Bananas Here are the prices (in cents per pound) of bananas reported from 15 markets surveyed by the U.S. Department of Agriculture. a) Display these data with an appropriate graph. b) Report appropriate summary statistics. c) Write a few sentences about this distribution.

Question

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Answer 1

Textbook Question

Chapter R, Problem 1.1RE

Bananas Here are the prices (in cents per pound) of bananas reported from 15 markets surveyed by the U.S. Department of Agriculture.

Chapter R, Problem 1.1RE, Bananas Here are the prices (in cents per pound) of bananas reported from 15 markets surveyed by the

a) Display these data with an appropriate graph.
b) Report appropriate summary statistics.
c) Write a few sentences about this distribution.

a.

Expert Solution

To determine

Construct appropriate graph for the data.

Answer to Problem 1.1RE

Output obtained from the MINITAB is given below:

Intro Stats, Books a la Carte Edition (5th Edition), Chapter R, Problem 1.1RE , additional homework tip 1

The distribution of banana prices reported by USDA tends to left skewed distribution.

Explanation of Solution

Given info:

The data represents the sample of 15 bananas price surveyed by the U.S Department of agriculture.

Calculation:

Software procedure:

Step by step procedure to draw the frequency histogram chart by using MINITAB software.

Choose Graph > Histogram.
Choose Simple, and then click OK.
In Graph variables, enter the corresponding column of data.
To modify the interval settings, double click on the horizontal axis of the graph. Then, select Labels > Specified. In this box, enter the values for the cut points of the bin intervals (42, 46, 50, 54)
In scale on y-axis, make click on frequency.
Click on ok.

Skew ness:

The data is said to be skewed if there is lack of symmetry and values fall on one side that is, either left or right of the distribution.

Left skewed:

If the tail on the distribution is elongated towards the left, more over it attains its horizontal axis rapidly than its peak then it is a left skewed distribution. It is also called negatively skewed.

The mean is less than the median when the distribution of the data is left skewed. That is, Mean<Median<Mode.

b.

Expert Solution

To determine

Determine the appropriate summary statistics for the given data.

Answer to Problem 1.1RE

Median and IQR is the appropriate summary statistics for the given data.

Explanation of Solution

Calculation:

Software procedure:

Step-by-step procedure to obtain summary statistics is given below.

Choose Stat > Basic Statistics > Display Descriptive Statistics.
In Variables, enter the columns Bananas
Choose Statistics and select the median and IQR.
Click OK.

Output obtained from the MINITAB is given below:

Intro Stats, Books a la Carte Edition (5th Edition), Chapter R, Problem 1.1RE , additional homework tip 2

From the output, the median is 49 cents per pound, and the interquartile range is 6 cents per pound.

Relationship between mean and median:

The value of mean is equal to the median when the distribution of the data is symmetric. Mean=Median=Mode.
The mean is greater than the median when the distribution of the data is right skewed. Mean>Median>Mode.
The mean is less than the median when the distribution of the data is left skewed. That is, Mean<Median<Mode.

From part a., the distribution of the data is left skewed. This indicates that median will be greater than the mean.

Inter quartile range:

In contrast to the range, which measures only differences between the extremes, the inter quartile range (also called mid spread) is the difference between the third quartile and the first quartile. Thus, it measures the variation in the middle 50 percent of the data, and, unlike the range, is not affected by extreme values. IQR=Q3−Q1

Thus, for a left skewed distribution median and IQR are the better summary statistics.

c.

Expert Solution

To determine

Describe the distribution with few sentences.

Explanation of Solution

Justification:

Histogram:

The graphical representation of classes of the quantitative data in the horizontal axis and class frequency in the vertical axis displayed in terms of bar is termed as histogram of the data and there is no possibility of gap is in between these bars of histogram.

Based on the number of peaks, the modality is classified into three types namely unimodal, bi-modal and multimodal.

Unimodal: The number of peak is one.

Bi-modal: The number of peak is two.

Multi-modal: The number of peak is three or more than three.

Here, the histogram has only one peak and hence it is unimodal with left skewed.

Moreover, the center of the distribution lies approximately 50 cents and it also contains of lowest price near 42 cents per pound and the highest price near 53 cents per pound.

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Answer 2

Textbook Question

Chapter R, Problem 1.1RE

Bananas Here are the prices (in cents per pound) of bananas reported from 15 markets surveyed by the U.S. Department of Agriculture.

