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Soap and Biodiesel Synthesis
Abstract
The purpose of this study is to determine how the characteristics of different oils affect
the properties of the biodiesel produced by them, specifically which oil characteristics lead to
lower freezing points, viscosity, and higher energy per gram of fuel for the biodiesel the oil
produces. This was done by synthesizing both soap and biodiesel from a variety of different oils,
since both procedures involve the same chemicals and would therefore give two different
references to determine the relationship between oil characteristics and product properties. The
result of this study was that the unsaturated:saturated ratio of the oil significantly impacts the
melting point of the resulting biodiesel (meaning it does the same for freezing point), with higher
unsaturated:saturated ratios resulting in higher IMFs, meaning higher melting and freezing
points. The unsaturated:saturated ratios of the feedstock oils also directly impacted the viscosity
of the biodiesel synthesized with them, with higher amounts of carbon double bonds (from
unsaturated fatty acids) resulting in higher viscosities. Finally, the higher energy per gram of fuel
is also influenced by the feedstock oil used. While these conclusions are drawn from molecular
understanding inferences with examples from the data to back them, there are exceptions to these
conclusions that are most likely a result of the synthesis process and human error during
experimentation.
Introduction
The goal of this lab is to explore the relationship between molecular structure and physical
properties using the synthesis of soap and biodiesel. One common approach to making soaps is
the reaction of triglycerides with a concentrated strong base, in a process known as
saponification. This is a type of chemical reaction in which ester molecules are broken to create a
functional group of carboxylic acid and alcohol. Fats and oils are composed mainly of
triglycerides, three fatty acids joined together by a glycerol backbone. During the synthesis of
soaps, triglycerides are converted to fatty acid salts and glycerol; the properties of a fatty acid
salt depend on the triglycerides from which they came from. In order to separate out the salts
from the rest of the reaction products, a saturated NaCl solution is added. This forces the soap to
coagulate without dissolving in the water. It can then be collected by filtration and washed to
remove the excess base. Biodiesel is made by a reaction very similar to that of soaps where a
triglyceride is reacted but biodiesel needs esterification. Esterification is the process of
combining a carboxylic acid with an alcohol to form an ester and water. One very important
property of biodiesel is its viscosity, a fluid's resistance to flow. Although these two substances
are made in very similar manners, they have very different properties which will be explored in
this lab.
Methods/procedure
Soap Synthesis Protocol:
20 ml of canola oil were prepared
20 ml of ethanol were prepared
50 ml of a 10 M NaOH solution were gathered
All of the above reactants were combined then placed on a hot plate
The reactants were stirred on the hotplate until all the ethanol was dissolved and the product
looked like a gummy marshmallow
The beaker was removed and cooled before we added 100 ml of a saturated NaCl and mixed
The beaker was covered properly and rested for 2 weeks
Soap drying procedure:
The products that were stored from week one was poured through a mesh screen to separate the
soap from the remaining liquid
The soap was then rinsed with water to ensure all excess liquids were gone
The soap was then dried with paper towels and weighed
Testing of Soap and Biodiesel:
The soap was tested for foam deflation distance by adding 5 ml of DI water and a pea sized
amount of soap and shaking to see the height difference in the bubbles
To find the density 10 g of soap was submerged in water and the volume change was recorded
The pH of the soap was found using pH paper
Emulsification was found using a small amount of soap and 5 ml of DI water with 10 drops of
mineral oil
It was shaken and examined to see if the layers remained
The biodiesel was tested using calorimetry
A pop can was filled with 200g of water and 1.5 g of biodiesel was measured into a crucible
A wick was placed into the oil and then lit, the flames was touching can and a thermometer was
placed into the can without touching the bottom
2
The temperature was monitored, being watched to not go over 80C
The time was measured for the biodiesel to be fully consumed and then calculated into J/g using
