Chapter A.6, Problem 97AYU

To determine

To solve: The equation by the square root method: ${\left(2x+3\right)}^2=9$.

Answer to Problem 97AYU

$x=0, -3$

Explanation of Solution

${\left(2x+3\right)}^2=9$

$2x+3=\pm \sqrt{9}$

$2x+3=\pm 3$

$2x+3=3$, $2x+3=-3$

$2x+3-3=3-3$, $2x+3-3=-3-3$

$2x=0$, $2x=-6$

$\frac{2x}{2}=\frac{0}{2}$, $\frac{2x}{2}=-\frac{6}{2}$

$x=0$, $x=-3$

The solution set is $\left\{0, -3\right\}$.