EBK ORGANIC CHEMISTRY: PRINCIPLES AND M
EBK ORGANIC CHEMISTRY: PRINCIPLES AND M
2nd Edition
ISBN: 9780393543971
Author: KARTY
Publisher: VST
Question
Book Icon
Chapter A, Problem A.24P
Interpretation Introduction

(a)

Interpretation:

The structure from the provided IUPAC name is to be drawn.

Concept introduction:

The last part of the IUPAC name represents, the parent chain which is the longest continuous carbon chain. The names of all substituents appear as prefixes before the root, and they are appear alphabetically according to the substituent’s name. If there is just one of a particular substituent, the locator number appears immediately to the left of the substituent it describes. The prefixes, ‘di, tri... ’ suggests the number of substituents present along the parent chain. The locator numbers of substituents represents the carbon atoms in the parent chain to which the substituents are attached. A parenthesis represents a substituted branched alkane, while the number just before the parenthesis denotes the point of attachment of the substituted branched alkane to the parent chain.

Interpretation Introduction

(b)

Interpretation:

The structure from the given IUPAC name is to be drawn.

Concept introduction:

The last part of the IUPAC name represents the parent chain which is the longest continuous carbon chain. The names of all substituents appear as prefixes before the root, and they appear alphabetically according to the substituent’s name. If there is just one of a particular substituent, the locator number appears immediately to the left of the substituent it describes. The prefixes, ‘di, tri’ suggests the number of substituents present along the parent chain. The locator numbers of substituents represent the carbon atoms in the parent chain to which the substituents are attached. A parenthesis represents a substituted branched alkane, while the number just before the parenthesis denotes the point of attachment of the substituted branched alkane to the parent chain.

Blurred answer
Students have asked these similar questions
Don't used hand raiting
CS2(g) →CS(g) + S(g) The rate law is Rate = k[CS2] where k = 1.6 × 10−6 s−¹. S What is the concentration of CS2 after 5 hours if the initial concentration is 0.25 M?
CS2(g) → CS(g) + S(g) The rate law is Rate = k [CS2] where k = 1.6 × 10-6 s−1. S Calculate the half-life.
Knowledge Booster
Background pattern image
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Chemistry for Today: General, Organic, and Bioche...
Chemistry
ISBN:9781305960060
Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher:Cengage Learning
Text book image
Introductory Chemistry: An Active Learning Approa...
Chemistry
ISBN:9781305079250
Author:Mark S. Cracolice, Ed Peters
Publisher:Cengage Learning
Text book image
Introductory Chemistry For Today
Chemistry
ISBN:9781285644561
Author:Seager
Publisher:Cengage