
To find: The where did the support beams meet to parabola.

Answer to Problem 68SGR
The beam given by equation y=−x+10 meets the entrance at points (0,10) and (30,−10) .
The beam given by equation y=x−10 meets the entrance at points (20,10) and (−10,−20) .
Explanation of Solution
Given information:
Equation of the parabola y=−110(x−10)2+20
The construction team put in two support beams with the equations y=−x+10 and y=x−10 .
Calculation:
The front entrance of a building is parabola in shape with the equation,
y=−110(x−10)2+20 ........(1)
The parabolic entrance is supported by two beams The support beams have the following equations,
y=−x+10 .......(2)
And
y=x−10 ........(3)
The beam given by equation (2) y=−x+10 meets the parabola (1) y=−110(x−10)2+20 at the intersection point of two equations.
Substitute y=−x+10 from equation (2) in equation (1) y=−110(x−10)2+20 and solve for x
−x+10=−110(x−10)2+20−10x+100=−x2+20x−100+200x2−30x=0
x(x−30)=0x=0,30
Substitute x=0 in equation (2) y=−x+10 and solve for y
y=−0+10y=10
Hence, (0,10) is a solution of parabola and line (2) y=−x+10 .
Substitute x = 30 in equation (2) y=−x+10 and solve for y,
y=−30+10y=−20
Hence, (30,−10) is a solution of parabola and line (2) y=−x+10 .
Therefore, beam given by equation (2) y=−x+10 meets the entrance at points (0,10) and (30,−10) .
The beam given by equation (3) y=x−10 meets the parabola (1) y=−110(x−10)2+20 at the intersection point of two equations.
Substitute y=x−10 from equation (3) in equation (1) y=−110(x−10)2+20 and solve for x,
x−10=−110(x−10)2+2010x−100=−x2+20x−100+200x2−10x−200=0
Simplify further
x=20,−10
Substitute x=20 in equation (3) y=x−10 and solve for y
y=20−10y=10
Hence (20,10) is a solution of parabola and line (3) y=x−10 .
Therefore, beam given by equation (3) y=x−10 meets the entrance at points (20,10) and (−10,−20) .
Chapter 9 Solutions
Glencoe Algebra 2 Student Edition C2014
Additional Math Textbook Solutions
Calculus: Early Transcendentals (2nd Edition)
Pre-Algebra Student Edition
Introductory Statistics
University Calculus: Early Transcendentals (4th Edition)
Precalculus
A First Course in Probability (10th Edition)
- 1. For the following subsets of R3, explain whether or not they are a subspace of R³. (a) (b) 1.1 0.65 U = span -3.4 0.23 0.4 -0.44 0 (})} a V {(2) | ER (c) Z= the points in the z-axisarrow_forwardSolve the following equation forx. leave answer in Simplified radical form. 5x²-4x-3=6arrow_forwardMATCHING LIST Question 6 Listen Use the given equations and their discriminants to match them to the type and number of solutions. 00 ed two irrational solutions a. x²+10x-2=-24 two rational solutions b. 8x²+11x-3=7 one rational solution c. 3x²+2x+7=2 two non-real solutions d. x²+12x+45 = 9 DELL FLOWER CHILD 10/20 All Changes S $681 22991arrow_forward
- 88 MULTIPLE CHOICE Question 7 Listen The following irrational expression is given in unsimplified form with four op- tions in simplified form. Select the correct simplified form. Select only one option. A 2±3√√2 B 4±√3 2±√ √3 D 1±√√3 DELL FLOWER CHILD 11/200 4 ± √48 4 ✓ All Changes Saved 165arrow_forwardUse the graph of y = f(x) to answer the following. 3- 2 -4 -2 -1 1 2 3 4 -1 2 m -3- + (d) Find all x for which f(x) = -2. If there is more than one value, separate them with commas or write your answer in interval notation, if necessary. Select "None", if applicable. Value(s) of x for which f(x)=-2: | (0,0) (0,0) (0,0) (0,0) 0,0... -00 None (h) Determine the range of f. The range is (0,0) Garrow_forwardWhat is g(f(4))arrow_forward
- 10) Multiply (8m + 3)² A) 8m²+11m+6 B) m² + 48m+9 C) 64m²+48m+9 D) 16m²+11m+6arrow_forwardLet R be field and X= R³/s Vector space over R M=(a,b,c)labic, e Rra+b= 3- <3 Show that Ms and why with proof. 1) is convexset and affine set of botost ii) is blanced set and symmetirs set of x iii) is hy per space and hyper plane ofx or hot iii) find f:MR st kerf = M 18/103 and finnd fiM→R/{0} st M= {xEX, f(t) = x, texiαER? jiii) show that Mis Maxsubspace or not and Mis a max. affine set or not.arrow_forwardFind The partial fraction decomposition for each The following 2× B) (x+3) a 3 6 X-3x+2x-6arrow_forward
- 1) Find the partial feraction decomposition for each of 5- X 2 2x+x-1 The following: 3 B) 3 X + 3xarrow_forwardT={(−7,1),(1,−1),(6,−8),(2,8)} Find the domain and range of the inverse. Express your answer as a set of numbers.arrow_forwardT={(−7,1),(1,−1),(6,−8),(2,8)}. Find the inverse. Express your answer as a set of ordered pairs.arrow_forward
- Algebra and Trigonometry (6th Edition)AlgebraISBN:9780134463216Author:Robert F. BlitzerPublisher:PEARSONContemporary Abstract AlgebraAlgebraISBN:9781305657960Author:Joseph GallianPublisher:Cengage LearningLinear Algebra: A Modern IntroductionAlgebraISBN:9781285463247Author:David PoolePublisher:Cengage Learning
- Algebra And Trigonometry (11th Edition)AlgebraISBN:9780135163078Author:Michael SullivanPublisher:PEARSONIntroduction to Linear Algebra, Fifth EditionAlgebraISBN:9780980232776Author:Gilbert StrangPublisher:Wellesley-Cambridge PressCollege Algebra (Collegiate Math)AlgebraISBN:9780077836344Author:Julie Miller, Donna GerkenPublisher:McGraw-Hill Education





