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Concept explainers
(a)
Interpretation:
The structure of the molecule hexanedinitrile is to be drawn.
Concept introduction:
The structure of a nitrile can be drawn on the basis of its IUPAC name as follows. The name consists of three parts, a prefix, a root, and a suffix. The suffix is ‘nitrile’. The root, which is the middle part of the name, shows the number of carbons in the longest continuous carbon chain that also contains the nitrile group. The nitrile carbon is a part of this chain. If the nitrile is attached to a ring, the nitrile carbon is not considered a part of the root. Any lower priority
(b)
Interpretation:
The structure of the molecule,
Concept introduction:
The structure of a nitrile can be drawn on the basis of its IUPAC name as follows. The name consists of three parts, a prefix, a root, and a suffix. The suffix is ‘nitrile’. The root, the middle part of the name shows the number of carbons in the longest continuous carbon chain that also contains the nitrile group. The nitrile carbon is a part of this chain. If the nitrile is attached to a ring, the nitrile carbon is not considered a part of the root. Any lower priority functional groups attached to this chain or ring are named in the prefix, with their locants. The numbering of the carbons in the root starts at the nitrile carbon if the root is an open chain. If the root is a ring, the carbon with the nitrile group is numbered 1, and the numbering continues in the direction that will give the lowest possible numbers to any substituent groups.
If the molecule contains a chiral carbon, the absolute configuration is specified at the start of the name. The configuration is shown using a dash/wedge representation so that the priority groups 1 to 3 are arranged in a clockwise direction with the lowest priority group pointing away from the observer for an R configuration. The three groups are arranged in counterclockwise direction with the lowest priority group pointing away from the observer for an S configuration. The respective directions are reversed if the lowest priority group is pointing toward the observer.
(c)
Interpretation:
The structure of
Concept introduction:
The structure of a nitrile can be drawn on the basis of its IUPAC name as follows. The name consists of three parts, a prefix, a root, and a suffix. The suffix is ‘nitrile’. The root, the middle part of the name shows the number of carbons in the longest continuous carbon chain that also contains the nitrile group. The nitrile carbon is a part of this chain. If the nitrile is attached to a ring, the nitrile carbon is not considered a part of the root. Any lower priority functional groups attached to this chain or ring are named in the prefix, with their locants. The numbering of the carbons in the root starts at the nitrile carbon if the root is an open chain. If the root is a ring, the carbon with the nitrile group is numbered 1, and the numbering continues in the direction that will give the lowest possible numbers to any substituents.
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Chapter F Solutions
Organic Chemistry: Principles And Mechanisms: Study Guide/solutions Manual (second)
- Please answer the question and provide a detailed drawing of the structure. If there will not be a new C – C bond, then the box under the drawing area will be checked. Will the following reaction make a molecule with a new C – C bond as its major product: Draw the major organic product or products, if the reaction will work. Be sure you use wedge and dash bonds if necessary, for example to distinguish between major products with different stereochemistry.arrow_forwardPlease do not use AI. AI cannot "see" the molecules properly, and it therefore gives the wrong answer while giving incorrect descriptions of the visual images we're looking at. All of these compounds would be produced (I think). In my book, I don't see any rules about yield in this case, like explaining that one product would be present in less yield for this reason or that reason. Please explain why some of these produce less yield than others.arrow_forwardPlease answer the question and provide detailed explanations.arrow_forward
- All of these compounds would be produced (I think). In my book, I don't see any rules about yield in this case, like explaining that one product would be present in less yield for this reason or that reason. Please explain why some of these produce less yield than others.arrow_forward5. Fill in the missing molecules in the following reaction pathway. TMSO Heat + CI then HF O₂N (1.0 equiv) AICI 3 OMearrow_forwarde. O₂N NO2 1. excess H2, Pd/C 2. excess NaNO2, HCI 3. excess CuCNarrow_forward
- Help with a periodic table task.' Procedure Part 1: Customizing a Periodic Table Use a textbook or other valid source to determine which elements are metals, nonmetals, metalloids (called semimetals in some texts), alkali metals, alkaline earth metals, transition metals, halogens, and noble gases. Download and print a copy of the Periodic Table of Elements. Use colored pencils, colorful highlighters, or computer drawing tools to devise a schematic for designating each of the following on the periodic table: Group numbers Period number Labels for these groups: alkali metals, alkaline earth metals, transition metals, inner transition metals (lanthanides and actinides), other metals, metalloids (semimetals), other nonmetals, halogens, and noble gases Metals, nonmetals, and metalloids Note: Write the group and period numbers and color/highlight each element for categorization. Be sure to include a key for the schematic. Take a photo of the completed periodic table and upload the…arrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forwardCan you explain these two problems for mearrow_forward
- 个 ^ Blackboard x Organic Chemistry II Lecture (m x Aktiv Learning App x → C app.aktiv.com ← Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. Problem 28 of 35 :OH H HH KO Select to Edit Arrows CH CH₂OK, CH CH2OH 5+ H :0: Donearrow_forwardCan you explain those two problems for me please.arrow_forwardDo we need to draw the "ethyne" first for this problem? im confusedarrow_forward
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