(a)
Interpretation:
The structure of the molecule that corresponds to the IUPAC name
Concept introduction:
The IUPAC name of a compound consists of three parts, prefix, root, and suffix. The root is the longest continuous carbon chain or the largest ring that bears the highest priority functional group. The suffix refers to the highest priority functional group. The functional group name suffix replaces the last ‘e’ in the root alkyl/aryl name. The root chain or ring carbons are numbered so that the highest priority group gets the lowest possible location numbers. The number is inserted between the root and the suffix unless redundant. Any other, low priority
The suffix ‘ol’ refers to the alcohol functional group. The suffix ‘amino’ refers to the
(b)
Interpretation:
The structure of the molecule that corresponds to the IUPAC name
Concept introduction:
IUPAC name of a compound consists of three parts, prefix, root, and suffix. The root is the longest continuous carbon chain or the largest ring that bears the highest priority functional group. The suffix refers to the highest priority functional group. The functional group name suffix replaces the last ‘e’ in the root alkyl/aryl name. The root chain or ring carbons are numbered so that the highest priority group gets the lowest possible location numbers. The number is inserted between the root and the suffix unless redundant. Any other low priority functional groups are listed alphabetically in the prefix, along with the location numberss. A prefix di, tri, etc. is used in case two or more instances of the functional group are present.
The suffix ‘ol’ refers to the alcohol functional group. The suffix ‘amino’ refers to the amine functional group.
(c)
Interpretation:
The structure of the molecule that corresponds to the IUPAC name
Concept introduction:
IUPAC name of a compound consists of three parts, prefix, root, and suffix. The root is the longest continuous carbon chain or the largest ring that bears the highest priority functional group. The suffix refers to the highest priority functional group. The functional group name suffix replaces the last ‘e’ in the root alkyl/aryl name. The root chain or ring carbons are numbered so that the highest priority group gets the lowest possible location numbers. The number is inserted between the root and the suffix unless redundant. Any other low priority functional groups are listed alphabetically in the prefix, along with the location numbers. A prefix di, tri, etc. is used in case two or more instances of the functional group are present.
The suffix ‘ol’ refers to the alcohol functional group. The suffix ‘amino’ refers to the amine functional group.
(d)
Interpretation:
The structure of the molecule that corresponds to the IUPAC name
Concept introduction:
IUPAC name of a compound consists of three parts, prefix, root. and suffix. The root is the longest continuous carbon chain or the largest ring that bears the highest priority functional group. The suffix refers to the highest priority functional group. The functional group name suffix replaces the last ‘e’ in the root alkyl/aryl name. The root chain or ring carbons are numbered so that the highest priority group gets the lowest possible location numbers. The number is inserted between the root and the suffix unless redundant. Any other, low priority functional groups are listed alphabetically in the prefix, along with the location numbers. A prefix di, tri, etc. is used in case two or more instances of the functional group are present.
The suffix ‘ol’ refers to the alcohol functional group. The suffix ‘amino’ refers to the amine functional group.

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Chapter E Solutions
Organic Chemistry: Principles And Mechanisms
- A solution of 14 g of a nonvolatile, nonelectrolyte compound in 0.10 kg of benzene boils at 81.7°C. If the BP of pure benzene is 80.2°C and the K, of benzene is 2.53°C/m, calculate the molar mass of the unknown compound. AT₁ = Km (14)arrow_forwardPlease help me answer the following questions. My answers weren't good enough. Need to know whyy the following chemicals were not used in this experiment related to the melting points and kf values. For lab notebook not a graded assignments.arrow_forwardDraw the arrow pushing reaction mechanism. DO NOT ANSWER IF YOU WONT DRAW IT. Do not use chat gpt.arrow_forward
- Complete the following esterification reaction by drawing the structural formula of the product formed. HOH HO i catalyst catalyst OH HO (product has rum flavor) (product has orange flavor)arrow_forwardThe statements in the tables below are about two different chemical equilibria. The symbols have their usual meaning, for example AG stands for the standard Gibbs free energy of reaction and K stands for the equilibrium constant. In each table, there may be one statement that is faise because it contradicts the other three statements. If you find a false statement, check the box next to t Otherwise, check the "no false statements" box under the table. statement false? AG"1 no false statements: statement false? AG-0 0 InK-0 0 K-1 0 AH-TAS no false statements 2arrow_forwardComplete the following esterification reactions by drawing the line formulas of the carboxylic acid and alcohol required to form the ester shown. catalyst catalyst catalyst apricot fragrancearrow_forward
- Show the saponification products of the following ester: You don't need to draw in the Na+ cation. catalyst, A catalyst, A catalyst, Aarrow_forwardWhat would happen if the carboxylic acid and alcohol groups were on the same molecule? In essence, the molecule reacts with itself. Draw the structure of the products formed in this manner using the reactants below. If two functional groups interact with one another on the same molecule, this is called an “intramolecular" (within one) rather than "intermolecular" (between two or more) attack. OH OH catalyst OH HO catalyst catalyst HO OHarrow_forwardQ3: Write in the starting alkyl bromide used to form the following products. Include any reactants, reagents, and solvents over the reaction arrow. If more than one step is required, denote separate steps by using 1), 2), 3), etc. H OH racemic OH OH 5 racemicarrow_forward
- Draw the Lewis structure of the SO3-O(CH3)2 complex shown in the bottom right of slide 2in lecture 3-3 (“Me” means a CH3 group) – include all valence electron pairs and formal charges.From this structure, should the complex be a stable molecule? Explain.arrow_forwardPredict all organic product(s), including stereoisomers when applicable.arrow_forwardQ5: Propose a reasonable synthesis for the following decalin derivative. using only decalin and alkanes of 3 or fewer carbons. Decalin H3C HO க CH3arrow_forward
- Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning
