Structural Steel Design (6th Edition)6th EditionJack C. McCormac, Stephen F. Csernak Publisher: PEARSONISBN: 9780134589657
Structural Steel Design (6th Edition)
Solutions for Structural Steel Design (6th Edition)
Browse All Chapters of This Textbook
Chapter 1 - Introduction To Structural Steel DesignChapter 2 - Specifications, Loads, And Methods Of DesignChapter 3 - Analysis Of Tension MembersChapter 4 - Design Of Tension MembersChapter 5 - Introduction To Axially Loaded Compression MembersChapter 6 - Design Of Axially Loaded Compression MembersChapter 7 - Design Of Axially Loaded Compression Members (continued) And Column Base PlatesChapter 8 - Introduction To BeamsChapter 9 - Design Of Beams For MomentsChapter 10 - Design Of Beams—miscellaneous Topics (shear, Deflection, Etc.)
Sample Solutions for this Textbook
We offer sample solutions for Structural Steel Design (6th Edition) homework problems. See examples below:
Chapter 1, Problem 1.1PFSGiven data: D = 80 psfL = 100 psfR = 14 psfLr = 20 psf S = 28 psf Calculation: Consider the dead...Given data: Section given is L4x4x1/4 Diameter of the bolt = 78 in. Gross area of the given angle...Given: The specified minimum yield stress is Fy=50 ksi, the specified minimum tensile strength is...Given: L=4 ftd=1.5 in Calculation: The area of a given solid round bar is A=πd24 Substitute the d...Given data: PD=150 kipsPL=230 kipsLC=18 ftSteel used=A992, Grade 50 LRFD method: The factored load...Given: The given frame is, Formula used: The rotational stiffness is given by, G=∑( I L )(IL) Here,...Chapter 8, Problem 8.1PFSGiven Information: LRFD: The design load is wu=1.2wD+1.5wLwu=1.2×1.2+1.6×3wu=6.24 k/ft The design...
Given: The continuous beam is shown below. And steel is 50 ksi . Calculation: Compute the factored...Given: Fy=50 ksiFu=65 ksiPD=80 kPL=100 kMDx=10 ft−kMLx=12 ft−kLb=12 ftCb=1.0 Calculation: The...Given: size of plates=1"×16"yield strength of steel,Fy=36 ksiultimate tensile strength Fu=58 ksiBolt...Given: The given connection is, Calculation: Calculate factored load for LRFD. Pu=1.2 (50)+1.6...Given: Calculation: The ultimate load by LRFD is Pu=1.6PLPu=1.6(32)Pu=51.2 kips The factored moment...Given: A36 web angleFy for W18×55 beam=50 ksiDiameter of bolts=34in.Angle...
More Editions of This Book
Corresponding editions of this textbook are also available below:
EBK STRUCTURAL STEEL DESIGN
5th Edition
ISBN: 9780100795013
EBK STRUCTURAL STEEL DESIGN
5th Edition
ISBN: 9780133464962
Structural Steel Design - 5th Edition
5th Edition
ISBN: 9780136079484
Structural Steel Design
4th Edition
ISBN: 9780132218160
STRUCTURAL STEEL DESIGN
7th Edition
ISBN: 9780137874163
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