120_Chapter2_measurements_practice_key

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Lansing Community College *

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CHEM-120

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Chemistry

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Feb 20, 2024

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pdf

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Chapter 3: 1. Convert the following to scientific notation: 62,345 = 6.2345x10 4 0.0000453= 4.53x10 -5 2. How many significant digits are in the following 0.12 (2) 359 (3) 123.0 (4) 0.0230 (3) 2.500 x 10 2 (4) 2005 (4) 3.4 x 10 3 (2) 0.0007 (1) 3. Round off the following to 3 significant figures, use scientific notation as appropriate 23465008 = 2.35x10 7 0.00045689= 4.57x10 -4 8.4317x 10 4 = 8.43x10 4 4. Do the following calculations and keep the correct in your answers 8.72 x 10 -3 - 9.53 x 10 -4 = 7.77x10 -3 8.16 x 10 4 + 3.79 x 10 5 = 4.61x10 5 (2.333 x 10 2 ) x 5.6 = 1.3x10 3 (2.34 x 54.65)/1.2 = 1.1x10 2 5. Complete with a number: 1 microgram = _ 10 -6 ____grams 1 liter = ___ 10 3 ______milliliters 6. Complete with a prefix: 10 6 meters = __ mega __meter 10 -3 grams = _ milli ____gram
Chapter 3 continued: 7. Calculate the following – make sure to show the set up equation for each conversion: a. 165 mL to L: 165mL x 1L______ = 0.165 L 1000mL b. 2.40x10 2 cm to mm: 2.40x10 2 cm x _1m_ x 1000mm = 2.40x10 3 mm (or 10mm ) 100cm 1m 1cm c. 0.012kg to mg: 0.012kg x 10 3 g x 10 3 mg = 1.2x10 4 mg 1kg 1g d. 1.564m to inches: 1.564m x 100cm x 1 in ____ = 61.57 in 1m 2.54cm 8. The density of lead at 20 ° C is 11.4 g / cm 3 . What is the volume of 15.0 g? V = 15.0 g x 1 cm 3 _ = 1.32cm 3 11.4 g 9. A sample of an unknown substance has a mass of 7.78 g and the volume is 9.725 cm 3 what is the density of the sample? D = m__ = 7.78 g = 0.800 g/cm 3 V 9.725cm 3 10. Gold has a density of 19.3 g / cm 3 at 20 ° C. What is the mass of a sample that is 14.0 cm 3 . m = 14.0cm 3 x 19.3 g = 270. g or (2.70x10 2 g) 1cm 3
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