilon bc \). It represents the relationship of absorbance \( A \) and concentration. Absorbance \( A \) can be calculated by multiplying the absorptivity constant by the path length, then dividing that value by the length.

2. **The following solutions are prepared from 0.200 M NiCl\(_2\), and their absorbance measured at 725 nm.**

| Solution # | Volume (mL) of 0.200 M NiCl\(_2\) | Volume (mL) of H\(_2\)O | [NiCl\(_2\)] | Absorbance at 725 nm |
|------------|-----------------------------------|-------------------------|-------------|----------------------|
| 1          | 1.00                              | 4.00                    |             | 0.105                |
| 2          | 2.00                              | 3.00                    |             | 0.210                |
| 3          | 3.00                              | 2.00                    |             | 0.315                |
| 4          | 4.00                              | 1.00                    |             | 0.420                |
| 5          | 5.00                              | 0.00                    |             | 0.525                |

**(a) Calculate the molar concentration of NiCl\(_2\) in each solution 1 – 5.**
Transcribed Image Text:**Experiment A8: Spectrophotometry of Cobalt(II) Chloride** ### Pre-laboratory Exercises 1. **(a) Define Beer’s law and give the mathematical equation (specify each symbol in the equation).** - **Beer’s law states** that the concentration of a chemical solution is directly proportional to its absorption of light and can be calculated by the following formula: \( A = \epsilon bc \) - \( A \) = Absorbance - \( \epsilon \) = Molar absorptivity - \( b \) = Path length - \( c \) = Concentration **(b) Briefly explain what Beer’s plot is and how you obtain the Beer’s constant (k) from the plot.** - **Beer's plot is a straight line** with a y-intercept of zero and a slope of \( \epsilon bc \). It represents the relationship of absorbance \( A \) and concentration. Absorbance \( A \) can be calculated by multiplying the absorptivity constant by the path length, then dividing that value by the length. 2. **The following solutions are prepared from 0.200 M NiCl\(_2\), and their absorbance measured at 725 nm.** | Solution # | Volume (mL) of 0.200 M NiCl\(_2\) | Volume (mL) of H\(_2\)O | [NiCl\(_2\)] | Absorbance at 725 nm | |------------|-----------------------------------|-------------------------|-------------|----------------------| | 1 | 1.00 | 4.00 | | 0.105 | | 2 | 2.00 | 3.00 | | 0.210 | | 3 | 3.00 | 2.00 | | 0.315 | | 4 | 4.00 | 1.00 | | 0.420 | | 5 | 5.00 | 0.00 | | 0.525 | **(a) Calculate the molar concentration of NiCl\(_2\) in each solution 1 – 5.**
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