Concept explainers
(a)
Interpretation:
For the given molecule, the complete IUPAC name, is to be written.
Concept introduction:
To write the IUPAC name, first, it is important to determine the highest-priority functional group present that requires a suffix referring to Table E-1. For the molecules having two or more highest-priority
The main chain or ring containing the highest-priority functional group is to be determined. The next step is to number the main chain or ring such that carbon atoms involving the highest-priority functional group receive the lowest possible numbers. The locator number for the highest-priority functional group is written immediately before the suffix unless needed. All other functional groups in the molecule are treated as substituents and appear in the name as a prefix. Prefixes like ‘di’, ‘tri’, ‘tetra’… etc. are used to indicate the number of identical substituents attached. The substituents are written in an alphabetical order.
(b)
Interpretation:
For the given molecule, the complete IUPAC name, is to be written.
Concept introduction:
To write the IUPAC name, first, it is important to determine the highest-priority functional group present that requires a suffix referring to Table E-1. For the molecules having two or more highest-priority functional groups, the rules are slightly different. In the IUPAC name of such molecules, the final ‘e’ of ‘ane’, ‘ene’, or ‘yne’ is not removed in the suffix. Prefixes like ‘di’, ‘tri, etc are written immediately before the suffix to specify the number of highest-priority functional groups. Add a locator number for each of the highest-priority functional groups immediately before the prefixes.
The main chain or ring containing the highest-priority functional group is to be determined. The next step is to number the main chain or ring such that carbon atoms involving the highest-priority functional group receive the lowest possible numbers. The locator number for the highest-priority functional group is written immediately before the suffix unless needed. All other functional groups in the molecule are treated as substituents and appear in the name as a prefix. Prefixes such as ‘di’, ‘tri’, ‘tetra’… etc. are used to indicate the number of identical substituents attached. The substituents are written in an alphabetical order.
(c)
Interpretation:
For the given molecule, the complete IUPAC name of is to be written.
Concept introduction:
To write the IUPAC name, first, it is important to determine the highest-priority functional group present that requires a suffix referring to Table E-1. For the molecules having two or more highest-priority functional groups, the rules are slightly different. In the IUPAC name of such molecules, the final ‘e’ of ‘ane’, ‘ene’, or ‘yne’ is not removed in the suffix. Prefixes such as ‘di’, ‘tri, etc are written immediately before the suffix to specify the number of highest-priority functional groups. Add a locator number for each of the highest-priority functional groups immediately before the prefixes.
The main chain or ring containing the highest-priority functional group is to be determined. The next step is to number the main chain or ring such that carbon atoms involving the highest-priority functional group receive the lowest possible numbers. The locator number for the highest-priority functional group is written immediately before the suffix unless needed. All other functional groups in the molecule are treated as substituents and appear in the name as a prefix. Prefixes like ‘di’, ‘tri’, ‘tetra’… etc. are used to indicate the number of identical substituents attached. The substituents are written in an alphabetical order.

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Chapter E Solutions
EBK GET READY FOR ORGANIC CHEMISTRY
- If we have the equation 3 ln0 = 2t. What is the value of t?arrow_forward1 N2H4 (l) + 3 O2(g) > 2 NO2 (g) + 2 H2O (g) If 75.0 kg of hydrazine are reacted with 75.0 kg of oxygen, which is the limiting reactant?arrow_forwardPQ-10. What is the major product of this reaction? (A) (C) 930 Me HO O=S=O O-8-CF, C 어 Me H+ OH 270 O 0-5-0 O=S=O O-S-CF CF3 2arrow_forward
- Predict the major organic product(s) of the following reactions. Include stereochemistry when necessary. Write NR if no reaction, try to explain.arrow_forwardQ2: Explain why epoxides that react in an SN1 manner will not show any stereochemical inversion in the product. Q3: Rationalize why Alcohol B will react under the indicated reaction conditions, but Alcohol A will not. A ☑ OH B OH PBr3 R-Brarrow_forwardQ1: Predict the major organic product(s) of the following reactions. Include stereochemistry when necessary. Write NR if no reaction, try to explain. 1.) LDA, THF 2.) СОН CI OH H2SO4, heat OH m...... OH 1.) PCC, CH2Cl2 2.) CH3CH2MgBr, THF 3.) H3O+ 4.) TsCl, pyr 5.) tBuOK, tBuOH 1.) SOCI 2, CHCI 3 2.) CH3CH2ONA, DMF OH 1.) HBr 2.) Mg, THF 3.) H₂CO, THE 4.) H3O+ OH NaH, THFarrow_forward
- Problem 6-29 Identify the functional groups in the following molecules, and show the polarity of each: (a) CH3CH2C=N CH, CH, COCH (c) CH3CCH2COCH3 NH2 (e) OCH3 (b) (d) O Problem 6-30 Identify the following reactions as additions, eliminations, substitutions, or rearrangements: (a) CH3CH2Br + NaCN CH3CH2CN ( + NaBr) Acid -OH (+ H2O) catalyst (b) + (c) Heat NO2 Light + 02N-NO2 (+ HNO2) (d)arrow_forwardPredict the organic product of Y that is formed in the reaction below, and draw the skeletal ("line") structures of the missing organic product. Please include all steps & drawings & explanations.arrow_forwardPlease choose the best reagents to complete the following reactionarrow_forward
