Lab Report-3-Stoichiometry Calculations

Grams: m(g) = n(mol) x M(g/mol) Moles of substance: n(mol) = m(g) / M(g/mol) These formulas were used to calculate the moles of all the substances to determine our unknown. X = Be BeCl2 + 2 AgNO3 -  Be(NO3)2 + 2 AgCl m(g) = m=M*n 3.0456 10.951 Mw (g/mol) = 79.718 143.42 N (MOL) = n=m/M 0.038 0.076 0.076 X = Mg MgCl2 + 2 AgNO3 -  Mg(NO3)2 + 2 AgCl m(g) = m=M*n 3.0456 9.169 Mw (g/mol) = 95.211 143.42 N (MOL) = n=m/M 0.032 0.064 0.064 X = Ca MgCl2 + 2 AgNO3 -  Ca(NO3)2 + 2 AgCl m(g) = m=M*n 3.0456 7.866 Mw (g/mol) = 110.98 143.32 N (MOL) = n=m/M 0.027 0.055 0.055 IV.  Results XCl2 + 2 AgNO3 -  X(NO3)2(aq)+ 2 AgCl(s) m(g) = 3.0456 8.5341 Compound is MgCl2 Percentage yield Y=(E/T)*100% 93.075 The unknown substance was identified as MgCl2. A 93% yield of MgCl2 was obtained during this lab experiment. V.  Conclusion