Chapter 9.3, Problem 15PPS

To determine

To Find: The equation of the circle.

Answer to Problem 15PPS

  ${(x+2)}^2+{(y+1)}^2=81$

Explanation of Solution

Given: $center:(-2,-1),r=9units$

Given: $center:(-2,-1),r=9units$

The center of the circle is at $(h,k)$ and radius is at $r$

Equation of the circle

  ${(x-h)}^2+{(y-k)}^2=r^2$

Then

  $\begin{array}{}$ {(x-h)}^2+{(y-k)}^2=r^2$$ {(x-(-2))}^2+{(y-(-1))}^2=9^2$$ {(x+2)}^2+{(y+1)}^2=81$\end{array}$

Hence, ${(x+2)}^2+{(y+1)}^2=81$