Concept explainers
(a)
Interpretation:
The configuration of each stereo center in the given molecule is to be designated as R or S.
Concept introduction:
When assigning priorities to substituents, the atom having the greater
When the fourth priority substituent is pointing away (it is attached by a dash bond) and the first, second, and third priority substituents are arranged clockwise, the configuration is R.
When the fourth priority substituent is pointing away (it is attached by a dash bond) and the first, second, and third priority substituents are arranged counterclockwise, the configuration is S.
If the fourth priority substituent is attached by a wedge bond, then the clockwise or counterclockwise arrangement of the first, second, and third priority substituents is determined and that arrangement is reversed before assigning R or S.
If the fourth priority substituent is in the plane of the page, then it is switched with the substituent that points away. Then the clockwise or counterclockwise arrangement of the first, second, and third priority substituents is determined and that arrangement is reversed before assigning R or S.
(b)
Interpretation:
The configuration of each stereo center in the given molecule is to be designated as R or S.
Concept introduction:
When assigning priorities to substituents, the atom having the greater atomic number has higher priority. In case of comparison between isotopes, the one having the greater atomic mass gets higher priority.
When the fourth priority substituent is pointing away (it is attached by a dash bond) and the first, second, and third priority substituents are arranged clockwise, the configuration is R.
When the fourth priority substituent is pointing away (it is attached by a dash bond) and the first, second, and third priority substituents are arranged counterclockwise, the configuration is S.
If the fourth priority substituent is attached by a wedge bond, then the clockwise or counterclockwise arrangement of the first, second, and third priority substituent is determined and that arrangement is reversed before assigning R or S.
If the fourth priority substituent is in the plane of the page, then it is switched with the substituent that points away. Then the clockwise or counterclockwise arrangement of the first, second, and third priority substituents is determined and that arrangement is reversed before assigning R or S.
(c)
Interpretation:
The configuration of each stereo center in the given molecule is to be designated as R or S.
Concept introduction:
When assigning priorities to substituents, the atom having the greater atomic number has higher priority. In case of comparison between isotopes, the one having the greater atomic mass gets higher priority.
When the fourth priority substituent is pointing away (it is attached by a dash bond) and the first, second, and third priority substituents are arranged clockwise, the configuration is R.
When the fourth priority substituent is pointing away (it is attached by a dash bond) and the first, second, and third priority substituents are arranged counterclockwise, the configuration is S.
If the fourth priority substituent is attached by a wedge bond, then the clockwise or counterclockwise arrangement of the first, second, and third priority substituents is determined and that arrangement is reversed before assigning R or S.
If the fourth priority substituent is in the plane of the page, then it is switched with the substituent that points away. Then the clockwise or counterclockwise arrangement of the first, second, and third priority substituents is determined and that arrangement is reversed before assigning R or S.
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Chapter C Solutions
EBK ORGANIC CHEMISTRY: PRINCIPLES AND M
- Write the electron configuration of an atom of the element highlighted in this outline of the Periodic Table: 1 23 4 5 6 7 He Ne Ar Kr Xe Rn Hint: you do not need to know the name or symbol of the highlighted element! ☐arrow_forwardCompare these chromatograms of three anti-psychotic drugs done by HPLC and SFC. Why is there the difference in separation time for SFC versus HPLC? Hint, use the Van Deemter plot as a guide in answering this question. Why, fundamentally, would you expect a faster separation for SFC than HPLC, in general?arrow_forwardA certain inorganic cation has an electrophoretic mobility of 5.27 x 10-4 cm2s-1V-1. The same ion has a diffusion coefficient of 9.5 x 10-6cm2s-1. If this ion is separated from cations by CZE with a 75cm capillary, what is the expected plate count, N, at an applied voltage of 15.0kV? Under these separation conditions, the electroosmotic flow rate was 0.85mm s-1 toward the cathode. If the detector was 50.0cm from the injection end of the capillary, how long would it take in minutes for the analyte cation to reach the detector after the field was applied?arrow_forward
- 2.arrow_forwardPlease solve for the following Electrochemistry that occursarrow_forwardCommercial bleach contains either chlorine or oxygen as an active ingredient. A commercial oxygenated bleach is much safer to handle and less likely to ruin your clothes. It is possible to determine the amount of active ingredient in an oxygenated bleach product by performing a redox titration. The balance reaction for such a titration is: 6H+ +5H2O2 +2MnO4- à 5O2 + 2Mn2+ + 8H2O If you performed the following procedure: “First, dilute the Seventh Generation Non-Chlorine Bleach by pipetting 10 mL of bleach in a 100 mL volumetric flask and filling the flask to the mark with distilled water. Next, pipet 10 mL of the diluted bleach solution into a 250 mL Erlenmeyer flask and add 20 mL of 1.0 M H2SO4 to the flask. This solution should be titrated with 0.0100 M KMnO4 solution.” It took 18.47mL of the KMnO4 to reach the endpoint on average. What was the concentration of H2O2 in the original bleach solution in weight % assuming the density of bleach is 1g/mL?arrow_forward
- 10.arrow_forwardProper care of pH electrodes: Why can you not store a pH electrode in distilled water? What must you instead store it in? Why?arrow_forwardWrite the electron configuration of an atom of the element highlighted in this outline of the Periodic Table: 1 23 4 569 7 He Ne Ar Kr Xe Rn Hint: you do not need to know the name or symbol of the highlighted element! §arrow_forward
- Identify the amino acids by name. Illustrate a titration curve for this tetrapeptide indicating the pKa's for each ionizable groups and identify the pI for this tetrapeptide. please helparrow_forward↓ ina xSign x Sign X labs X Intro X Cop Xa chat X My Cx Grac X Laur x Laur xash learning.com/ihub/assessment/f188d950-dd73-11e0-9572-0800200c9a66/d591b3f2-d5f7-4983-843c-0d00c1c0340b/f2b47861-07c4-4d1b-a1ee-e7db2 +949 pts /3400 K Question 16 of 34 > © Macmillan Learning Draw the major E2 reaction product formed when cis-1-chloro-2-ethylcyclohexane (shown) reacts with hydroxide ion in DMSO. H CH2CH3 H H HO- H H H Cl DMSO H H C Select Draw Templates More C H 0 2 Erasearrow_forwardA common buffer for stabilizing antibodies is 100 mM Histidine at pH 7.0. Describe the preparation of this buffer beginning with L-Histidine monohydrochloride monohydrate and 1 M NaOH. Be certain to show the buffering reaction that includes the conjugate acid and base.arrow_forward
Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning