Enter a balanced equation for the complete combustion of liquid C3H6O. Express your answer as a chemical equation. Identify all of the phases in your answer. ΑΣφ ? C; H, O(1) + 0, (g)→CO, (g)+H, O(g) O A chemical reaction does not occur for this question.
Thermochemistry
Thermochemistry can be considered as a branch of thermodynamics that deals with the connections between warmth, work, and various types of energy, formed because of different synthetic and actual cycles. Thermochemistry describes the energy changes that occur as a result of reactions or chemical changes in a substance.
Exergonic Reaction
The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.
![**Balanced Chemical Equation for the Complete Combustion of Liquid C₃H₆O**
To determine the complete combustion of liquid C₃H₆O, you need to write the chemical equation and identify the phases of each compound involved.
**Given Equation:**
\[ C_3H_6O(l) + O_2(g) \rightarrow CO_2(g) + H_2O(g) \]
### Explanation:
1. **C₃H₆O (l)**: This represents liquid Propanol (or another isomer with the same formula).
- **Phase**: Liquid (l)
2. **O₂ (g)**: This represents oxygen gas.
- **Phase**: Gas (g)
3. **CO₂ (g)**: This represents carbon dioxide gas.
- **Phase**: Gas (g)
4. **H₂O (g)**: This represents water in the gaseous phase (steam).
- **Phase**: Gas (g)
### Steps to Balance the Equation:
1. **Balance the carbons (C)**:
- There are 3 carbons on the reactant side (C₃H₆O) and we need 3 on the product side.
- Put a coefficient of 3 before CO₂:
\[ C_3H_6O(l) + O_2(g) \rightarrow 3CO_2(g) + H_2O(g) \]
2. **Balance the hydrogens (H)**:
- There are 6 hydrogens on the reactant side (C₃H₆O) and we need 6 on the product side.
- Put a coefficient of 3 before H₂O:
\[ C_3H_6O(l) + O_2(g) \rightarrow 3CO_2(g) + 3H_2O(g) \]
3. **Balance the oxygens (O)**:
- There are now 3 CO₂ which gives us \(3 \times 2 = 6\) oxygens.
- There are also 3 H₂O which gives us \(3 \times 1 = 3\) oxygens.
- Total oxygens needed on the reactant side is 9 (6 from CO₂ and 3 from H₂O).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3e9bc902-5aae-4660-a256-c76a2ed5e4a1%2Fa4cd7858-4cb9-4396-b50d-bcd7f8e12268%2Fjkhdd3c_processed.png&w=3840&q=75)
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