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Concept explainers
The following passages and associated questions are based on the material of Part VI
Taking an X Ray
Cathode Turret electrode
X rays are a very penetrating form of
FIGURE VI.1
A schematic view of an x-ray tube and a driver circuit is given in Figure VI.1. A filament warms the cathode, treeing electrons. These electrons are accelerated by the electric field established by a high-voltage power supply connected between the cathode and a metal target. The electrons accelerate in the direction of the target. The rapid deceleration when they strike the target generates x rays. Each electron will emit one or more x rays as it comes to rest.
An x-ray image is essentially a shadow; x rays darken the film where they pass, but the film stays unexposed, and thus light, where bones or dense tissues block x rays. An x-ray technician adjusts the quality of an image by adjusting the energy and the intensity of the x-ray beam. This is done by adjusting two parameters: the accelerating voltage and the current through the tube. The accelerating voltage determines the energy of the x-ray photons, which can't be greater than the energy of the electrons. The current through the tube determines the number of electrons per second and thus the number of photons emitted. In clinical practice, the exposure is characterized by two values: “kVp” and “mAs.” kVp is the peak voltage in kV. The value mAs is the product of the current (in mA) and the time (in s) to give a reading in mA · s. This is a measure of the total number of electrons that hit the target and thus the number of x rays emitted.
Typical values for a dental x ray are a kVp of 70 (meaning a peak voltage of 70 kV) and mAs of 7.5 (which comes from a current of 10 mA for 0.75 s, for a total of 7.5 mAs). Assume these values in all of the problem that follow.
What, physically, does the product of a current (in mA) and a time (in s) represent?
- A. Energy in mJ
- B. Potential difference in mV
- C. Charge in mC
- D. Resistance in mΩ
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Chapter P Solutions
College Physics: A Strategic Approach (4th Edition)
- Please please help me I will rate good for you even if it’s incorrect.arrow_forwardPart D: Conclusions 28. Do the experimentally determined capacitance measurements match the value marked? Are they close? 29. Would the capacitor discharge more quickly or more slowly if we had used a capacitor with a smaller value of capacitance? Explain. 30. Why does the capacitor charge almost instantly when the switch is closed? 31. Why does the capacitor discharge more slowly when the switch is opened compared to charging?arrow_forwardPlz solve within 30 min I will upvotearrow_forward
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