Experiment 18 Report

Calculate the pH of a weak base solution (quadratic equation). Calculate the pH of a 0.0302 M aqueous solution of diethylamine ((C2H5)2NH, K₁ = 6.9×10-4) and the equilibrium concentrations of the weak base and its conjugate acid. pH [(C2H5)2NH] equilibrium [(C2H5)2NH2* ]equilibrium || || || = ΣΣ

Part A The chemical 5-amino-2,3-dihydro-1,4-phthalazinedione, better known as luminol, is used by forensic scientists in analyzing crime scenes for the presence of washed-away blood. Luminol is so sensitive that it can detect blood that has been diluted 10,000 times. A basic solution of luminol is often sprayed onto surfaces that are suspected of containing minute amounts of blood. The forensic technician at a crime scene has just prepared a luminol stock solution by adding 15.0 g of luminol into a total volume of 75.0 mL of H2O. What is the molarity of the stock solution of luminol? Express your answer with the appropriate units. Luminol has a molecular weight of 177 g/mol. • View Available Hint(s) HẢ molarity of luminol solution = Value Units Submit Part B Before investigating the scene, the technician must dilute the luminol solution to a concentration of 6.00x10-2 M. The diluted solution is then placed in a spray bottle for application on the desired surfaces. How many moles of…

Submit correct and complete solutions. Please provide Explanation. Provide step-by-step detailed explanations.

Calculate the pH of a 0.295 M solution of ethylenediamine (H₂NCH,CH,NH₂). The pKa values for the acidic form of ethylenediamine (HNCH,CH,NH) are 6.848 (pKa1) and 9.928 (pKa2). pH = Calculate the concentration of each form of ethylenediamine in this solution at equilibrium. [H2NCH2CH2NH₂] = [H2NCH,CH,NH] = [HNCH,CH,NH3] = M M M

Predict and complete two reactions of a compound with water. Use a single arrow to indicate that the reaction proceeds to completion and a double arrow to indicate an equilibrium. Phases (liquid, aqueous, etc.) are optional. Reaction A: H,S + H,O Reaction B: CaH, + 2H,0

Consider the following data on some weak acids and weak bases: acid base K. Kb name formula name formula HCH,CO, 1.8 × 10¬ ethylamine C2H5NH2|6.4 × 10 acetic acid 8 3.0 x 10 4 hypochlorous acid HCIO methylamine CH3NH2 |4.4 × 10 Use this data to rank the following solutions in order of increasing pH. In other words, select a 'l' next to the solution that will have the lowest pH, a '2' next to the solution that will have the next lowest pH, and so on. solution pH 0.1 M NaCIО choose one 0.1 М КCН3СО2 choose one 0.1 M C2H5NH3CI choose one 0.1 М CH3NH3Br choose one

Calculate the pH of a 0.105 M solution of ethylenediamine (H,NCH,CH,NH,). The pKa values for the acidic form of ethylenediamine (H NCH,CH,NH}) are 6.848 (pKa1) and 9.928 (pK2). pH = Calculate the concentration of each form of ethylenediamine in this solution at equilibrium. [H,NCH,CH,NH,] = M [H,NCH,CH,NH] = М [H;NCH,CH,NH†] =

Calculate the pH of a 0.365 M solution of ethylenediamine (H,NCH, CH, NH,). The pKa values for the acidic form of ethylenediamine (H†NCH,CH,NH†) are 6.848 (pKa1) and 9.928 (pKa2). pH =| 11.25 Calculate the concentration of each form of ethylenediamine in this solution at equilibrium. [H,NCH,CH,NH,] = M [H,NCH,CH,NH)= M [HNCH,CH,NH;) = M

Explain why the pH of a 0.25 M solution of formic acid (HCO2H) has a lower pH than a solution that is 0.25 M in both formic acid and sodium formate (NaCO2H). Please include chemical reactions.

Do not give handwriting solution.

