Chapter A.3, Problem 89AYU

To determine

To find: The factor completely each polynomial. If the polynomial cannot be factored, say it is prime.

Answer to Problem 89AYU

$y^4+11y^3+30y^2=y^2\left(y+6)(y+5\right)$

Explanation of Solution

Given:

$y^4+11y^3+30y^2$

Calculation:

$y^4+11y^3+30y^2=y^2\left(y^2+11y+30\right)=y^2\left(y+6)(y+5\right)$, since the product of 6 and 5 is 30, and the sum of 6 and 5 is 11.