q water (J) = m (g) * C (J/g.K) * ΔT (K)
m = mass of water used
C = heat capacity of water
ΔT =change in temperature of water
Biodiesel was also tested for presence of soap
2 ml of biodiesel and 5 ml of water were placed in a test tube and mixed
If 2 distinct layers were formed no soap was present and if 3 layers were formed then soap was
present
Viscometry was tested using a Varnish Viscometer Tube where the time was recorded for the
bubble to travel from the 27 line to the 100 line for both canola oil and glycerol
The melting point of canola oil was found through attaching the thermocouple to the Pasco
SparkLink interface and recording the range of temperatures on the thermocouple
Results
Table 1: Soap Summary of Properties
Feedstock
Oil
Physical
Characteristics
Molecular
Weight of
Soap
(g/mol)
Theoretical
Yield of
Soap (g)
Calculated
Yield of
Soap (%)
Foam
Deflation
Distance
(Inches)
Calculated
Density
(g/mL)
pH
Emulsif
-ication
Olive
Off white,
chunky, soft,
damp
300.64
18.987
237.26
0.82
1.11
9
No
Sunflower
White, chunky,
moist,
malleable
299.30
18.41
228.19
1.5
1.13
11
No
Safflower
Chunky, hard,
white, and dry
300.97
19
250.89
2.2
1.12
11
No
Canola
Off white, soft,
stringy, pliable
302.64
18.15
440
0.75
1.25
12
No
Soybean
Off white,
chunky, damp
300.30
19.82
312.76
1.25
1.11
11
No
3
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Table 2: Biodiesel Summary of Properties
Feedstock
Oil
Physical
Qualities
Calculated
J/g
Biodiesel
3 layers of
soap? (if
yes, time in
seconds to
separate)
Viscosity
Trial 1
(bubble
seconds)
Viscosity
Trial 2
(bubble
seconds)
Average
Viscosity
(bubble
seconds)
Glycerol
Control
(bubble
seconds)
Melting
Point
Range
Olive
White,
soft,
chunky
-15,627.73
Yes, 10
seconds
1.12
1.15
1.135
9.51
15
Sunflower
White,
chunky,
soft,
malleable
-18,418
Yes, 20
seconds
1.13
1.1
1.115
9.47
14.9
Safflower
Chunky,
solid,
white, dry
35,162.40
No (2
layers)
1.18
1.1
1.14
9.51
16
Canola
White/yell
ow, soft,
smooth,
stringy
-14,511.47
Yes, 38
seconds
1.08
1.07
1.075
9.51
18.1
Soybean
Yellow,
soft,
smooth
-13,047.27
No (2
layers)
1.08
1
1.04
9.51
13.6
Table 3: Unsaturated: Saturated Ratio
Feedstock Oil
Unsaturated: Saturated Ratio
Olive
4.6
Sunflower
7.3
Safflower
10.1
Canola
15.7
Soybean
5.7
Examples of Calculations (Using Canola Oil Results)
Molecular Weight of Soap (g/mol)
((880-89.09)/3)+39= 302.64 g/mol
4
Calculated Percent Yield of Soap
(79.86/18.15) times 100= 440
Calculated Density of Soap
10.0034g/8mL= 1.25g/mL
Calculated J/g of Biodiesel
200 times 4.186 times 26= 21,767.2
-21,767.2/1.5= -14,511.4667
Average Viscosity of Biodiesel
(1.08+1.07)/2= 1.075
Melting Point Range of Biodiesel
14.4+3.7= 18.1
Discussion
Question 1
One connection between the soap structure and its properties is that the molecular
structure of soap has a polar side and a nonpolar side to allow for emulsification. The COONa
end is meant to attract water molecules and form hydrogen bonds since both are polar, while the
nonpolar end is meant to form IMFs with nonpolar molecules that are dirt on the skin. In the case
of this experiment, no soap was able to emulsify. This may be due to the large amount of excess
NaOH added to the soap. As seen in the table, the pH of the soaps varied from olive oil soap’s
pH of 9 to canola oil soap’s pH of 12. Since NaOH is a strong base, having too much NaOH that
did not react during the saponification process will greatly affect the pH of the solution, which
will prevent the soap from properly attaching to the dirt. As seen in the table, every soap could
not emulsify the mineral oil with the water. High pH is the reasoning behind this.
Another
connection
between
soap structure and properties is that the higher the
unsaturated:saturated ratio (or the more unsaturated fatty acids contained in the oil to make the
soap), the less lather produced in the form of foam. This is shown most clearly between canola
oil, which has the highest unsaturated:saturated ratio of 15.7 and the lowest foam deflation
distance of 0.75, and soybean oil, which has a ratio of 5.7 and a foam deflation rate of 1.25. This
is because the shorter and more saturated fatty acid chains are more easily dissolved in water,
since the nonpolar portion of the fatty acid is smaller and more manageable than the unsaturated
carbon chains with double bonds (Vidal, et. al., 2018). This pattern is not followed by all the
soaps however, as seen with safflower oil with the 10.1 ratio and the 2.2 foam deflation rate. This
is because how much foam is produced depends on multiple factors, such as the other non-water
solutes in the solution such as the Na and Cl ions that were used to store the soap and again, the
excess NaOH.
