Chapter A.6, Problem 96AYU

To determine

To solve: The equation by the square root method: ${\left(x+2\right)}^2=1$.

Answer to Problem 96AYU

$x=-1, -3$

Explanation of Solution

${\left(x+2\right)}^2=1$

$x+2=\pm \sqrt{1}$

$x+2=\pm 1$

$x+2=1$, $x+2=-1$

$x+2-2=1-2$, $x+2-2=-1-2$

$x=-1$, $x=-3$

The solution set is $\left\{-1, -3\right\}$.