The amount of tartaric acid is responsible for the tartness of wine and controls the acidity of the wine.  Tartaric acid also plays a very significant role in the overall taste, feel and color of a wine.   Tartaric acid is a diprotic organic acid The chemical formula for tartaric acid is C4H6O6 and its structural formula is HO2CCH(OH)CH(OH)CO2H.   A 50.00 mL sample of a white dinner wine required 21.48 mL of 0.03776 M NaOH to achieve a faint pink color.  Express the acidity of the wine in terms of grams of tartaric acid, H2C4H4O6 (M. M.  =  150.10) per 100 mL of wine.  Assume that the two acidic hydrogens are titrated at the end point. MM H2C4H4O6 = 150.10 MM NaOH = 40.00 Below is the balanced chemical equation for this titration.

Question Completion Status: The structure of aspirin is shown below. Look at the carbon atom marked with the arrow. Which functional group is this carbon atom a part of? You may find it helpful to refer to Table 15.5 in the Silberberg textbook, which shows the names and representative structures of the common functional groups in organic compounds. H QUESTION 1 H H O alcohol ether O ketone O carboxylic acid Oester H H3C QUESTION 2 The structure of aspirin is shown below. Look at the oxygen atom marked with the arrow. Which functional group is this oxygen atom a part of? You may find helpful to refer to Table 15.5 in the Silberberg textbook, which shows the names and representative structures of the common functional groups in organic compounds. T H H₂C OH O alcohol Oether O ketone O carboxylic acid Oester Look here to answer Question 1! OH Look here to answer Question 2! QUESTION 3 Salicylic acid, one of the starting materials that you will use in the synthesis of aspirin, has…

In the following acid - base reactions, a) Draw Lewis structures of the reactants and the products. b) Determine which species are acting as electrophiles (acids) and which are acting as nucleophiles (bases). c) Use the curved - arrow formalism to show the movement of electron pairs in these reactions and the imaginary movement in the resonance hybrids of the products. d) Indicate which reactions are best termed Brønsted-Lowry acid - base reactions i. CH3CHO + HCI-- > CH3CH2O + + Cl- ii. CH3CHO + OH- - - > CH3CO-(OH) H

Consider the following data on some weak acids and weak bases: acid base Ba K, name formula name formula hydrocyanic acid HCN 10 4.9 x 10 methylamine| CH3NH2 |4.4 × 10 HCH,CO2 1.8 × 10 ethylamine C2H5NH2|6.4 × 10 acetic acid Use this data to rank the following solutions in order of increasing pH. In other words, select a '1' next to the solution that will have the lowest pH, a '2' next to the solution that will have the next lowest pH, and so on. solution pH 0.1 M NaCN choose one 0.1 M KBr choose one 0.1 М КСН3СО2 choose one 0.1 М CН3NHзBr choose one

CARBON 5 1 H 1.008 Circle and name ALL the functional groups in this molecule HO O 6 с 12.01 CH 3 | но H 1 C-C-C-C-N | || | OH Indicate which carbon/s in the molecule would be asymmetric What is the molecular formula of this molecule: Draw the group that serves as an ACID and show it in ionized form There are two groups that can become IONIZED (lose or gain H*). H/ I H Draw the group that serves as an BASE and show it in ionized form

K Calculate the pH of a 0.295 M solution of ethylenediamine (H₂NCH₂CH₂NH₂). The pKa values for the acidic form of ethylenediamine (HFNCH₂CH₂NH3) are 6.848 (pKat) and 9.928 (pK₁2). pH = Calculate the concentration of each form of ethylenediamine in this solution at equilibrium. [H₂NCH₂CH₂NH₂] = [H₂NCH₂CH₂NH] = [HNCH₂CH₂NH3] = M M M

Can you help to resolve this worksheet? this  is organic chemistry

Consider the following data on some weak acids and weak bases: acid base Ka name formula name formula hydrocyanic acid НCN - 10 4.9 x 10 methylamine CH3NH2 |4.4 × 10 hypochlorous acid HC1O 8. 3.0 × 10 ethylamine C2H,NH,|6.4 × 10 Use this data to rank the following solutions in order of increasing pH. In other words, select a 'l' next to the solution that will have the lowest pH, a '2' next to the solution that will have the next lowest pH, and so on. solution pH 0.1 M C2H5NH3CI choose one 0.1 M NaCN choose one 0.1 M NaCi choose one 0.1 М CН3NH3B choose one

Calculate the pH of a 0.123 M solution of ethylenediamine (H₂NCH₂CH₂NH₂). The pKą values for the acidic form of ethylenediamine (H3NCH₂CH₂NH³) are 6.848 (pKal) and 9.928 (pKa2). pH = Calculate the concentration of each form of ethylenediamine in this solution at equilibrium. [H₂NCH₂CH₂NH₂] : = [H₂NCH₂CH₂NH3] = M M

Draw the Lewis structures for chloroacetic acid and for acetic acid.  Use structural arguments to explain why acetic acid is a weaker acid then chloroacetic acid.  Be sure to refer to the stability of the ion that would be formed after dissociation of the acid.