Chapter R, Problem 1.1RE, Bananas Here are the prices (in cents per pound) of bananas reported from 15 markets surveyed by the

a) Display these data with an appropriate graph.
b) Report appropriate summary statistics.
c) Write a few sentences about this distribution.

a.

Expert Solution

To determine

Construct appropriate graph for the data.

Answer to Problem 1.1RE

Output obtained from the MINITAB is given below:

Intro Stats, Books a la Carte Edition (5th Edition), Chapter R, Problem 1.1RE , additional homework tip 1

The distribution of banana prices reported by USDA tends to left skewed distribution.

Explanation of Solution

Given info:

The data represents the sample of 15 bananas price surveyed by the U.S Department of agriculture.

Calculation:

Software procedure:

Step by step procedure to draw the frequency histogram chart by using MINITAB software.

Choose Graph > Histogram.
Choose Simple, and then click OK.
In Graph variables, enter the corresponding column of data.
To modify the interval settings, double click on the horizontal axis of the graph. Then, select Labels > Specified. In this box, enter the values for the cut points of the bin intervals (42, 46, 50, 54)
In scale on y-axis, make click on frequency.
Click on ok.

Skew ness:

The data is said to be skewed if there is lack of symmetry and values fall on one side that is, either left or right of the distribution.

Left skewed:

If the tail on the distribution is elongated towards the left, more over it attains its horizontal axis rapidly than its peak then it is a left skewed distribution. It is also called negatively skewed.

The mean is less than the median when the distribution of the data is left skewed. That is, Mean<Median<Mode.

b.

Expert Solution

To determine

Determine the appropriate summary statistics for the given data.

Answer to Problem 1.1RE

Median and IQR is the appropriate summary statistics for the given data.

Explanation of Solution

Calculation:

Software procedure:

Step-by-step procedure to obtain summary statistics is given below.

Choose Stat > Basic Statistics > Display Descriptive Statistics.
In Variables, enter the columns Bananas
Choose Statistics and select the median and IQR.
Click OK.

Output obtained from the MINITAB is given below:

Intro Stats, Books a la Carte Edition (5th Edition), Chapter R, Problem 1.1RE , additional homework tip 2

From the output, the median is 49 cents per pound, and the interquartile range is 6 cents per pound.

Relationship between mean and median:

The value of mean is equal to the median when the distribution of the data is symmetric. Mean=Median=Mode.
The mean is greater than the median when the distribution of the data is right skewed. Mean>Median>Mode.
The mean is less than the median when the distribution of the data is left skewed. That is, Mean<Median<Mode.

From part a., the distribution of the data is left skewed. This indicates that median will be greater than the mean.

Inter quartile range:

In contrast to the range, which measures only differences between the extremes, the inter quartile range (also called mid spread) is the difference between the third quartile and the first quartile. Thus, it measures the variation in the middle 50 percent of the data, and, unlike the range, is not affected by extreme values. IQR=Q3−Q1

Thus, for a left skewed distribution median and IQR are the better summary statistics.

c.

Expert Solution

To determine

Describe the distribution with few sentences.

Explanation of Solution

Justification:

Histogram:

The graphical representation of classes of the quantitative data in the horizontal axis and class frequency in the vertical axis displayed in terms of bar is termed as histogram of the data and there is no possibility of gap is in between these bars of histogram.

Based on the number of peaks, the modality is classified into three types namely unimodal, bi-modal and multimodal.

Unimodal: The number of peak is one.

Bi-modal: The number of peak is two.

Multi-modal: The number of peak is three or more than three.

Here, the histogram has only one peak and hence it is unimodal with left skewed.

Moreover, the center of the distribution lies approximately 50 cents and it also contains of lowest price near 42 cents per pound and the highest price near 53 cents per pound.

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Answer 3

Textbook Question

Chapter R, Problem 1.1RE

Bananas Here are the prices (in cents per pound) of bananas reported from 15 markets surveyed by the U.S. Department of Agriculture.

Chapter R, Problem 1.1RE, Bananas Here are the prices (in cents per pound) of bananas reported from 15 markets surveyed by the

a) Display these data with an appropriate graph.
b) Report appropriate summary statistics.
c) Write a few sentences about this distribution.

a.

Expert Solution

To determine

Construct appropriate graph for the data.

Answer to Problem 1.1RE

Output obtained from the MINITAB is given below:

Intro Stats, Books a la Carte Edition (5th Edition), Chapter R, Problem 1.1RE , additional homework tip 1

The distribution of banana prices reported by USDA tends to left skewed distribution.

