Business Driven Technology
7th Edition
ISBN: 9781259567322
Author: Paige Baltzan Instructor
Publisher: McGraw-Hill Education
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Chapter B, Problem B9.10MBD
Explanation of Solution
Benefits from Box.net:
- It allows to store the documents, media file and all of online content.
- So, student can easily access, handle and contribute them from anywhere.
- Combine Box.net with Google apps and salesforce.
- Student can connect Box.net on mobile devices.
- File sharing is secure
- Sharing the file using link within or outside of the company.
- Full-recommended cooperation
- Make an online workstation
- To share project files.
- To manage files with version and history.
- To create new content.
- Make an online workstation
Challenges of using Box.net:
- Security concerns
- The service provider necessities to need a robust security protocol and firewalls in order to avoid any malware...
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#include
int main (void)
{
int i, *p, count
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p
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for (i = 5; i >= 0; i--) {
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1. [20 pts] What is the output of the program? Please explain why.
2. [15 pts] What is the gdb command to set a breakpoint in line 6 (p
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Please run and debug the following program and answer the questions.
(OnlineGDB)
#include <stdio.h>int main(void) {int a;char *s;int v0 = 4, v1 = 5, v2 = 6, v3 = 1, v4 = 2;printf("Exercise 1:\n====================\n");switch(v0) {case 0: printf("Hello October\n"); break;case 1: printf("Go Kean!\n"); break;case 2: printf("Academic Building Center \n"); break;case 3: printf("UNION \n"); break;case 4: printf("Go ");case 5: printf("Kean! \n");default: printf("Have a great semester! \n"); break;}for(a=5; a<v1; a++) {printf("Kean");}printf("\n");if (v2 == 6) {s = "Go";}else {s = "Hello";}if(v3 != v4) {printf("%s Kean!\n",s);} else {printf("%s Computer Science!\n",s);}return 0;}
Assume the following codes are added between line 36 (}) and line 38 (return 0;) v0>0 ? ++v1, ++v2 : --v3; Please give the values of v0, v1, v2, v3, and v4 after this line and explain the reason. You can test the program to verify your answer if you like.
Chapter B Solutions
Business Driven Technology
Ch. B - Prob. B1.1MBDCh. B - Prob. B1.2MBDCh. B - Prob. B1.3MBDCh. B - Prob. B1.4MBDCh. B - Prob. B1.5MBDCh. B - Prob. B1.6MBDCh. B - Prob. B2.1MBDCh. B - Modeling a Business Process Do you hate waiting in...Ch. B - Prob. B2.3MBDCh. B - Prob. B2.4MBD
Ch. B - Prob. B2.5MBDCh. B - Prob. B3.1MBDCh. B - Prob. B3.2MBDCh. B - Prob. B4.1MBDCh. B - Prob. B4.2MBDCh. B - Prob. B4.3MBDCh. B - Prob. B4.4MBDCh. B - Prob. B4.5MBDCh. B - Prob. B4.6MBDCh. B - Prob. B4.7MBDCh. B - Prob. B4.8MBDCh. B - Prob. B4.9MBDCh. B - Prob. B4.10MBDCh. B - Prob. B4.11MBDCh. B - Prob. B5.1MBDCh. B - Prob. B5.2MBDCh. B - Prob. B5.3MBDCh. B - Prob. B5.4MBDCh. B - Prob. B5.5MBDCh. B - Prob. B5.6MBDCh. B - Prob. B6.1MBDCh. B - Prob. B6.2MBDCh. B - Prob. B6.3MBDCh. B - Prob. B6.4MBDCh. B - Prob. B6.5MBDCh. B - Prob. B7.1MBDCh. B - Prob. B7.2MBDCh. B - Prob. B7.3MBDCh. B - Prob. B7.4MBDCh. B - Prob. B7.5MBDCh. B - Prob. B7.6MBDCh. B - Prob. B7.7MBDCh. B - Prob. B7.8MBDCh. B - Prob. B7.9MBDCh. B - Prob. B7.10MBDCh. B - Prob. B7.11MBDCh. B - Prob. B8.1MBDCh. B - Prob. B8.2MBDCh. B - Prob. B9.1MBDCh. B - Prob. B9.2MBDCh. B - Prob. B9.3MBDCh. B - Prob. B9.4MBDCh. B - Prob. B9.5MBDCh. B - Prob. B9.6MBDCh. B - Prob. B9.7MBDCh. B - Prob. B9.8MBDCh. B - Prob. B9.9MBDCh. B - Prob. B9.10MBDCh. B - Prob. B10.1MBDCh. B - Prob. B10.2MBDCh. B - Prob. B10.3MBDCh. B - Prob. B10.4MBDCh. B - Prob. B10.5MBDCh. B - Prob. B11.1MBDCh. B - Prob. B11.2MBDCh. B - Prob. B11.3MBDCh. B - Prob. B11.4MBDCh. B - Prob. B12.1MBDCh. B - Prob. B12.2MBDCh. B - Prob. B12.3MBDCh. B - Prob. B12.4MBDCh. B - Prob. B12.5MBDCh. B - Prob. B12.6MBD
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- #include <stdio.h>int main(void) {int a;char *s;int v0 = 4, v1 = 5, v2 = 6, v3 = 1, v4 = 2;printf("Exercise 1:\n====================\n");switch(v0) {case 0: printf("Hello October\n"); break;case 1: printf("Go Kean!\n"); break;case 2: printf("Academic Building Center \n"); break;case 3: printf("UNION \n"); break;case 4: printf("Go ");case 5: printf("Kean! \n");default: printf("Have a great semester! \n"); break;}for(a=5; a<v1; a++) {printf("Kean");}printf("\n");if (v2 == 6) {s = "Go";}else {s = "Hello";}if(v3 != v4) {printf("%s Kean!\n",s);} else {printf("%s Computer Science!\n",s);}return 0;} Output: Exercise 1:====================Go Kean! Have a great semester! Go Kean! Please only modify the initial value of v0, v1, v2, v3 and v4 to get the following output. Youneed to show your program output (in the screenshot) and submit the code that youmodified.Exercise 1:====================Hello OctoberKeanHello Computer Science!arrow_forward(OnlineGDB) 1. Please read and run the following code and answer the questions.#include <stdio.h>int main(void) {int a;char *s;int v0 = 4, v1 = 5, v2 = 6, v3 = 1, v4 = 2;printf("Exercise 1:\n====================\n");switch(v0) {case 0: printf("Hello October\n"); break;case 1: printf("Go Kean!\n"); break;case 2: printf("Academic Building Center \n"); break;case 3: printf("UNION \n"); break;case 4: printf("Go ");case 5: printf("Kean! \n");default: printf("Have a great semester! \n"); break;}for(a=5; a<v1; a++) {printf("Kean");}printf("\n");if (v2 == 6) {s = "Go";}else {s = "Hello";}if(v3 != v4) {printf("%s Kean!\n",s);} else {printf("%s Computer Science!\n",s);}return 0;} What is the output of the program? Please explain why.arrow_forward1.[30 pts] Answer the following questions: a. [10 pts] Write a Boolean equation in sum-of-products canonical form for the truth table shown below: A B C Y 0 0 0 1 0 0 1 0 0 1 0 0 0 1 1 0 1 0 0 1 1 0 1 0 1 1 0 1 1 1 1 0 a. [10 pts] Minimize the Boolean equation you obtained in (a). b. [10 pts] Implement, using Logisim, the simplified logic circuit. Include an image of the circuitarrow_forward
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