Chapter A.6, Problem 40AYU

To determine

To solve: $4z^3-8z^2=0$

Answer to Problem 40AYU

$z=0, 2$

Explanation of Solution

$4z^3-8z^2=0$

$4z^2\left(z-2\right)=0$

$4z^2=0$ and $z-2=0$

$\frac{4z^2}{4}=\frac{0}{4}$   (Divide 4 on both sides) and $z-2+2=0+2$   (Add 2 on both sides)

$z^2=0$ and $z=2$

$z=0$ and $z=2$