Explanation of Solution

Given info:

The data represents the sample of 15 bananas price surveyed by the U.S Department of agriculture.

Calculation:

Software procedure:

Step by step procedure to draw the frequency histogram chart by using MINITAB software.

Choose Graph > Histogram.
Choose Simple, and then click OK.
In Graph variables, enter the corresponding column of data.
To modify the interval settings, double click on the horizontal axis of the graph. Then, select Labels > Specified. In this box, enter the values for the cut points of the bin intervals (42, 46, 50, 54)
In scale on y-axis, make click on frequency.
Click on ok.

Skew ness:

The data is said to be skewed if there is lack of symmetry and values fall on one side that is, either left or right of the distribution.

Left skewed:

If the tail on the distribution is elongated towards the left, more over it attains its horizontal axis rapidly than its peak then it is a left skewed distribution. It is also called negatively skewed.

The mean is less than the median when the distribution of the data is left skewed. That is, Mean<Median<Mode.

b.

Expert Solution

To determine

Determine the appropriate summary statistics for the given data.

Answer to Problem 1.1RE

Median and IQR is the appropriate summary statistics for the given data.

Explanation of Solution

Calculation:

Software procedure:

Step-by-step procedure to obtain summary statistics is given below.

Choose Stat > Basic Statistics > Display Descriptive Statistics.
In Variables, enter the columns Bananas
Choose Statistics and select the median and IQR.
Click OK.

Output obtained from the MINITAB is given below:

Intro Stats, Books a la Carte Edition (5th Edition), Chapter R, Problem 1.1RE , additional homework tip 2

From the output, the median is 49 cents per pound, and the interquartile range is 6 cents per pound.

Relationship between mean and median:

The value of mean is equal to the median when the distribution of the data is symmetric. Mean=Median=Mode.
The mean is greater than the median when the distribution of the data is right skewed. Mean>Median>Mode.
The mean is less than the median when the distribution of the data is left skewed. That is, Mean<Median<Mode.

From part a., the distribution of the data is left skewed. This indicates that median will be greater than the mean.

Inter quartile range:

In contrast to the range, which measures only differences between the extremes, the inter quartile range (also called mid spread) is the difference between the third quartile and the first quartile. Thus, it measures the variation in the middle 50 percent of the data, and, unlike the range, is not affected by extreme values. IQR=Q3−Q1

Thus, for a left skewed distribution median and IQR are the better summary statistics.

c.

Expert Solution

To determine

Describe the distribution with few sentences.

Explanation of Solution

Justification:

Histogram:

The graphical representation of classes of the quantitative data in the horizontal axis and class frequency in the vertical axis displayed in terms of bar is termed as histogram of the data and there is no possibility of gap is in between these bars of histogram.

Based on the number of peaks, the modality is classified into three types namely unimodal, bi-modal and multimodal.

Unimodal: The number of peak is one.

Bi-modal: The number of peak is two.

Multi-modal: The number of peak is three or more than three.

Here, the histogram has only one peak and hence it is unimodal with left skewed.

Moreover, the center of the distribution lies approximately 50 cents and it also contains of lowest price near 42 cents per pound and the highest price near 53 cents per pound.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Textbook Question

Chapter R, Problem 1.1RE

Bananas Here are the prices (in cents per pound) of bananas reported from 15 markets surveyed by the U.S. Department of Agriculture.

Chapter R, Problem 1.1RE, Bananas Here are the prices (in cents per pound) of bananas reported from 15 markets surveyed by the

a) Display these data with an appropriate graph.
b) Report appropriate summary statistics.
c) Write a few sentences about this distribution.

a.

Expert Solution

To determine

Construct appropriate graph for the data.

Answer to Problem 1.1RE

Output obtained from the MINITAB is given below:

Intro Stats, Books a la Carte Edition (5th Edition), Chapter R, Problem 1.1RE , additional homework tip 1

The distribution of banana prices reported by USDA tends to left skewed distribution.

Explanation of Solution

Given info:

The data represents the sample of 15 bananas price surveyed by the U.S Department of agriculture.

Calculation:

Software procedure:

Step by step procedure to draw the frequency histogram chart by using MINITAB software.

Choose Graph > Histogram.
Choose Simple, and then click OK.
In Graph variables, enter the corresponding column of data.
To modify the interval settings, double click on the horizontal axis of the graph. Then, select Labels > Specified. In this box, enter the values for the cut points of the bin intervals (42, 46, 50, 54)
In scale on y-axis, make click on frequency.
Click on ok.

