Chapter A.3, Problem 106AYU

To determine

To find: The factor completely each polynomial. If the polynomial cannot be factored, say it is prime.

Answer to Problem 106AYU

$9y^2+9y-4=\left(3y-4\right)\left(3y-1\right)$

Explanation of Solution

Given:

$9y^2+9y-4$

Calculation:

$9y^2+9y-4=9y^2+12y-3y-4$, since the product of 12 and $-3$ is $-36$, and the sum of 12 and $-3$ is 9.

$=3y\left(3y-4\right)-1\left(3y-4\right)=\left(3y-4\right)\left(3y-1\right)$