Q8. Convert 76.8 cm to m. (a) 0.0768 m (c) 0.768 m Q9. Convert 2855 mg to kg. (a) 2.855 x 10³ kg (b) 2.855 kg (c) 0.02855 kg (d) 3.503 x 104 kg Chemical Principles (b) 7.68 m (d) 7.68 x 10-2 m P:91 'e:g1 'qt
Q8. Convert 76.8 cm to m. (a) 0.0768 m (c) 0.768 m Q9. Convert 2855 mg to kg. (a) 2.855 x 10³ kg (b) 2.855 kg (c) 0.02855 kg (d) 3.503 x 104 kg Chemical Principles (b) 7.68 m (d) 7.68 x 10-2 m P:91 'e:g1 'qt
Introductory Chemistry: A Foundation
9th Edition
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter2: Measurements And Calculations
Section: Chapter Questions
Problem 2QAP: Although your textbook lists (he rules for converting an ordinary number to scientific notation,...
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Q9. I am unsure on how to get the final answer. I believe we have to convert the number to scientific notation but I’m not sure how they got that answer.
![**Unit Conversion Examples**
Let's go through two examples of unit conversions: one for length and one for mass.
### Length Conversion
**Given Values:**
- 1 centimeter (cm) = 0.01 meters (m)
**Problem:** Convert 76.8 cm to meters (m).
**Steps:**
1. Multiply the length in centimeters by the conversion factor to convert it to meters.
2.
\[76.8 \times 0.01\]
**Calculation:**
\[76.8 \times 0.01 = 0.768 \, m\]
**Result:**
\[76.8 \, cm = 0.768 \, m\]
### Mass Conversion
**Given Values:**
- 1 milligram (mg) = \(1 \times 10^{-6}\) kilograms (kg)
**Problem:** Convert 2855 mg to kilograms (kg).
**Steps:**
1. Multiply the mass in milligrams by the conversion factor to convert it to kilograms.
2.
\[2855 \, mg \times \frac{1 \times 10^{-6} \, kg}{1 \, mg}\]
**Calculation:**
\[2855 \, mg \times 1 \times 10^{-6} = 0.002855 \, kg\]
**Result:**
\[2855 \, mg = 0.002855 \, kg\]
These examples illustrate basic unit conversions using multiplication by appropriate conversion factors.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F538f3e83-7f0d-4c1a-a688-bdf41958b228%2F05c26ad9-fecf-40fa-98f6-f1060eeaf9b1%2Frfvivnh_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Unit Conversion Examples**
Let's go through two examples of unit conversions: one for length and one for mass.
### Length Conversion
**Given Values:**
- 1 centimeter (cm) = 0.01 meters (m)
**Problem:** Convert 76.8 cm to meters (m).
**Steps:**
1. Multiply the length in centimeters by the conversion factor to convert it to meters.
2.
\[76.8 \times 0.01\]
**Calculation:**
\[76.8 \times 0.01 = 0.768 \, m\]
**Result:**
\[76.8 \, cm = 0.768 \, m\]
### Mass Conversion
**Given Values:**
- 1 milligram (mg) = \(1 \times 10^{-6}\) kilograms (kg)
**Problem:** Convert 2855 mg to kilograms (kg).
**Steps:**
1. Multiply the mass in milligrams by the conversion factor to convert it to kilograms.
2.
\[2855 \, mg \times \frac{1 \times 10^{-6} \, kg}{1 \, mg}\]
**Calculation:**
\[2855 \, mg \times 1 \times 10^{-6} = 0.002855 \, kg\]
**Result:**
\[2855 \, mg = 0.002855 \, kg\]
These examples illustrate basic unit conversions using multiplication by appropriate conversion factors.
Transcribed Image Text:**Significant Figures and Unit Conversions Practice Questions**
**Q6. Perform this addition to the correct number of significant figures: 8.32 + 12.148 + 0.02**
- (a) 20.488
- (b) 20.49
- (c) 20.5
- (d) 21
**Q7. Perform this calculation to the correct number of significant figures: 78.222 × (12.02 − 11.52)**
- (a) 39
- (b) 39.1
- (c) 39.11
- (d) 39.111
**Q8. Convert 76.8 cm to m.**
- (a) 0.0768 m
- (b) 7.68 m
- (c) 0.768 m
- (d) 7.68 × 10⁻² m
**Q9. Convert 2855 mg to kg.**
- (a) 2.855 × 10⁻³ kg
- (b) 2.855 kg
- (c) 0.02855 kg
- (d) 3.503 × 10⁻⁴ kg
---
**Chemical Principles**
**Uncertainty**
Scientists report measured quantities so that the number of digits reflects the certainty in the measurement. Write measured quantities so that every digit is certain except the last, which is estimated.
**Units**
Measured quantities usually have units associated with them. The SI unit for length is the meter; for mass, the kilogram; and for time, the second. Prefix multipliers such as kilo- or milli- are often used in combination with these basic units. The SI units for length and mass are highlighted in the third image.
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