120_Chapter2_measurements_practice_key
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CHEM-120
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Chemistry
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Feb 20, 2024
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Chapter 3: 1.
Convert the following to scientific notation: 62,345 = 6.2345x10
4
0.0000453=
4.53x10
-5
2.
How many significant digits are in the following 0.12
(2) 359 (3) 123.0 (4) 0.0230 (3) 2.500 x 10
2
(4) 2005 (4) 3.4 x 10
3
(2) 0.0007 (1) 3.
Round off the following to 3 significant figures, use scientific notation as appropriate 23465008 = 2.35x10
7
0.00045689=
4.57x10
-4
8.4317x 10
4
= 8.43x10
4
4.
Do the following calculations and keep the correct in your answers 8.72 x 10
-3
- 9.53 x 10
-4
= 7.77x10
-3
8.16 x 10
4
+ 3.79 x 10
5
= 4.61x10
5
(2.333 x 10
2
) x 5.6 = 1.3x10
3
(2.34
x 54.65)/1.2 = 1.1x10
2
5.
Complete with a number: 1
microgram = _
10
-6
____grams 1 liter = ___
10
3
______milliliters 6.
Complete with a prefix: 10
6
meters = __
mega
__meter 10
-3
grams = _
milli
____gram
Chapter 3 continued: 7.
Calculate the following – make sure to show the set up equation for each conversion: a.
165 mL to L: 165mL x 1L______ = 0.165 L 1000mL b.
2.40x10
2
cm to mm: 2.40x10
2
cm x _1m_
x 1000mm
= 2.40x10
3
mm (or 10mm ) 100cm 1m 1cm c.
0.012kg to mg: 0.012kg x 10
3
g x 10
3
mg
= 1.2x10
4
mg 1kg 1g d.
1.564m to inches: 1.564m x 100cm
x 1 in ____
= 61.57 in 1m 2.54cm 8.
The density of lead at 20 °
C is 11.4 g / cm
3
. What is the volume of 15.0 g? V = 15.0 g x 1 cm
3
_ = 1.32cm
3 11.4 g 9.
A sample of an unknown substance has a mass of 7.78 g and the volume is 9.725 cm
3
what is the density of the sample? D = m__
= 7.78 g = 0.800 g/cm
3
V 9.725cm
3
10.
Gold has a density of 19.3 g / cm
3 at 20 °
C. What is the mass of a sample that is 14.0 cm
3
. m = 14.0cm
3
x 19.3 g = 270. g or (2.70x10
2
g) 1cm
3
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