Skew ness:

The data is said to be skewed if there is lack of symmetry and values fall on one side that is, either left or right of the distribution.

Left skewed:

If the tail on the distribution is elongated towards the left, more over it attains its horizontal axis rapidly than its peak then it is a left skewed distribution. It is also called negatively skewed.

The mean is less than the median when the distribution of the data is left skewed. That is, Mean<Median<Mode.

b.

Expert Solution

To determine

Determine the appropriate summary statistics for the given data.

Answer to Problem 1.1RE

Median and IQR is the appropriate summary statistics for the given data.

Explanation of Solution

Calculation:

Software procedure:

Step-by-step procedure to obtain summary statistics is given below.

Choose Stat > Basic Statistics > Display Descriptive Statistics.
In Variables, enter the columns Bananas
Choose Statistics and select the median and IQR.
Click OK.

Output obtained from the MINITAB is given below:

Intro Stats, Books a la Carte Edition (5th Edition), Chapter R, Problem 1.1RE , additional homework tip 2

From the output, the median is 49 cents per pound, and the interquartile range is 6 cents per pound.

Relationship between mean and median:

The value of mean is equal to the median when the distribution of the data is symmetric. Mean=Median=Mode.
The mean is greater than the median when the distribution of the data is right skewed. Mean>Median>Mode.
The mean is less than the median when the distribution of the data is left skewed. That is, Mean<Median<Mode.

From part a., the distribution of the data is left skewed. This indicates that median will be greater than the mean.

Inter quartile range:

In contrast to the range, which measures only differences between the extremes, the inter quartile range (also called mid spread) is the difference between the third quartile and the first quartile. Thus, it measures the variation in the middle 50 percent of the data, and, unlike the range, is not affected by extreme values. IQR=Q3−Q1

Thus, for a left skewed distribution median and IQR are the better summary statistics.

c.

Expert Solution

To determine

Describe the distribution with few sentences.

Explanation of Solution

Justification:

Histogram:

The graphical representation of classes of the quantitative data in the horizontal axis and class frequency in the vertical axis displayed in terms of bar is termed as histogram of the data and there is no possibility of gap is in between these bars of histogram.

Based on the number of peaks, the modality is classified into three types namely unimodal, bi-modal and multimodal.

Unimodal: The number of peak is one.

Bi-modal: The number of peak is two.

Multi-modal: The number of peak is three or more than three.

Here, the histogram has only one peak and hence it is unimodal with left skewed.

Moreover, the center of the distribution lies approximately 50 cents and it also contains of lowest price near 42 cents per pound and the highest price near 53 cents per pound.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

a.

Expert Solution

To determine

Construct appropriate graph for the data.

Answer to Problem 1.1RE

Output obtained from the MINITAB is given below:

Intro Stats, Books a la Carte Edition (5th Edition), Chapter R, Problem 1.1RE , additional homework tip 1

The distribution of banana prices reported by USDA tends to left skewed distribution.

Explanation of Solution

Given info:

The data represents the sample of 15 bananas price surveyed by the U.S Department of agriculture.

Calculation:

Software procedure:

Step by step procedure to draw the frequency histogram chart by using MINITAB software.

Choose Graph > Histogram.
Choose Simple, and then click OK.
In Graph variables, enter the corresponding column of data.
To modify the interval settings, double click on the horizontal axis of the graph. Then, select Labels > Specified. In this box, enter the values for the cut points of the bin intervals (42, 46, 50, 54)
In scale on y-axis, make click on frequency.
Click on ok.

Skew ness:

The data is said to be skewed if there is lack of symmetry and values fall on one side that is, either left or right of the distribution.

Left skewed:

If the tail on the distribution is elongated towards the left, more over it attains its horizontal axis rapidly than its peak then it is a left skewed distribution. It is also called negatively skewed.

The mean is less than the median when the distribution of the data is left skewed. That is, Mean<Median<Mode.

b.

Expert Solution

To determine

Determine the appropriate summary statistics for the given data.

Answer to Problem 1.1RE

Median and IQR is the appropriate summary statistics for the given data.

Explanation of Solution

Calculation:

Software procedure:

Step-by-step procedure to obtain summary statistics is given below.

Choose Stat > Basic Statistics > Display Descriptive Statistics.
In Variables, enter the columns Bananas
Choose Statistics and select the median and IQR.
Click OK.

Output obtained from the MINITAB is given below:

Intro Stats, Books a la Carte Edition (5th Edition), Chapter R, Problem 1.1RE , additional homework tip 2

From the output, the median is 49 cents per pound, and the interquartile range is 6 cents per pound.

