Chapter A.6, Problem 87AYU

To determine

To solve: $x^3+x^2-20x=0$

Answer to Problem 87AYU

$x=0,4, -5$

Explanation of Solution

$x^3+x^2-20x=0$

$x\left(x^2+x-20\right)=0$

$x\left(x-4\right)\left(x+5\right)=0$

$x=0, x-4=0, x+5=0$

$x=0, x=4, x=-5$