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Concept explainers
(a)
Interpretation:
The complete IUPAC name of the given molecule is to be written.
Concept introduction:
When assigning priorities to substituents, the atom having the greater
If substituents are attached by the same atom, the tiebreaker is applied.
For each substituent, the set of three atoms one bond away from its point of attachment is to be identified.
In each set, arrange the three atoms from the highest to the lowest priority. Compare each set’s highest-priority atom.
If they are different, then the atom that has the higher priority corresponds to the higher-priority substituent.
If the highest-priority atoms from each set are identical, then compare each set’s second highest priority corresponding to the higher priority substituent. If the second-highest-priority atoms from each set are identical, then compare each set’s lowest-priority atom to break the tie.
When the fourth priority substituent is pointing away (it is attached by a dash bond) and the first, second, and third priority substituents are arranged clockwise, the configuration is R.
When the fourth priority substituent is pointing away (it is attached by a dash bond) and the first, second, and third priority substituents are arranged counterclockwise, the configuration is S.
If the fourth priority substituent is attached by a wedge bond, then the clockwise or counterclockwise arrangement of the first, second, and third priority substituents is determined, and that arrangement is reversed before assigning R or S.
If the fourth priority substituent is in the plane of the page, then it is switched with the substituent that points away. Then the clockwise or counterclockwise arrangement of the first, second, and third priority substituents is determined, and that arrangement is reversed before assigning R or S.
When writing the IPUAC name, the R or S designation is written in parenthesis for each asymmetric carbon atom, and hyphens are used to separate those designations from the rest of the IUPAC name. Alternatively, all R and S designations can be placed together at the front of the name.
(b)
Interpretation:
The complete IUPAC name of the given molecule is to be written.
Concept introduction:
When assigning priorities to substituents, the atom having the greater atomic number has the higher priority. In case of comparison between isotopes, the one having the greater atomic mass gets the higher priority.
If substituents are attached by the same atom, the tiebreaker is applied.
For each substituent, the set of three atoms one bond away from its point of attachment is to be identified.
In each set, arrange the three atoms from the highest to the lowest priority. Compare each set’s highest-priority atom.
If they are different, then the atom that has the higher priority corresponds to the higher-priority substituent.
If the highest-priority atoms from each set are identical, then compare each set’s second highest priority corresponding to the higher priority substituent. If the second-highest-priority atoms from each set are identical, then compare each set’s lowest-priority atom to break the tie.
When the fourth priority substituent is pointing away (it is attached by a dash bond) and the first, second, and third priority substituents are arranged clockwise, the configuration is R.
When the fourth priority substituent is pointing away (it is attached by a dash bond) and the first, second, and third priority substituents are arranged counterclockwise, the configuration is S.
If the fourth priority substituent is attached by a wedge bond, then the clockwise or counterclockwise arrangement of the first, second, and third priority substituents is determined, and that arrangement is reversed before assigning R or S.
If the fourth priority substituent is in the plane of the page, then it is switched with the substituent that points away. Then the clockwise or counterclockwise arrangement of the first, second, and third priority substituents is determined, and that arrangement is reversed before assigning R or S.
When writing the IPUAC name, the R or S designation is written in parenthesis for each asymmetric carbon atom, and hyphens are used to separate those designations from the rest of the IUPAC name. Alternatively, all R and S designations can be placed together at the front of the name.
(c)
Interpretation:
The complete IUPAC name of the given molecule is to be written.
Concept introduction:
When assigning priorities to substituents, the atom having the greater atomic number has the higher priority. In case of comparison between isotopes, the one having the greater atomic mass gets the higher priority.
If substituents are attached by the same atom, the tiebreaker is applied.
For each substituent, the set of three atoms one bond away from its point of attachment is to be identified.
In each set, arrange the three atoms from the highest to the lowest priority. Compare each set’s highest-priority atom.
If they are different, then the atom that has the higher priority corresponds to the higher-priority substituent.
If the highest-priority atoms from each set are identical, then compare each set’s second highest priority corresponding to the higher priority substituent. If the second-highest-priority atoms from each set are identical, then compare each set’s lowest-priority atom to break the tie.
When the fourth priority substituent is pointing away (it is attached by a dash bond) and the first, second, and third priority substituents are arranged clockwise, the configuration is R.
When the fourth priority substituent is pointing away (it is attached by a dash bond) and the first, second, and third priority substituents are arranged counterclockwise, the configuration is S.
If the fourth priority substituent is attached by a wedge bond, then the clockwise or counterclockwise arrangement of the first, second, and third priority substituents is determined, and that arrangement is reversed before assigning R or S.
If the fourth priority substituent is in the plane of the page, then it is switched with the substituent that points away. Then the clockwise or counterclockwise arrangement of the first, second, and third priority substituents is determined, and that arrangement is reversed before assigning R or S.
When writing the IPUAC name, the R or S designation is written in parenthesis for each asymmetric carbon atom, and hyphens are used to separate those designations from the rest of the IUPAC name. Alternatively, all R and S designations can be placed together at the front of the name.
