2. Calculate the enthalpy change to be expected for the dissolution of NaOH ((s) and (aq) mean solid and aqueous) using Hess's Law: q + H*(aq) your class and NaOH(s) → NAOH(aq) НСІ culate the action. Use the enthalpy change for NaOH-HCI pair that your class measured in this experiment, and the data from the following table: Reaction* AH(kJ/mol) ½H2(g) + ½CI2(g) → HCI(g) - 92.3 Na(s) + ½O2(g) + ½H2(g) → NaOH(s) –426.8 Na(s) + ½CI2(g) → NaCI(s) – 411.1 H2(g) + ½O2(g) → H2O(1) - 285.8 HCI(g) → HCI(aq) -75.2 NaCI(s) → NaCI(aq) 4.0 NaOH(aq) + HCI(aq) → NaCl(aq) + H2O(1) *(g) = gas, (1) = liquid, (s) = solid, (aq) = aqueous %3D %3D %3D
2. Calculate the enthalpy change to be expected for the dissolution of NaOH ((s) and (aq) mean solid and aqueous) using Hess's Law: q + H*(aq) your class and NaOH(s) → NAOH(aq) НСІ culate the action. Use the enthalpy change for NaOH-HCI pair that your class measured in this experiment, and the data from the following table: Reaction* AH(kJ/mol) ½H2(g) + ½CI2(g) → HCI(g) - 92.3 Na(s) + ½O2(g) + ½H2(g) → NaOH(s) –426.8 Na(s) + ½CI2(g) → NaCI(s) – 411.1 H2(g) + ½O2(g) → H2O(1) - 285.8 HCI(g) → HCI(aq) -75.2 NaCI(s) → NaCI(aq) 4.0 NaOH(aq) + HCI(aq) → NaCl(aq) + H2O(1) *(g) = gas, (1) = liquid, (s) = solid, (aq) = aqueous %3D %3D %3D
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:2. Calculate the enthalpy change to be expected
for the dissolution of NaOH ((s) and (aq) mean
solid and aqueous) using Hess's Law:
q + H*(aq)
your class
and
NaOH(s) → NAOH(aq)
НСІ
culate the
action.
Use the enthalpy change for NaOH-HCI pair
that your class measured in this experiment,
and the data from the following table:
Reaction*
AH(kJ/mol)
½H2(g) + ½CI2(g) → HCI(g)
- 92.3
Na(s) + ½O2(g) + ½H2(g) → NaOH(s)
–426.8
Na(s) + ½CI2(g) → NaCI(s)
– 411.1
H2(g) + ½O2(g) → H2O(1)
- 285.8
HCI(g) → HCI(aq)
-75.2
NaCI(s) → NaCI(aq)
4.0
NaOH(aq) + HCI(aq)
→ NaCl(aq) + H2O(1)
*(g) = gas, (1) = liquid, (s) = solid, (aq) = aqueous
%3D
%3D
%3D
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