5
Question 2
The structure of biodiesel directly impacts the different properties of biodiesel. The main
biodiesel properties that we tested are unsaturated/saturated ratio, calorimetry (specifically J/g of
biodiesel), presence of soap, viscosity, and melting point range. All of the evidence related to
biodiesel can be located in table 2. Canola oil had the highest unsaturated: saturated ratio at 15.7,
while olive oil had the lowest at 4.6, and soybean had 5.7. All of the feedstock oils had similar
physical characteristics. The lowest calculated J/g of biodiesel was sunflower oil at -18,418,
while the highest calculated J/g of biodiesel was safflower oil at 35,162.40. Soybean oil had
-13,047.27 and canola oil had a J/g ratio of -14,511.47. Olive, sunflower, and canola oil all had 3
layers of soap, while safflower and soybean oil only had two layers in their biodiesel. The
longest time to see full separation of the layers of soap was 38 seconds for canola oil, and the
quickest time to clearly see the layers was olive oil at 10 seconds. The highest average viscosity
in bubble seconds was 1.14 for safflower, while the lowest was 1.04 for soybean oil. Canola had
an average viscosity of 1.075 bubble seconds. The largest melting point range was seen by
canola oil at 18.1 and the smallest melting point range was 13.6 for soybean oil. Biodiesel is
made through the process of transesterification where an oil/fat (triglyceride) reacts with an
alcohol. Biodiesel has a very low solubility in water because it is non-polar with the exception of
two polar C-O bonds, so the strongest IMF in biodiesel is weak dipole-dipole, meaning biodiesel
cannot dissolve in a polar solvent like water. One of the main ways to determine the structure of
a fatty acid is to look at the unsaturated to saturated ratio. This is because it tells us the length of
a carbon chain and if there are any double bonds. Canola oil had the highest unsaturated to
saturated ratio because it had the highest number of oleic acid, linoleic acid, and alpha linoleic
acid (all of which are unsaturated fats). Soybean oil had a lower unsaturated to saturated ratio
because it had less unsaturated fats compared to canola oil (except for polyunsaturated fat). This
means that canola oil would typically have longer carbon chains than soybean oil. Viscosity has a
direct correlation with the number of carbon atoms. The double bond in unsaturated fatty acids
produces a bend in the carbon chain that is more pronounced in cis configurations than trans
configurations. Because of this, cis configurations cannot line up next to one another neatly, and
that means molecules are more tightly packed in trans carbon chains, resulting in a higher
viscosity. (Gopinath et al., 2014). This can be seen when comparing the average viscosity of
canola oil (1.075 bubble seconds) to soybean oil (1.04 bubble seconds). Canola oil had the
largest melting point range because the melting point increases with chain length for saturated
compounds (Gopinath et al., 2014). Canola oil also had a higher calculated J/g of biodiesel than
soybean oil because it had a greater total change in the temperature of the water by 2 degrees
celsius. Finally, soybean oil did not have the presence of soap but canola oil did. According to an
article by the National Library of Medicine, the saponification value was 189-195 for soybean oil
and 188-193 for canola oil (Neupane, 2022). The ranges from the study are just small enough
that it passes biodiesel soap percentage standards, so our results could be from canola oil or
soybean oil having slightly more soap in the experiment conducted by the class. In conclusion,
the properties found in biodiesel are different when created with contrasting feedstock oils.
Question 3
All oils melted at a relatively consistent range, but canola oil melting lowest, at -3.7 C.
The melting point of oils is affected by the length of the fatty acid chain. Canola oil has the
largest unsaturated to saturated ratio (15.7), so it would have the lowest melting point. This
6
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would be beneficial in biodiesel because it wouldn't freeze as quickly when used in containers.
Canola oil also has the second highest energy per gram. At -14511.4667J/G, it would combust
energy more efficiently in comparison to the other oils tested. This would improve usage and
efficiency when using biodiesel. Lastly, canola oil has low viscosity. While all tested oils are
significantly similar, it does have the second lowest. This is also because of the high unsaturated
ratio, making the oil not have significant viscosity.
Question 4 (bonus)
Canola oil would make a good soap, if treated properly. In the experiment, the soap had a
pH of 12, but if cleaned and dried thoroughly, this could be down to 10. Canola oil has the lowest
deflation of all oils tested, as well as no layers of emulsification. It would be beneficial to run the
experiment again before concluding that it is safe, however with the data provided, canola oil
would be a good candidate for soap making.
Conclusion
In order to determine how the characteristics of different oils affect the properties of the
biodiesel produced by them, an experiment was conducted to produce soap with triglycerides.
Oil characteristics with long fatty acid chains have lower freezing points. High unsaturated to
saturated ratios lead to low viscosity.
High energy per gram of fuel is directly related to the
energy per bonds. In order to test these conclude these properties, experiments were conducted
on the physical properties and compared to the molecular properties of oils.
References
Gopinath, A., Sairam, K., Velraj, R., & Kumaresan, G. (2014). Effects of the properties and the
structural configurations of fatty acid methyl esters on the properties of biodiesel fuel: a review.
