Tiny samples of aqueous solutions are sketched below, as if under a microscope so powerful that individual molecules could be seen. (The water molecules are not shown.) The two substances in each sample can interconvert. That is, each kind of molecule can turn into the other. The equilibrium constant K for each interconversion equilibrium is shown below the sketch. Decide whether each solution is at equilibrium. Coo yes 000 8 At equilibrium? yes 1 K = = = = 8 9 no K=9 At equilibrium? O no At equilibrium? O yes K= 4 yes no 3 K= 2 At equilibrium? no X

Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter15: Principles Of Chemical Reactivity: Equilibria
Section15.3: Determining An Equilibrium Constant
Problem 15.3CYU: A solution is prepared by dissolving 0.050 mol of diiodocyclohexane, C5H10I2, in the solvent...
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Tiny samples of aqueous solutions are sketched below, as if under a microscope so powerful that individual molecules could be seen. (The
water molecules are not shown.)
The two substances in each sample can interconvert. That is, each kind of molecule can turn into the other. The equilibrium constant K for
each interconversion equilibrium is shown below the sketch.
Decide whether each solution is at equilibrium.
Coo
yes
000
8
At equilibrium?
yes
1
K = = = = 8
9
no
K=9
At equilibrium?
O no
At equilibrium?
O yes
K=
4
yes
no
3
K=
2
At equilibrium?
no
X
Transcribed Image Text:Tiny samples of aqueous solutions are sketched below, as if under a microscope so powerful that individual molecules could be seen. (The water molecules are not shown.) The two substances in each sample can interconvert. That is, each kind of molecule can turn into the other. The equilibrium constant K for each interconversion equilibrium is shown below the sketch. Decide whether each solution is at equilibrium. Coo yes 000 8 At equilibrium? yes 1 K = = = = 8 9 no K=9 At equilibrium? O no At equilibrium? O yes K= 4 yes no 3 K= 2 At equilibrium? no X
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