Chapter A.3, Problem 87AYU

To determine

To find: The factor completely each polynomial. If the polynomial cannot be factored, say it is prime.

Answer to Problem 87AYU

$3x^2-12x-36=3\left(x+2\right)\left(x-6\right)$

Explanation of Solution

Given:

$3x^2-12x-36$

Calculation:

$3x^2-12x-36=3\left(x^2-4x-12\right)=3\left(x+2\right)\left(x-6\right)$, since the product of 2 and $-6$ is $-12$, and the sum of 2 and $-6$ is $-4$.