Proceedings of the Institution of Mechanical Engineers, Part D: Journal of Automobile
Engineering
,
229
(3), 357–390.
https://doi.org/10.1177/0954407014541103
Neupane, D. (2022). Biofuels from Renewable Sources, a Potential Option for Biodiesel
Production.
Bioengineering
,
10
(1), 29.
https://doi.org/10.3390/bioengineering10010029
Prieto Vidal N, Adeseun Adigun O, Pham TH, Mumtaz A, Manful C, Callahan G, Stewart P,
Keough D, Thomas RH. The Effects of Cold Saponification on the Unsaponified Fatty Acid
Composition and Sensory Perception of Commercial Natural Herbal Soaps. Molecules. 2018 Sep
14;23(9):2356. doi: 10.3390/molecules23092356. PMID: 30223479; PMCID: PMC6225244
https://www.ncbi.nlm.nih.gov/pmc/articles/PMC6225244/#B2-molecules-23-02356
.
7
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- A geochemist in the field takes a small sample of the crystals of mineral compound X from a rock pool lined with more crystals of X. He notes the temperature of the pool, 24. C, and caps the sample carefully. Back in the lab, the geochemist dissolves the crystals in 3.00 L of distilled water. He then filters this solution and evaporates all the water under vacuum. Crystals of X are left behind. The researcher washes, dries and weighs the crystals. They weigh 45.0 g. Using only the information above, can you calculate yes the solubility of X in water at 24." C no If you said yes, calculate it. Be sure your answer has a unit symbol and 3 signiicant digits.arrow_forwardA 2C3H18(1) + 2502(g) = 16CO2(g) + 18H20(1) B CO2(g) + 2H20(g) = CO2(g) + 4H2(g) C 3CO(g) + Fe,03(s) = 3CO2(g) + 2Fe(s) Which of these processes energetically favors the products A only B and C only А, В and C A and C onlyarrow_forwardusing a calibrated solution calorimeter measured a temperature decrease of 1.10 K when 1.00 g of KNO3 was added to 74.40 g of deionized water in the calorimeter. The specific heat capacity of the solution calorimeter was found to be 4.15 J/gK. Calculate the experimental value of the molar heat of solution of KNO3, ΔHsoln. Was the dissolution of this salt exothermic or endothermic?arrow_forward
- When 4 grams of a certain compound is dissolved in 61 grams of water in a calorimeter, the temperature of the calorimeter changes from 25.00ºC to 26.98 ºC. Assuming that the specific heat capacity for the resulting solution is 4.184 J/(g oC), and the heat for this solvation is found as x kJ, what is the value of x?arrow_forward4NH3(g) + 3O2(g) → 2N2(g) + 6H2O(l), ΔH = -1530kJmol-1 (1) H2(g) + 1/2O2(g) → H2O(l), ΔH = -288 kJmol-1 (2) Construct an enthalpy cycle and calculate the enthalpy of formation of ammonia.arrow_forwardNumber 1arrow_forward
- When 5.022 g of sodium hydrogen carbonate NAHCO2(s) reacts completely with 80.00 mL of acetic acidCH3COOH(aq), the temperature increases from 18.6°C to 28.4°C. CH3COOH(aq)NaHCO2 (s) → CH3COONa(aq) + CO2(g) + H2O(l) Assume that the acid solution has the same density and specific heat capacity as water and that the mass of the finalsolution is 80.00 g. Calculate the molar enthalpy of reaction, ΔHr.arrow_forwardCalculate the amount of energy released as heat by the formation of 1.00 mL of water from a stoichiometric mixture of H2(g) and O2(g) at 25°C and a constant pressure of one bar. Calculate the amount of energy released as heat by this reaction per mole and per gram of H2(g). Take the density of water to be 1.00 grams per milliliter.arrow_forward13.3p. If you allow one pound of carbon dioxide to sublime (change from CO2(s) to CO2(g)) at room conditions of roughly 1atm and 25C, what volume would it occupy?arrow_forward
- Nonearrow_forwardEnter a balanced equation for the complete combustion of liquid C3 H60. Express your answer as a chemical equation. Identify all of the phases in your answer. ΑΣΦ ? C, H, O(1) + O, (g)→CO, (g)+H, O(g) A chemical reaction does not occur for this question.arrow_forwardUse the Born Haber cycle to calculate the lattice energy of Na2O(s) from the following data. Ionization energy of Na(g ) = 485 kJ mol-1 Electron Affinity of O(g) for two electrons = 553 kJ mol-1 Energy to Sublime Na(s) = 109 kJ mol-1 Bond energy of O2 = 449 kJ mol-1 ArxnH for 2 Na(s) + 1/2 O2(g) -> Na2O(s) = -466 kJ mol-1arrow_forward
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