Relationship between mean and median:

The value of mean is equal to the median when the distribution of the data is symmetric. Mean=Median=Mode.
The mean is greater than the median when the distribution of the data is right skewed. Mean>Median>Mode.
The mean is less than the median when the distribution of the data is left skewed. That is, Mean<Median<Mode.

From part a., the distribution of the data is left skewed. This indicates that median will be greater than the mean.

Inter quartile range:

In contrast to the range, which measures only differences between the extremes, the inter quartile range (also called mid spread) is the difference between the third quartile and the first quartile. Thus, it measures the variation in the middle 50 percent of the data, and, unlike the range, is not affected by extreme values. IQR=Q3−Q1

Thus, for a left skewed distribution median and IQR are the better summary statistics.

c.

Expert Solution

To determine

Describe the distribution with few sentences.

Explanation of Solution

Justification:

Histogram:

The graphical representation of classes of the quantitative data in the horizontal axis and class frequency in the vertical axis displayed in terms of bar is termed as histogram of the data and there is no possibility of gap is in between these bars of histogram.

Based on the number of peaks, the modality is classified into three types namely unimodal, bi-modal and multimodal.

Unimodal: The number of peak is one.

Bi-modal: The number of peak is two.

Multi-modal: The number of peak is three or more than three.

Here, the histogram has only one peak and hence it is unimodal with left skewed.

Moreover, the center of the distribution lies approximately 50 cents and it also contains of lowest price near 42 cents per pound and the highest price near 53 cents per pound.

Answer 8

a.

Expert Solution

To determine

Construct appropriate graph for the data.

Answer to Problem 1.1RE

Output obtained from the MINITAB is given below:

Intro Stats, Books a la Carte Edition (5th Edition), Chapter R, Problem 1.1RE , additional homework tip 1

The distribution of banana prices reported by USDA tends to left skewed distribution.

Explanation of Solution

Given info:

The data represents the sample of 15 bananas price surveyed by the U.S Department of agriculture.

Calculation:

Software procedure:

Step by step procedure to draw the frequency histogram chart by using MINITAB software.

Choose Graph > Histogram.
Choose Simple, and then click OK.
In Graph variables, enter the corresponding column of data.
To modify the interval settings, double click on the horizontal axis of the graph. Then, select Labels > Specified. In this box, enter the values for the cut points of the bin intervals (42, 46, 50, 54)
In scale on y-axis, make click on frequency.
Click on ok.

Skew ness:

The data is said to be skewed if there is lack of symmetry and values fall on one side that is, either left or right of the distribution.

Left skewed:

If the tail on the distribution is elongated towards the left, more over it attains its horizontal axis rapidly than its peak then it is a left skewed distribution. It is also called negatively skewed.

The mean is less than the median when the distribution of the data is left skewed. That is, Mean<Median<Mode.

Answer 9

a.

Expert Solution

Answer 10

a.

Expert Solution

Answer 11

Expert Solution

Answer 12

To determine

Construct appropriate graph for the data.

Answer 13

Answer to Problem 1.1RE

Output obtained from the MINITAB is given below:

Intro Stats, Books a la Carte Edition (5th Edition), Chapter R, Problem 1.1RE , additional homework tip 1

The distribution of banana prices reported by USDA tends to left skewed distribution.

Answer 14

Explanation of Solution

Given info:

The data represents the sample of 15 bananas price surveyed by the U.S Department of agriculture.

Calculation:

Software procedure:

Step by step procedure to draw the frequency histogram chart by using MINITAB software.

Choose Graph > Histogram.
Choose Simple, and then click OK.
In Graph variables, enter the corresponding column of data.
To modify the interval settings, double click on the horizontal axis of the graph. Then, select Labels > Specified. In this box, enter the values for the cut points of the bin intervals (42, 46, 50, 54)
In scale on y-axis, make click on frequency.
Click on ok.

Skew ness:

The data is said to be skewed if there is lack of symmetry and values fall on one side that is, either left or right of the distribution.

Left skewed:

If the tail on the distribution is elongated towards the left, more over it attains its horizontal axis rapidly than its peak then it is a left skewed distribution. It is also called negatively skewed.

The mean is less than the median when the distribution of the data is left skewed. That is, Mean<Median<Mode.

Answer 15

b.

Expert Solution

To determine

Determine the appropriate summary statistics for the given data.

Answer to Problem 1.1RE

Median and IQR is the appropriate summary statistics for the given data.

