
Concept explainers
To find: The given equation in the standard form and the vertex, axis of symmetry, and the direction of opening of the parabola.

Answer to Problem 7MCQ
The given equation in the standard form is x=2(y+2)2−5 , the coordinate of the vertex is (−2,−5) , the axis of symmetry is y=−2 , and the direction of opening of the parabola is right.
Explanation of Solution
Given information:
The equation of the parabola is,
x−2y2=4y+6
Concept used:
Write the standard form of the equation of the parabola,
x=a(y−k)2+h
The direction of opening,
right, a>0left, a<0
The coordinate of the vertex is (h,k) , the coordinate of focus is (h+14a,k) , and the length of latus rectum is |1a| .
The equation of directrix is,
x=h−14a
The axis of symmetry is,
y=k
Write the standard form of the equation of the parabola,
x−2y2=4y+6x=2(y2+2y+4)−8+3x=2(y+2)2−5
The direction of opening is,
a=2>0, right
The coordinate of the vertex is (−2,−5) .
The axis of symmetry is,
y=ky=−2
Thus, the given equation in the standard form is x=2(y+2)2−5 , the coordinate of the vertex is (−2,−5) , the axis of symmetry is y=−2 , and the direction of opening of the parabola is right.
Chapter 9 Solutions
Glencoe Algebra 2 Student Edition C2014
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