Living By Chemistry: First Edition Textbook
Living By Chemistry: First Edition Textbook
1st Edition
ISBN: 9781559539418
Author: Angelica Stacy
Publisher: MAC HIGHER
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Chapter U6.5, Problem 3E

(a)

Interpretation Introduction

Interpretation: For the given reversible reaction, equilibrium equation needs to be written.

Concept introduction: For a reversible reaction, equilibrium is a state when both reactants and products have equal concentrations and it does not change with time.

An equilibrium reaction is represented as follows:

  A+BAB

At equilibrium, the change in the concentration of A, B is same as change in concentration of AB. For example, if concentration of A and B decreases by x value, the concentration of AB will increase by x .

(a)

Expert Solution
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Explanation of Solution

The given reaction is represented as follows:

  H2(g)+Cl2(g)2HCl(g)

The equilibrium equation can be represented for the above reaction as follows:

  K=[HCl(g)]2[H2(g)][Cl2(g)]

Here, [HCl(g)] , [H2(g)] and [Cl2(g)] is equilibrium concentration of hydrochloride gas, hydrogen gas and chlorine gas respectively.

(b)

Interpretation Introduction

Interpretation: Whether there is more product or reactant in the equilibrium mixture needs to be determined.

Concept introduction: An equilibrium reaction is represented as follows:

  A+BAB

For the above reaction, the change in concentration of A and B is equal to that of AB.

For the above reaction, equilibrium constant can be represented as follows:

  K=[AB][A][B]

Here, K is equilibrium constant.

(b)

Expert Solution
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Explanation of Solution

If the value of equilibrium constant K is more than 1 then product is favored in the reaction but, if the value of K is less than 1 then reactant is favored in the reaction.

Thus, if the value of K for an equilibrium reaction is known, it can be determine whether it is product or reactant favored.

The given value of equilibrium constant is 4.05×1031 .

The above value of K is more than 1, even is very large value thus, products will be favored in the equilibrium reaction. Therefore, there will be more products in the equilibrium mixture.

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