Explanation of Solution

Calculation:

Software procedure:

Step-by-step procedure to obtain summary statistics is given below.

Choose Stat > Basic Statistics > Display Descriptive Statistics.
In Variables, enter the columns Bananas
Choose Statistics and select the median and IQR.
Click OK.

Output obtained from the MINITAB is given below:

Intro Stats, Books a la Carte Edition (5th Edition), Chapter R, Problem 1.1RE , additional homework tip 2

From the output, the median is 49 cents per pound, and the interquartile range is 6 cents per pound.

Relationship between mean and median:

The value of mean is equal to the median when the distribution of the data is symmetric. Mean=Median=Mode.
The mean is greater than the median when the distribution of the data is right skewed. Mean>Median>Mode.
The mean is less than the median when the distribution of the data is left skewed. That is, Mean<Median<Mode.

From part a., the distribution of the data is left skewed. This indicates that median will be greater than the mean.

Inter quartile range:

In contrast to the range, which measures only differences between the extremes, the inter quartile range (also called mid spread) is the difference between the third quartile and the first quartile. Thus, it measures the variation in the middle 50 percent of the data, and, unlike the range, is not affected by extreme values. IQR=Q3−Q1

Thus, for a left skewed distribution median and IQR are the better summary statistics.

Answer 16

b.

Expert Solution

Answer 17

b.

Expert Solution

Answer 18

Expert Solution

Answer 19

To determine

Determine the appropriate summary statistics for the given data.

Answer 20

Answer to Problem 1.1RE

Median and IQR is the appropriate summary statistics for the given data.

Answer 21

Explanation of Solution

Calculation:

Software procedure:

Step-by-step procedure to obtain summary statistics is given below.

Choose Stat > Basic Statistics > Display Descriptive Statistics.
In Variables, enter the columns Bananas
Choose Statistics and select the median and IQR.
Click OK.

Output obtained from the MINITAB is given below:

Intro Stats, Books a la Carte Edition (5th Edition), Chapter R, Problem 1.1RE , additional homework tip 2

From the output, the median is 49 cents per pound, and the interquartile range is 6 cents per pound.

Relationship between mean and median:

The value of mean is equal to the median when the distribution of the data is symmetric. Mean=Median=Mode.
The mean is greater than the median when the distribution of the data is right skewed. Mean>Median>Mode.
The mean is less than the median when the distribution of the data is left skewed. That is, Mean<Median<Mode.

From part a., the distribution of the data is left skewed. This indicates that median will be greater than the mean.

Inter quartile range:

In contrast to the range, which measures only differences between the extremes, the inter quartile range (also called mid spread) is the difference between the third quartile and the first quartile. Thus, it measures the variation in the middle 50 percent of the data, and, unlike the range, is not affected by extreme values. IQR=Q3−Q1

Thus, for a left skewed distribution median and IQR are the better summary statistics.

Answer 22

c.

Expert Solution

To determine

Describe the distribution with few sentences.

Explanation of Solution

Justification:

Histogram:

The graphical representation of classes of the quantitative data in the horizontal axis and class frequency in the vertical axis displayed in terms of bar is termed as histogram of the data and there is no possibility of gap is in between these bars of histogram.

Based on the number of peaks, the modality is classified into three types namely unimodal, bi-modal and multimodal.

Unimodal: The number of peak is one.

Bi-modal: The number of peak is two.

Multi-modal: The number of peak is three or more than three.

Here, the histogram has only one peak and hence it is unimodal with left skewed.

Moreover, the center of the distribution lies approximately 50 cents and it also contains of lowest price near 42 cents per pound and the highest price near 53 cents per pound.

Answer 23

c.

Expert Solution

Answer 24

c.

Expert Solution

Answer 25

Expert Solution

Answer 26

To determine

Describe the distribution with few sentences.

Answer 27

Explanation of Solution

Justification:

Histogram:

The graphical representation of classes of the quantitative data in the horizontal axis and class frequency in the vertical axis displayed in terms of bar is termed as histogram of the data and there is no possibility of gap is in between these bars of histogram.

Based on the number of peaks, the modality is classified into three types namely unimodal, bi-modal and multimodal.

Unimodal: The number of peak is one.

Bi-modal: The number of peak is two.

Multi-modal: The number of peak is three or more than three.

Here, the histogram has only one peak and hence it is unimodal with left skewed.

Moreover, the center of the distribution lies approximately 50 cents and it also contains of lowest price near 42 cents per pound and the highest price near 53 cents per pound.