Chapter A.6, Problem 66AYU

To determine

To solve: $x^2=-8x$

Answer to Problem 66AYU

$x= 0, -8$

Explanation of Solution

$x^2=-8x$

$x^2+8x=-8x+8x$   (Add $8x$ on both sides)

$x^2+8x=0$

$x\left(x+8\right)=0$

$x=0, x+8=0$

$x=0, x=-8$