Alkaloids are basic nitrogen-containing compounds of plant origin, many of which are physiologically active when administered to humans. Ingestion of coniine, isolated from water hemlock, can cause weakness, labored respiration, paralysis, and eventually death. Coniine is the toxic substance in the “poison hemlock” used in the death of Socrates. In small doses, nicotine is an addictive stimulant. In larger doses, it causes depression, nausea, and vomiting. In still larger doses, it is a deadly poison. Solutions of nicotine in water are used as insecticides. Cocaine is a central nervous system stimulant obtained from the leaves of the coca plant.Classify each amino group in these alkaloids according to type (primary, secondary, tertiary, aliphatic, aromatic, heterocyclic).

You have a solution of the three molecules below in a suitable organic solvent. NH₂ ملو OH In addition to the organic solvent and the three molecules, you have access to the following solutions: 1 M NaOH 1 M HCI 1 M CH3COOH 1 M Na2HPO4 Outline a method for how you would separate this solution into its component parts and briefly explain your rationale. You do not need to provide the level of detail shown in the Experimental; just the basics will be sufficient (e.g. wash with _____ to separate component __, then wash with _____ to separate component Y, etc.). Hint: you might need to search their pką values! You can write in paragraph style or organize your steps in a numbered list. 111)

Decide whether each of the molecules in the table below is stable, in the exact form in which it is drawn, at pH = 12. If you decide at least one molecule is not stable, then redraw one of the unstable molecules in its stable form below the table. (If more than one molecule is unstable, you can pick any of them to redraw.) Please include detailed steps and drawings of why the molecule is unstable or stable, and then a drawing of the new stable molecule from an unstable one. Remember that the pH = 12.

I'm asked to "assume that ozempic is in a solution at pH = 7. Draw the functional groups at their correct protonation form". For this, would I make all of the carboxyl groupsgo from COOH to COO-? and then the amide groups go from CONH to CONH3 + ? What about ether groups (COC) ?

1. Use the image provided to answer the question in detail: a) Two of the earliest drug molecules featured in Chapter 8 are Vicodin and Heroin, whose chemical structures are very similar.  Both of these molecules contain an amine functional group and several rings.  Indicate the number of aromatic rings in each structure, and identify the amine functional group in each molecule as primary, secondary, or tertiary.

Please help answer these questions, I'm stuck on them

Correct each molecule in the drawing area below so that it has the structure it would have if it were dissolved in a 0.1 M aqueous solution of HCI. If there are no changes to be made, check the No changes box under the drawing area.

General, Organic and Biochemistry -Laboratory Manual 2. A student was titrating pure hydrochloric acid of unknown molarity. He forgot to take the initial volume reading for the NaOH addition in his buret and decided to assume it was 0.00 mL. His final reading on the NaOH buret was 23.45 mL, and the volume of hydrochloric acid used for titration was 25.00 mL. The molarity of the NaOH is 0.120 M. his data. Show your work: (HINT: This is a very Calculate the molarity of HCl based similar procedure for calculating excess HCI acid. Remember for the last step that molarity equals mol/L) а.

Need help with 1-4 please. Will submit another time as well. Pre-laboratory questions

Calculate the pH of a 0.381 M solution of ethylenediamine (H, NCH, CH, NH,). The pKa values for the acidic form of ethylenediamine (H NCH, CH, NH) are 6.848 (pKa1) and 9.928 (pK2). pH Calculate the concentration of each form of ethylenediamine in this solution at equilibrium. [H,NCH,CH,NH,] = M [H,NCH,CH,NH;] = M [HNCH, CH, NH†] = M