(d)
Interpretation:
The complete IUPAC name of the given molecule is to be written.
Concept introduction:
When assigning priorities to substituents, the atom having the greater atomic number has the higher priority. In case of comparison between isotopes, the one having the greater atomic mass gets the higher priority.
If substituents are attached by the same atom, the tiebreaker is applied.
For each substituent, the set of three atoms one bond away from its point of attachment is to be identified.
In each set, arrange the three atoms from the highest to the lowest priority. Compare each set’s highest-priority atom.
If they are different, then the atom that has the higher priority corresponds to the higher-priority substituent.
If the highest-priority atoms from each set are identical, then compare each set’s second highest priority corresponding to the higher priority substituent. If the second-highest-priority atoms from each set are identical, then compare each set’s lowest-priority atom to break the tie.
When the fourth priority substituent is pointing away (it is attached by a dash bond) and the first, second, and third priority substituents are arranged clockwise, the configuration is R.
When the fourth priority substituent is pointing away (it is attached by a dash bond) and the first, second, and third priority substituents are arranged counterclockwise, the configuration is S.
If the fourth priority substituent is attached by a wedge bond, then the clockwise or counterclockwise arrangement of the first, second, and third priority substituents is determined, and that arrangement is reversed before assigning R or S.
If the fourth priority substituent is in the plane of the page, then it is switched with the substituent that points away. Then the clockwise or counterclockwise arrangement of the first, second, and third priority substituents is determined, and that arrangement is reversed before assigning R or S.
When writing the IPUAC name, the R or S designation is written in parenthesis for each asymmetric carbon atom, and hyphens are used to separate those designations from the rest of the IUPAC name.
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Chapter C Solutions
EBK ORGANIC CHEMISTRY: PRINCIPLES AND M
- Draw the Lewis structure of C2H4Oarrow_forwarda) 5. Circle all acidic (and anticoplanar to the Leaving group) protons in the following molecules, Solve these elimination reactions, and identify the major and minor products where appropriate: 20 points + NaOCH3 Br (2 productarrow_forwardNonearrow_forward
- Dr. Mendel asked his BIOL 260 class what their height was and what their parent's heights were. He plotted that data in the graph below to determine if height was a heritable trait. A. Is height a heritable trait? If yes, what is the heritability value? (2 pts) B. If the phenotypic variation is 30, what is the variation due to additive alleles? (2 pts) Offspring Height (Inches) 75 67.5 60 52.5 y = 0.9264x + 4.8519 55 60 65 MidParent Height (Inches) 70 75 12pt v V Paragraph B IUA > AT2 v Varrow_forwardExperiment: Each team will be provided with 5g of a mixture of acetanilide and salicylic acid. You will divide it into three 1.5 g portions in separate 125 mL Erlenmeyer flasks savıng some for melting point analysis. Dissolve the mixture in each flask in ~60mL of DI water by heating to boiling on a hotplate. Take the flasks off the hotplate once you have a clear solution and let them stand on the bench top for 5 mins and then allow them to cool as described below. Sample A-Let the first sample cool slowly to room temperature by letting it stand on your lab bench, with occasional stirring to promote crystallization. Sample B-Cool the second sample 1n a tap-water bath to 10-15 °C Sample C-Cool the third sample in an ice-bath to 0-2 °C Results: weight after recrystalization and melting point temp. A=0.624g,102-115° B=0.765g, 80-105° C=1.135g, 77-108 What is the percent yield of A,B, and C.arrow_forwardRel. Intensity Q 1. Which one of the following is true of the compound whose mass spectrum is shown here? Explain how you decided. 100 a) It contains chlorine. b) It contains bromine. c) It contains neither chlorine nor bromine. 80- 60- 40- 20- 0.0 0.0 TT 40 80 120 160 m/z 2. Using the Table of IR Absorptions how could you distinguish between these two compounds in the IR? What absorbance would one compound have that the other compound does not? HO CIarrow_forward
- Illustrate reaction mechanisms of alkenes with water in the presence of H2SO4, detailing each step of the process. Please show steps of processing. Please do both, I will thumb up for sure #1 #3arrow_forwardDraw the following molecule: (Z)-1-chloro-1-butenearrow_forwardIdentify the molecule as having a(n) E, Z, cis, or trans configuration. CH3 H₁₂C ○ E ○ z ○ cis transarrow_forward
- Identify the molecule as having a(n) E, Z, cis, or trans configuration. H₂C- CH3 О Е ○ cis ○ transarrow_forwardThe decomposition of dinitrogen pentoxide according to the equation: 50°C 2 N2O5(g) 4 NO2(g) + O2(g) follows first-order kinetics with a rate constant of 0.0065 s-1. If the initial concentration of N2O5 is 0.275 M, determine: the final concentration of N2O5 after 180 seconds. ...arrow_forwardDon't used hand raitingarrow_forward
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