DNA Electrophoresis worksheet

DNA Fingerprinting & Paternity Worksheet Name: 1. The DNA fingerprints were made from blood samples taken from a puppyand four possible sires of this puppy in an effort to 5 determine the puppy’s pedigree. According to this information, which sire was probably the father of this puppy? Remember, a child must 2 share at least 50% of its DNA with each of its DNA Fingerprints ANSWER: C Puppy L O RXE 1) Possible Sires NTINEN T parents. So, you are c LT JUOLATIELR T ] looking for the father with the v s 4 closest match to the puppy. 11T felon S1 57 S3 2. The picture shows a segment of DNAfrom a cat and 4 possible offspring from that cat. Which of these IS most likely the kitten from that cat’s litter? ANSWER: 4 3. Mrs. Smith has a baby named Tyra. Shebelieves one of two men can be the father of her child. A paternity test IS done and the results are shown here. Which of the 2 men is baby Tyra’s father? _ Dad 2 4. Lt. Russ is investigating a murder scene. The felonwas scratched by his victim & some of his skin cells were found under the victim’s fingernails. A DNA test was performed. To which of the suspects do the skin cells collected from under the fingernails of the victim belong? baby mom dadl dad2 —— — — — WS —— — — — r— — . — — __ —— — — — — — Com— Cca— — — E— — ammn T _— —— mom daughter sonl son2 C— — — — —— — PR — — — — C— — — w— —— — —— — —_— T @S _—— E—— Co— g - — — — — S22

5. The millionaire, Mr. Big, has just died. He has left behind a wife, daughter and a large inheritance. The news of his death has brought forth 2 men who claim to be the long lost son of Mr. & Mrs. Big. Before Mr. & Mrs. Big were married they had an illegitimate child and had placed him up for adoption. They had tried to find him after they became wealthy but had no luck in locating him. A DNA sample was taken from Mrs. Big, the Big daughter and the two men who claim to be the long lost son. Which, if any, of the men are telling the truth? Son 2 6. Mr. & Mrs. Jones just gave birth to fraternal twins- Boband Jane. Unfortunately, the nurse has confused the Jones twins with 4 other babies. The doctors took samples of DNA from each of the babies and Mr. & Mrs. Jones. dad mom childl child2 child3 child4 childS childé6 — — — M— —— — I — ———] — — — m— — — —— — —— S— — — — — — o— — M e — — I Emm— — _—— s—— — —— E— I — — E— — A — e —— — — — — s — ] — N e — o— _—— s — S — —— aa—— E— e — — o commm o, mmmm —— — w— il « L before he died, and he arranged to have a sample of his blood frozen for DNA typing. The results of the typing are shown in the figure. Your job is to analyze the data and determine whether any of the children could be Megabucks' heir. Remember that every person has two of each chromosome, one inherited from his mother and one inherited from his father. Half of every person's DNA comes from his mother, and half comes from his father, so some of the DNA bands showing in the children will come from t fathers. The question is, could that father be Megabucks? 1. For the first child, identify the bands in the DNA profile that came f@e mother. (Remember that not all of the mother's DNA is transmitted to the child; just one of each pair of chromosomes is transmitted.) Mark the bal that came from the mother with an M. Circle the remaining ba-@ M Which of the 6 children are Mr. & Mrs. Jones twins? Child 1 and Child 4, 7. Mr. 1. M. Megabucks, the wealthiest man in the world, recently died. Since his death, three women have come forward. Each woman claims to have a child by Megabucks and demands a substantial share of his estate for her child. Lawyers for the estate have insisted on DNA typing of each of the alleged heirs. Fortunately, Megabucks anticipated trouble like this Fragment Megabucks X X's child Y Y's child 4 Z's child size.bp — [ ' ] I ] [ ) —J _J 400 - - 400 LI [ 300 - Eo— E— I - 300 — — —— L] — T 1 200 - =] T AT — . 200 —_— I E— = — — o — — EE—] G T —_— D 100 | — E—— E—— - e | BN | . I L} T — 50 - — . @hers, and t.s t will come from—== M < M C ™ — 10 Q <

Size, base pairs Semilog Graph 20,000 2,000 Size, base pairs 200 0 10 20 30 40 50 60 Distance traveled mm 80.000 e e e e < — e D i o ek et e B e i e T o i o o B B Lo S s S T S s S i 2R ok — e ——4-— 60.000 P Bt St PP PPt PP —g—q P4 > > - e g e o e e o - e e B S R S s S S i e e e sk ksl sk et — e —4 —4 -4 40.000 e e e P e e G e e e e - e e - G e - e — g —4 — e e e e e e e — e — -~ 20.000 - — 4 A S N NN e e e e i e e e e e« e — i . = 8.000 et -t -t PP A4 S+ S AP P 4 S+t 4+ gt —d 4 4 - B 0000 444t 4+t +++++t++t+1+41t 11+t +++++H++H41tt 4ttt t+t++++ 1+ -4 et o ae e e e e e e e el o o e e e —anf cad 4000 |44ttt 4+t 4+t 4+ttt 1ttt 1ttt N GHE VIS GHS S WIS ONS WU N O TR We N T SN .= e afhcnfhanth- - anfheatisats-cafinafiec - e S -GN PNV G T N .= et e 2.000 B 4 14121+ 4+ B S S o S e o ek e e e 44 4449+ ++ + 4+ — - -t =4~ 800 44141t 4+t ++++t+t+t+t+1t111t 1+t 4+ttt 11+ ++++++ 1+ Sy 44— ¢4 - 4+ 1~ — —q -~ 600 — 4ttt Pttt 1ttt Attt 44 4+—4—4 44 4+ 4+ -4t — 4 400 |44t t+t++++ttttt11 211ttt ++ 0+t — e e P o e e e - o e — —1 —p g - e B e e B e R ok o = = —4—1 4 - - 200 .. — — — -+ -+ 0 5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 85 Distance traveled, mm